MATH 1310 Section 2.5.

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Presentation transcript:

MATH 1310 Section 2.5

Other Techniques for Solving Equations Solving by Factoring: Factoring can be used to solve many types of equations. Always begin by Factoring Completely. Then, set each factor equal to zero.

Find all the solutions of x3 = x

Find all solutions to x3 + 3x2 + 2x + 6 = 0

Equations Involving Fractions: Option 1: Rewrite all fractions so that they have the same denominator, then drop all denominators from the equation. or Option 2: Multiply the entire equation by the LCD to clear the fractions. Then: Solve normally. Be advised: If your answer makes any of the original fractions undefined, it must be rejected!!

4 𝑥−1 + 3 𝑥 =3

Equations involving radicals: If an equation involves a square root (also called a radical), you must isolate the radical, square both sides, and solve the remaining equation. Be certain to check your answers!

Find all solutions to 𝑥+8 −2=𝑥

Extraneous Solutions: In a radical solution, you may “create” additional answers that are not correct. These must be rejected!

Find all solutions to 3𝑥+1 −1=𝑥

Popper # 2 Solve the following: x3 = 9x a. 0, 3 b. 0, 9, -9 c. 0,-3, 3 d. -3, 3 2. Solve the following: 𝑥+ 𝑥+1 =5 a. 8, 3 b. 3 c. 8 d. No Answer 3. Solve the following: 8 𝑥+1 + 3 𝑥 =3 a. 3 b. -1/3 c. -1 d. 3, -1/3

Solving by Substitution: When a function looks, “almost” quadratic, you may want to solve it by relating it to another function. x10 – x5 – 6 = 0 If the exponents go “full amount  half amount  nothing” then you can rewrite as a quadratic. Let u = x5, then x10 – x5 – 6 = 0  u2 – u – 6 = 0

x1/2 + 2x1/4 – 15 = 0

2 𝑥+5 − 𝑥+5 −10=0

Popper 3: 1 𝑥 2 + 5 𝑥 +6=0 What substitution should be made? a. u = x b. u = 5/x c. u = 1/x d. u = 5/x2 2. How does the equation re-write? a. u2 + 5u + 6 = 0 b. 0.2u2 + u + 6 = 0 c. u2 + 5u = 0 d. 5u2 + 6 = 0 3. What is the value(s) of u? a. {-1, 6} b. {2, 3} c. {-3, -2} d. {0, 5} 4. What is the value(s) of x? a. {2, 3, 5} b. {2, 3} c. {-3, -2} d. {-1/2, -1/3}

𝑥+4 𝑥 −5=0

𝑥+4 𝑥 −5=0