Combined Gas Law This is made by combining Charles’ and Boyle’s Law.

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Combined Gas Law This is made by combining Charles and Boyles Law. This is made by combining Charles and Boyles Law. V i P i / T i = V f P f / T f V i.
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Presentation transcript:

Combined Gas Law This is made by combining Charles’ and Boyle’s Law. Vi Pi / Ti = Vf Pf / Tf Temperature has to be in Kelvin (so it can never be 0) volume and pressure can be in any unit as long as it is the same on both sides.

A problem If a gas occupies 34 L at 1.2 atm and 290 K, what volume will it occupy at 1.1 atm and 280 K? Vi Pi / Ti = Vf Pf / Tf 34L (1.2atm) / 290 K = V (1.1atm)/280K V = 36 L

A problem If a gas occupies 24 mL at 115 kPa and 13o C, what volume will it occupy at 101 kPa and 0o C? 24 mL (115kPa)/286 K = V (101kPa)/273 K V = 26 mL (don’t forget to convert temp to K)

Standard Temperature and Pressure Normally volumes are reported at standard conditions. It is normally abbreviated STP (standard temperature and pressure) Standard temperature is 273 K or 0o C Standard pressure is 101 kPa, or 760 torr, or 1.00 atm.

Avogadro’s Law Avogadro discovered that the size or type of molecule or atom of a gas had no effect on the volume of that gas. His law states… ~equal volumes of different gases at the same temperature and pressure contain the same number of molecules. 1.00 mol of any gas at STP will occupy 22.4 L

To convert… What volume will .67 mol of a gas occupy at STP? .67mol 22.4 L (at STP) 1 mol = 15.008 15 L at STP What volume will .67 mol of a gas occupy at 740 torr and 295 K?

Add this into combined gas law Vi Pi / Ti = Vf Pf / Tf What volume will .67 mol of a gas occupy at 740 torr and 295 K? 15.008 L (760 torr)/273 K = V (740 torr)/295K V = 17 L

More What volume will .83 mol of a gas occupy at .82 atm and 264 K? .83 mol 22.4 L (at STP) 1 mol = 18.592 L at STP 18.592 L (1.00 atm)/273 K = V (.82 atm)/264 K V = 22 L

Combined Gas Law Problems

Number 1 126 mL of nitrogen at 113 kPa and 39o C will occupy what volume at STP? VP/T = VP/T 126 mL (113 kPa)/312K = V 101 kPa/273K V = 123 mL

Number 2 1.54 mol of helium will occupy what volume at 92 kPa and 315 K? 1.54 mol x 22.4 L/1 mol =34.496 L at STP VP/T = VP/T 34.496…L (101 kPa)/273K = V 92 kPa/315K V = 44 L

Number 3 2.14 g of NH3 ammonia will occupy what volume at 795 torr and 315 K? 2.14 g x 1 mol/17.034 g = .125mol .1256… mol x 22.4 L/1 mol =2.81… L at STP VP/T = VP/T 2.81…L (760 torr)/273K = V 795 torr/315K V = 3.10 L

Number 4 126 mL of nitrogen at 143 kPa and 39o C will occupy 154 mL at 101 kPa and what temperature? VP/T = VP/T 126 mL (143 kPa)/312K = 154 mL 101 kPa/ T T = 269 K or -4o C

Number 5 CH3OH + O2 → H2O + CO2 What volume of carbon dioxide will 5.2 g oxygen produce at 1.2 atm and 299 K? .108.. mol x 22.4 L/1 mol=2.42… L 2.426…L (1.00 atm)/273K = V 1.2 atm/299K V = 2.2 L 2 3 4 2 5.2 g O2 1 mol O2 2 mol CO2 32.00 g O2 3 mol O2

Number 6 HCl + Co → CoCl3 + H2 What volume of hydrogen gas will 5.2 g cobalt produce at 97 kPa and 285 K? .132.. mol x 22.4 L/1 mol=2.42… L 2.966…L (101 kPa)/273K = V 97 KPa/285K V = 3.2 L 6 2 2 3 5.2 g Co 1 mol Co 3 mol H2 58.93 g Co 2 mol Co