5.2 Functions of Angles and Fundamental Identities To define the six trigonometric functions, start with an angle  in standard position. Choose any point P having coordinates (x,y) on the terminal side as seen in the figure below. Notice that r > 0 since distance is never negative.

5.2 The Six Trigonometric Functions The six trigonometric functions are sine, cosine, tangent, cotangent, secant, and cosecant. Trigonometric Functions Let (x,y) be a point other than the origin on the terminal side of an angle  in standard position. The distance from the point to the origin is The six trigonometric functions of angle  are as follows.

5.2 Finding Function Values of an Angle Example The terminal side of angle  (beta) in standard position goes through (–3,–4). Find the values of the six trigonometric functions of . Solution

5.2 Quadrantal Angles The six trigonometric functions can be found from any point on the line. Due to similar triangles, so sin = y/r is the same no matter which point is used to find it.

5.2 Reciprocal Identities Since sin = y/r and csc = r/y, Similarly, we have the following reciprocal identities for any angle  that does not lead to a 0 denominator.

5.2 Using the Reciprocal Identities Example Find sin if csc = Solution

5.2 Signs and Ranges of Function Values In the definitions of the trigonometric functions, the distance r is never negative, so r > 0. Choose a point (x,y) in quadrant I, then both x and y will be positive, so the values of the six trigonometric functions will be positive in quadrant I. A point (x,y) in quadrant II has x < 0 and y > 0. This makes sine and cosecant positive for quadrant II angles, while the other four functions take on negative values. Similar results can be obtained for the other quadrants.

5.2 Signs and Ranges of Function Values Example Identify the quadrant (or quadrants) of any angle  that satisfies sin > 0, tan < 0. Solution Since sin > 0 in quadrants I and II, while tan < 0 in quadrants II and IV, both conditions are met only in quadrant II.

5.2 Signs and Ranges of Function Values The figure shows angle  as it increases from 0º to 90º. The value y increases as  increases, but never exceeds r, so y  r. Dividing both sides by r gives In a similar way, angles in quadrant IV suggests

5.2 Signs and Ranges of Function Values Since for any angle . In a similar way, sec and csc are reciprocals of sin and cos, respectively, making

5.2 Ranges of Trigonometric Functions Example Decide whether each statement is possible or impossible. (b) tan = 110.47 (c) sec = .6 Solution Not possible since Possible since tangent can take on any value. Not possible since sec  –1 or sec  1. For any angle  for which for which the indicated function exists: –1  sin  1 and –1  cos  1; tan and cot may be equal to any real number; sec  –1 or sec  1 and csc  –1 or csc  1.

5.2 Pythagorean Identities Three new identities from x2 + y2 = r2 Divide by r2 Since cos = x/r and sin = y/r, this result becomes Divide by x2 Dividing by y2 leads to cot2 + 1 = csc2.

5.2 Pythagorean Identities Example Find sin and cos, if tan = 4/3 and  is in quadrant III. Solution Since  is in quadrant III, sin and cos will both be negative. Pythagorean Identities

5.2 Quotient Identities Recall that Consider the quotient of sin and cos where cos  0. Similarly Quotient Identities