Chemical Calculations

Slides:



Advertisements
Similar presentations
12.2: CHEMICAL CALCULATIONS. STANDARD 3.e. Students know how to.
Advertisements

Chapter 12--Stoichiometry
Chemical Calculations Prentice-Hall Chapter 12.2 Dr. Yager.
© Copyright Pearson Prentice Hall Slide 1 of 41 The Arithmetic of Equations More than 3000 cocoons are needed to produce enough silk to make just one elegant.
Chemistry 12.2.
and cooking with chemicals
Chapter 9 Stoichiometry
Chapter 12: Stoichiometry
Sec. 11.2: Stoichiometric Calculations
Stoichiometry The study of quantities of materials consumed and produced in chemical reactions.
Slide 1 of 41 Chemistry © Copyright Pearson Prentice Hall Slide 2 of Chemical Calculations The effectiveness of car’s air bags is based.
Chemical Calculations Stoichiometry u OBJECTIVES: Calculate stoichiometric quantities from balanced chemical equations using units of moles, mass, representative.
Chapter 12: Stoichiometry 12.1 The Arithmetic of Equations.
Stoichiometry is… Greek for “measuring elements” Defined as: calculations of the quantities in chemical reactions, based on a balanced equation. There.
01 StoichiometryChapter 12. What conversion factors would you need if you were going to move from grams to liters? Solve the following problems. –How.
Can’t directly measure moles Measure units related to moles: –Mass (molar mass) –Number of particles (6.02 x ) –Liters of gas (22.4 Liters at STP)
 Stoichiometry Chemistry S.Fleck Objectives  9.1 – The Arithmetic of Equations  Interpret balanced chemical equations in terms of interacting.
Stoichiometry. Review: Dimensional Analysis Goal: To make the units cancel out Strategy: Start out with the quantity given that you are trying to convert.
Ch. 9.1 & 9.2 Chemical Calculations. POINT > Define the mole ratio POINT > Use the mole ratio as a conversion factor POINT > Solve for unknown quantities.
12.2 Chemical Calculations > 12.2 Chemical Calculations > 1 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. Chapter 12 Stoichiometry.
The Mathematics of Chemical Equations
7.7 Volume and Moles (Avogadro’s Law)
Stoichiometry II.
Chapter 12 Stoichiometry 12.1 The Arithmetic of Equations
Chapter 9 Chemical Quantities in Reactions
Stoichiometry “In solving a problem of this sort, the grand thing is to be able to reason backward. This is a very useful accomplishment, and a very easy.
Chapter 9A Notes Stoichiometry
Stoichiometry: Chapter 9.
Interconversions and Stoichiometry
Law of Conservation of Matter
Chapter 12 Stoichiometry.
Calculations with Equations
Calculations with Equations
Chapter 12 Stoichiometry
Chemical Reactions Unit
Chapter 9 Stoichiometry
Gas Stoichiometry At STP
12.2 Chemical Calculations
Chapter 9 Stoichiometry
Stoichiometric Calculations
Stoichiometry – Mr. Mole.
Chapter 11 “Stoichiometry”
Stoichiometry Unit 4 (Ch 9).
Stoichiometry Unit 8 Lesson 1.
Gas Stoichiometry.
Volume and Moles (Avogadro’s Law)
Stoichiometry Unit 8 Lesson 1.
Chapter 6 Chemical Reactions and Quantities
Chemical Calculations
Created by C. Ippolito June 2007
Chapter 12 Stoichiometry 12.2 Chemical Calculations
Chapter 12 Stoichiometry 12.2 Chemical Calculations
Chemistry 12.2.
Chapter 12 Stoichiometry 12.2 Chemical Calculations
Chemistry 12.2.
Section 2 - Chemical Calculations
DRILL Besides mass what is conserved during a chemical reaction?
Chapter 9 Stoichiometry
and cooking with chemicals
Stoichiometry How does stoichiometry relate to a correctly balanced chemical equation?
Chapter 9 Chemical Quantities in Reactions
Section 2 - Chemical Calculations
Chapter 12 Stoichiometry 12.2 Chemical Calculations
Chapter 12 Stoichiometry
Stoichiometric Calculations
Stoichiometry Unit 8 Lesson 1.
Stoichiometry Unit 7 Lesson 1.
Calculation of Chemical Quantities
Chapter 9 “Stoichiometry”
Chapter 5 Chemical Quantities and Reactions
Presentation transcript:

Chemical Calculations Prentice-Hall Chapter 12.2 Dr. Yager

Objectives Construct mole ratios from balanced chemical equations and apply these ratios in stoichiometric calculations. Calculate stoichiometric quantities from balanced chemical equations using units of moles, mass, representative particles and volume of gases at STP.

A mole ratio is a conversion factor derived from the coefficients of a balanced chemical equation and interpreted in terms of moles. In chemical calculations, mole ratios are used to convert between moles of reactant and moles of product, between moles of reactants, or between moles of products.

Mole Ratios N2(g) + 3H2(g) 2NH3(g) 1 mole of nitrogen reacts with 3 moles of hydrogen Mole ratios are used to convert between any two compounds:

Mole-Mole Calculation If you have 0.60 mol of N2, how much NH3 is produced? The ratios are:

Write the six mole ratios for: 4Al(s) + 3O2(g) 2Al2O3(s)

Write the six mole ratios for: 4Al(s) + 3O2(g) 2Al2O3(s)

How many moles of aluminum are needed to form 3.7 mol of Al2O3?

How many moles of aluminum are needed to form 3.7 mol of Al2O3?

Mass-Mass Calculation

Calculate the number of grams formed by reacting 5 Calculate the number of grams formed by reacting 5.4 grams of H2 with excess N2. N2(g) + 3H2(g) 2NH3(g)

N2(g) + 3H2(g) 2NH3(g) Calculate the number of grams formed by reacting 5.4 grams of H2 with excess N2.

Other Stoichiometric Calculations It all comes down to moles. If you want atoms, particles, etc. then multiply moles by 6.02x1023 If you want gas volume at STP then multiply moles by 22.4 liters. If you have volume divide by 22.4 L/mol to get moles Always use dimensional analysis to check units!

12.2 Solution Diagram

Problem-Solving Approach 12.2 Problem-Solving Approach

1. How many moles of water are produced when 2 1. How many moles of water are produced when 2.5 mol of O2 react according to the following equation? C3H8 + 5O2  3CO2 + 4H2O 2.0 2.5 3.0 4.0

1. How many moles of water are produced when 2 1. How many moles of water are produced when 2.5 mol of O2 react according to the following equation? C3H8 + 5O2  3CO2 + 4H2O 2.0 2.5 3.0 4.0

2. Nitrogen gas reacts with hydrogen gas to produce ammonia gas. N2(g) + 3H2(g)  2NH3(g) What volume of H2 is required to react with 3.00 L of N2, and what volume of NH3 is produced at 0°C? volume of H2 = 9.00 L, volume of NH3 = 6.00 L volume of H2 = 3.00 L, volume of NH3 = 3.00 L volume of H2 = 3.00 L, volume of NH3 = 6.00 L volume of H2 = 1.00 L, volume of NH3 = 1.50 L

2. Nitrogen gas reacts with hydrogen gas to produce ammonia gas. N2(g) + 3H2(g)  2NH3(g) What volume of H2 is required to react with 3.00 L of N2, and what volume of NH3 is produced at 0°C? volume of H2 = 9.00 L, volume of NH3 = 6.00 L volume of H2 = 3.00 L, volume of NH3 = 3.00 L volume of H2 = 3.00 L, volume of NH3 = 6.00 L volume of H2 = 1.00 L, volume of NH3 = 1.50 L

3. Automotive airbags inflate when sodium azide, NaN3, rapidly decomposes to its component elements via this reaction: 2NaN3  2Na + 3N2. How many grams of sodium azide are required to form 5.00 g of nitrogen gas? 11.61 g 17.41 g 7.74 g 1.36 g

3. Automotive airbags inflate when sodium azide, NaN3, rapidly decomposes to its component elements via this reaction: 2NaN3  2Na + 3N2. How many grams of sodium azide are required to form 5.00 g of nitrogen gas? 11.61 g 17.41 g 7.74 g 1.36 g