CSE322 CONSTRUCTION OF FINITE AUTOMATA EQUIVALENT TO REGULAR EXPRESSION Lecture #9.

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Presentation transcript:

CSE322 CONSTRUCTION OF FINITE AUTOMATA EQUIVALENT TO REGULAR EXPRESSION Lecture #9

STEPS

PROBLEM

SOLUTION

SOLUTION

SOLUTION

CSE322 EQUIVALENCE OF TWO FINITE AUTOMATA AND REGULAR EXPRESSION Lecture #9

EQUIVALENCE OF TWO FINITE AUTOMATA Two finite automata are over∑ are equivalent if they accept the same set of string over input ∑. When two finite automata are not equivalent ,there is some string w over ∑ satisfying the following: one automaton reaches a final state on application of w, whereas other automaton reaches a non final state.

CASES

PROBLEM

SOLUTION

EQUIVALENCE OF TWO REGULAR EXPRESSION The regular expressions P and Q are equivalent iff they represent the same set. Also, P and Q are equivalent iff the corresponding finite automata are equivalent.

PROBLEM PROVE (a+b)*=a*(ba*)*

SOLUTION

Closure properties of Regular set Set Union Concatenation Closure(iteration) Transpose Set intersection Complementation