C. less, but not zero. D. zero.

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C. less, but not zero. D. zero. A spherical Gaussian surface (#1) encloses and is centered on a point charge +q. A second spherical Gaussian surface (#2) of the same size also encloses the charge but is not centered on it. Compared to the electric flux through surface #1, the flux through surface #2 is +q Gaussian surface #1 Gaussian surface #2 Answer: B A. greater. B. the same. C. less, but not zero. D. zero. E. not enough information given to decide

A. surface A B. surface B C. surface C D. surface D Two point charges, +q (in red) and –q (in blue), are arranged as shown. Through which closed surface(s) is the net electric flux equal to zero? A. surface A B. surface B C. surface C D. surface D E. Both surfaces C and D Answer: D

A. the electric field points radially outward. A conducting spherical shell with inner radius a and outer radius b has a positive point charge Q located at its center. The total charge on the shell is –3Q, and it is insulated from its surroundings. In the region r > b, A. the electric field points radially outward. B. the electric field points radially inward. C. is zero. D. not enough information given to decide Answer: C

Just outside the surface of this conductor, the electric field There is a negative surface charge density on the surface of a solid conductor. Just outside the surface of this conductor, the electric field A. points outward, away from the surface of the conductor. B. points inward, toward the surface of the conductor. C. points parallel to the surface. D. is zero. E. not enough information given to decide Answer: D

A. a uniformly charged sphere of radius R Q22.6 For which of the following charge distributions would Gauss’s law not be useful for calculating the electric field? A. a uniformly charged sphere of radius R B. a spherical shell of radius R with charge uniformly distributed over its surface C. a right circular cylinder of radius R and height h with charge uniformly distributed over its surface D. an infinitely long circular cylinder of radius R with charge uniformly distributed over its surface E. Gauss’s law would be useful for finding the electric field in all of these cases. Answer: C

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