Stoichiometry.

Slides:



Advertisements
Similar presentations
Stoichiometry Chemistry I: Chapter 12 Chemistry I HD: Chapter 9 SAVE PAPER AND INK!!! When you print out the notes on PowerPoint, print "Handouts" instead.
Advertisements

Stoichiometry The Mole: Review A counting unit A counting unit Similar to a dozen, except instead of 12, its 602,000,000,000,000,000,000,000 Similar.
Stoichiometry Chapter 10 The Mole A counting unit A counting unit Similar to a dozen, except instead of 12, its 602,000,000,000,000,000,000,000 Similar.
Stoichiometry.
Stoichiometry Chapter 12 Notes.
Stoichiometry.
“Stoichiometry” Mr. Mole.
Stoichiometry.
“Stoichiometry” Mr. Mole u First… –A bit of review.
Stoichiometry SAVE PAPER AND INK!!! When you print out the notes on PowerPoint, print "Handouts" instead of "Slides" in the print setup. Also, turn off.
Stoichiometry SAVE PAPER AND INK!!! When you print out the notes on PowerPoint, print "Handouts" instead of "Slides" in the print setup. Also, turn off.
Unit 12 Chemistry Langley
Chocolate Chip Cookies!!
Stoichiometry Chocolate Chip Cookies!! 1 cup butter 1/2 cup white sugar 1 cup packed brown sugar 1 teaspoon vanilla extract 2 eggs 2 1/2 cups all-purpose.
Stoichiometry The Mole: Review A counting unit A counting unit Similar to a dozen, except instead of 12, it’s 602,000,000,000,000,000,000,000 Similar.
It’s time to learn about.... What's The Difference Between Roast Beef And Pea Soup? Anyone Can Roast Beef.
 The Mole Chemists have adopted the mole concept as a convenient way to deal with the enormous numbers of atoms, molecules or ions in the samples they.
Stoichiometry The Mole: Review A counting unit Similar to a dozen, except instead of 12, it’s 602,000,000,000,000,000,000, X (in scientific.
Stoichiometry.
Stoichiometry Chemistry I: Chapter 12 Chemistry IH: Chapter 12.
Chapter 12 Stoichiometry Mr. Mole. Molar Mass of Compounds Molar mass (MM) of a compound - determined by up the atomic masses of – Ex. Molar mass of CaCl.
Stoichiometry “The Mathematics of Chemical Reactions” By: Ms. Buroker.
Stoichiometry I                                                               Mole-Mole.
Stoichiometry Chemistry IH: Chapter 9 Stoichiometry The method of measuring amounts of substances and relating them to each other.
Stoichiometry Baking Chocolate Chip Cookies!! 1 cup butter 1/2 cup white sugar 1 cup packed brown sugar 1 teaspoon vanilla extract 2 eggs 2 1/2 cups.
Stoichiometry A branch of chemistry that deals with the quantitative relationship that exist between the reactants and products of in chemical reactions.
Stoichiometry Chemistry I: Chapter 12 Chemistry IH: Chapter 12.
C.7 (notes) – C.8 (practice) In which you will learn about… In which you will learn about… Mole ratios Mole ratios stoichiometry stoichiometry.
Chocolate Chip Cookies!!
Bell Work “We’re Cookin’ Now” Chocolate Chip Cookies!! 1 cup butter 1/2 cup white sugar 1 cup packed brown sugar 1 teaspoon vanilla extract 2 eggs 2.
Stoichiometry Chemistry 11 Chapter 2 Pg The Mole A counting unit Similar to a dozen, except instead of 12, it’s 602,000,000,000,000,000,000,000.
Stoichiometry Chemistry I: Chapter 9 Molar Mass of Compounds The molar mass (MM) of a compound is determined the same way, except now you add up all.
It’s time to learn about.... Stoichiometry Stoichiometry : Mole Ratios to Determining Grams of Product At the conclusion of our time together, you should.
Chp 9: Stoichiometry Chocolate Chip Cookies!! 1 cup butter 1/2 cup white sugar 1 cup packed brown sugar 1 teaspoon vanilla extract 2 eggs 2 1/2 cups.
Stoichiometry Topic – Chocolate Chip Cookies!! 1 cup butter 1/2 cup white sugar 1 cup packed brown sugar 1 teaspoon vanilla extract 2 eggs.
It’s time to learn about . . .
Stoichiometry Chapter 12
Stoichiometry The Mole: Review A counting unit A counting unit Similar to a dozen, except instead of 12, it’s 602,000,000,000,000,000,000,000 Similar.
Stoichiometry The Mole A counting unit A counting unit Similar to a dozen, except instead of 12, it’s 602,000,000,000,000,000,000,000 Similar to a dozen,
It’s time to learn about.... Stoichiometry Stoichiometry : Mole Ratios to Determining Grams of Product At the conclusion of our time together, you should.
Stoichiometry. Chocolate Chip Cookies!! 1 cup butter 1/2 cup white sugar 1 cup packed brown sugar 1 teaspoon vanilla extract 2 eggs 2 1/2 cups all-purpose.
Stoichiometry Chemistry I/IH: Chapter 11 1 Stoichiometry The method of measuring amounts of substances and relating them to each other. 2.
Stoichiometry Chapter 12. Chocolate Chip Cookies!! 1 cup butter ;1/2 cup white sugar 1 cup packed brown sugar 1 teaspoon vanilla extract 2 eggs ; 2 1/2.
Stoichiometry molar mass Avogadro’s number Grams Moles Particles molar mass Avogadro’s number Grams Moles Particles Everything must go through Moles!!!
Stoichiometry Chapter 12
Chapter 12 Stoichiometry 12.1 The Arithmetic of Equations
Stoichiometry Adapted from
Stoichiometry.
Stoichiometry II.
Stoichiometry.
Stoichiometry (Ch 12) Stoichiometry is the calculation of amounts of substances involved in a chemical reaction. Coefficients in chemical reactions show.
Stoichiometry.
Warm-up How many grams are in 3.45 X 104 formula units of iron (II) oxide?
Stoichiometry Chemistry I: Chapter 11
Stoichiometry.
Stoichiometry.
Chemical Stoichiometry
Stoichiometry.
Stoichiometry.
STOICHIOMETRY BASICS Chemistry.
Stoichiometry (Ch 12) Stoichiometry is the calculation of amounts of substances involved in a chemical reaction. Coefficients in chemical reactions show.
Stoichiometry Chemistry I: Chapter 11
Stoichiometry.
Stoichiometry.
Bellringer I have 2 eggs. How many cookies can I make?
Stoichiometry.
Stoichiometry.
Stoichiometry.
Stoichiometry.
Stoichiometry Chemistry I: Chapter 12 Chemistry I HD: Chapter 9
Presentation transcript:

Stoichiometry

Review of Molar Mass The molar mass (MM) of a compound is all the atomic masses for the molecule (or compound) added up. Ex. Molar mass of CaCl2 Avg. Atomic mass of Calcium = 40.08g Avg. Atomic mass of Chlorine = 35.45g Molar Mass of calcium chloride = 40.08 g/mol Ca + (2 X 35.45) g/mol Cl  110.98 g/mol CaCl2 20 Ca  40.08 17 Cl 35.45

Practice Ca3(PO4)2 Calculate the Molar Mass of calcium phosphate Formula = Masses elements: Ca = 40, P = 31, O = 16, Molar Mass = 3x40 + 2x31 + 8x16 = 310 g/mol Ca3(PO4)2

Everything must go through Moles!!! Calculations molar mass Avogadro’s number Grams Moles particles Everything must go through Moles!!!

Chocolate Chip Cookies!! 1 cup butter 1/2 cup white sugar 1 cup packed brown sugar 1 teaspoon vanilla extract 2 eggs 2 1/2 cups all-purpose flour 1 teaspoon baking soda 1 teaspoon salt 2 cups semisweet chocolate chips Makes 3 dozen 2 eggs 1 cup butter What is the ratio of eggs to butter to make 3 dozen cookies? What is the ratio of butter to chocolate chips? How many eggs would we need to make 9 dozen cookies? How much brown sugar would I need if I had 1 ½ cups white sugar? 1 to 2

Cookies and Chemistry…Huh!?!? Just like chocolate chip cookies have recipes, chemists have recipes as well Instead of calling them recipes, we call them chemical equations Furthermore, instead of using cups and teaspoons, we use moles Lastly, instead of eggs, butter, sugar, etc. we use chemical compounds as ingredients

4 moles of Na and 2 moles of Cl2 Chemistry Recipes Be sure you have a balanced reaction before you start! Example: 2 Na + Cl2  2 NaCl This reaction tells us that by mixing 2 moles of sodium with 1 mole of chlorine we will get 2 moles of sodium chloride How much Na and Cl2 would be need if we wanted to make 4 moles of NaCl? 4 moles of Na and 2 moles of Cl2

Practice 50 mol H2 = 50 mol H2O (they have a 1:1 ratio) Write the balanced reaction for hydrogen gas reacting with oxygen gas. 2 H2 + O2  2 H2O What if we had 50 moles of hydrogen, how much oxygen would react with it? How much water would be produced? 50 mol H2 x 1 mol O2 = 25 mol O2 2 mol H2 Mole ratio 50 mol H2 = 50 mol H2O (they have a 1:1 ratio)

Mole Ratios 5 moles Na 1 mol Cl2 2 mol Na = 2.5 moles Cl2 The mole ratio is used to switch between substances in a chemical equation. Example: How many moles of chlorine are needed to react with 5 moles of sodium? 2 Na + Cl2  2 NaCl 5 moles Na 1 mol Cl2 2 mol Na = 2.5 moles Cl2

Mole-Mole Conversions How many moles of sodium chloride will be produced if 2.6 moles of chlorine gas reacts with excess sodium metal? 2 Na + Cl2  2 NaCl 2.6 moles Cl2 x 2 mol NaCl = 5.20 mol of NaCl 1 mol Cl2

Mole-Mass Conversions Most of the time in chemistry, the amounts are given in grams instead of moles Example: How many grams of chlorine are required to react completely with 5.00 moles of sodium to produce sodium chloride? 2 Na + Cl2  2 NaCl Molar mass Mole ratio 5.00 moles Na 1 mol Cl2 70.90g Cl2 2 mol Na 1 mol Cl2 = 177g Cl2

Practice Given Quantity  convert to moles  mole ratio  convert to final units Calculate the mass in grams of Iodine required to react completely with 0.50 moles of aluminum. 2 Al + 3 I2  2 AlI3 0.50 moles Al X 3 moles I2 2 moles Al X 253.8 g I2 moles =190.35 g I2

Mass-Mole 10.0 g H2O 1 mol H2O 2 mol C2H6 18.0 g H2O 6 mol H20 We can also start with mass and convert to moles of product or another reactant Calculate the number of moles of ethane (C2H6) needed to produce 10.0 g of water 2 C2H6 + 7 O2  4 CO2 + 6 H20 Convert to moles Given quantity Multiply by the Mole ratio 10.0 g H2O 1 mol H2O 2 mol C2H6 18.0 g H2O 6 mol H20 = 0.185 mol C2H6

Consider : 4NH3 + 5O2  6H2O + 4NO How many grams of H2O are produced if 1.9 mol of NH3 are combined with excess oxygen? How many grams of O2 are required to produce 0.3 mol of H2O? # g H2O= 6 mol H2O 4 mol NH3 x 18.02 g H2O 1 mol H2O x 51.4 g H2O = 1.9 mol NH3 # g O2= 5 mol O2 6 mol H2O x 32 g O2 1 mol O2 x 8 g O2 = 0.3 mol H2O

Mass-Mass Conversions Most often we are given a starting mass and want to find out the mass of a product we will get (called theoretical yield) or how much of another reactant we need to completely react with it (no leftover ingredients!) Given Quantity  convert to moles  mole ratio  convert to final units

Mass-Mass Conversion 2.00g N2 1 mol N2 2 mol NH3 17.06g NH3 Ex. How many grams of ammonia are produced when 2.00g of nitrogen react with excess hydrogen. N2 + 3 H2  2 NH3 2.00g N2 1 mol N2 2 mol NH3 17.06g NH3 28.02g N2 1 mol N2 1 mol NH3 = 2.4 g NH3

Practice: Grams to Grams How many grams of calcium nitride are produced when 2.00 g of calcium reacts with an excess of nitrogen? 3 Ca + N2  Ca3N2 2.00 g Ca x 1 mole Ca x 1 mole Ca3N2 x 148 g Ca3N2 = 2.47 g Ca3N2 40 g 3 mol Ca 1 mole Given amount  change to moles  multiply by the mole ratio  change to (put the one on top that you grams are solving for)

Gases and Stoiochiometry Avogadro's Hypothesis - at the same temperature and pressure equal volumes of gas have the same number of particles. At STP 1 mole of any gas has a volume of 22.4 L STP = 0ºC and 1 atmosphere pressure

Gases and Stoichiometry 2 H2O2 (l) ---> 2 H2O (g) + O2 (g) Decompose 1.1 g of H2O2 in a flask with a volume of 2.50 L. What is the volume of O2 at STP? Bombardier beetle uses decomposition of hydrogen peroxide to defend itself.

Gases and Stoichiometry 2 H2O2 (l) ---> 2 H2O (g) + O2 (g) Decompose 1.1 g of H2O2 in a flask with a volume of 2.50 L. What is the volume of O2 at STP? Solution 1.1 g H2O2 1 mol H2O2 1 mol O2 22.4 L O2 34 g H2O2 2 mol H2O2 1 mol O2 = 0.36 L O2 at STP Molar volume

Gas Stoichiometry: Practice! A. What is the volume at STP of 4.00 g of CH4? 4.00 g CH4 x 1 mole x 22.4 L = 5.6 L of CH4 16 g 1 mole B. How many grams of CO2 are produced from the combustion of 20 grams CH4 at STP? CH4 + 2 O2  CO2 + 2 H2O 20 g CH4 x 1 mole x 1 mole CO2 x 22.4 L = 28 L CO2 16 g 1 mole CH4 1 mole