Quantum Two.

Slides:



Advertisements
Similar presentations
Mathematical Formulation of the Superposition Principle
Advertisements

Xkcd Xkcd.com. Section 3 Recap ► Angular momentum commutators:  [J x, J y ] = iħJ z etc ► Total ang. Mom. Operator: J 2 = J x 2 + J y 2 +J z 2 ► Ladder.
5.1 Real Vector Spaces.
Chapter 4 Euclidean Vector Spaces
Ch 7.7: Fundamental Matrices
Quantum One: Lecture 5a. Normalization Conditions for Free Particle Eigenstates.
Quantum One: Lecture 17.
Quantum One: Lecture 4. Schrödinger's Wave Mechanics for a Free Quantum Particle.
Quantum One: Lecture Postulate II 3 Observables of Quantum Mechanical Systems 4.
Quantum One: Lecture Canonical Commutation Relations 3.
MOHAMMAD IMRAN DEPARTMENT OF APPLIED SCIENCES JAHANGIRABAD EDUCATIONAL GROUP OF INSTITUTES.
3. Hilbert Space and Vector Spaces
Quantum One: Lecture Representation Independent Properties of Linear Operators 3.
Elementary Linear Algebra Anton & Rorres, 9 th Edition Lecture Set – 02 Chapter 2: Determinants.
PHYS 773: Quantum Mechanics February 6th, 2012
Quantum Two 1. 2 Angular Momentum and Rotations 3.
Angular Momentum Classical radius vector from origin linear momentum determinant form of cross product Copyright – Michael D. Fayer, 2007.
Quantum Two 1. 2 Angular Momentum and Rotations 3.
Quantum Two 1. 2 Angular Momentum and Rotations 3.
Quantum Two 1. 2 Angular Momentum and Rotations 3.
Matrices and Determinants
A function is a rule f that associates with each element in a set A one and only one element in a set B. If f associates the element b with the element.
MODULE 5 HERMITICITY, ORTHOGONALITY, AND THE SPECIFICATION OF STATES we have stated that we need Hermitian operators because their eigenvalues are real.
Quantum Two 1. 2 Angular Momentum and Rotations 3.
Chapter 1 Logic and Proof.
Systems of Identical Particles
Mathematical Formulation of the Superposition Principle
Chapter 2 Sets and Functions.
Q. M. Particle Superposition of Momentum Eigenstates Partially localized Wave Packet Photon – Electron Photon wave packet description of light same.
Average Rate of Change of a Function
5 Systems of Linear Equations and Matrices
Ch 10.1: Two-Point Boundary Value Problems
Chapter 6 Angular Momentum.
Boyce/DiPrima 10th ed, Ch 7.7: Fundamental Matrices Elementary Differential Equations and Boundary Value Problems, 10th edition, by William E. Boyce and.
To any sequence we can assign a sequence with terms defined as
Learning Outcomes After completing this ppt the student will be able to: Make and interpret a basic Routh table to determine the stability of a system.
Angular Momentum Classical radius vector from origin linear momentum
Systems of First Order Linear Equations
Quantum Two.
Lecture 03: Linear Algebra
Quantum One.
Quantum One.
Quantum One.
Quantum One.
Quantum Two.
4. The Postulates of Quantum Mechanics 4A. Revisiting Representations
Quantum One.
Quantum One.
Quantum One.
Quantum Two.
Quantum Two.
Quantum One.
Quantum One.
Orbital Angular Momentum
Quantum One.
Quantum One.
Quantum Two.
Quantum Two.
Quantum Two.
The Stale of a System Is Completely Specified by lts Wave Function
Quantum Two.
Maths for Signals and Systems Linear Algebra in Engineering Lectures 13 – 14, Tuesday 8th November 2016 DR TANIA STATHAKI READER (ASSOCIATE PROFFESOR)
AS-Level Maths: Core 2 for Edexcel
Eigenvalues and Eigenvectors
Vector Spaces RANK © 2012 Pearson Education, Inc..
Linear Vector Space and Matrix Mechanics
Matrix Algebra THE INVERSE OF A MATRIX © 2012 Pearson Education, Inc.
Quantum One.
Presentation transcript:

Quantum Two

Angular Momentum and Rotations

Angular Momentum and Rotations Eigenstates and Eigenvalues of Angular Momentum Operators

Having explored the relationship between rotations and angular momenta, we now undertake a systematic study of the eigenstates and eigenvalues of a vector operator J obeying angular momentum commutation relations of the type that we have derived. As we will see, the process for obtaining this information is very similar to that used to determine the spectrum of the eigenstates of the harmonic oscillator. We consider, therefore, an arbitrary angular momentum operator J whose components satisfy the relations We then note, as we did for the orbital angular momentum ℓ that, since the components do not commute with one another, cannot possess an ONB of eigenstates, i.e., states which are simultaneous eigenstates of all three of its operator components.

Having explored the relationship between rotations and angular momenta, we now undertake a systematic study of the eigenstates and eigenvalues of a vector operator J obeying angular momentum commutation relations of the type that we have derived. As we will see, the process for obtaining this information is very similar to that used to determine the spectrum of the eigenstates of the harmonic oscillator. We consider, therefore, an arbitrary angular momentum operator J whose components satisfy the relations We then note, as we did for the orbital angular momentum ℓ that, since the components do not commute with one another, cannot possess an ONB of eigenstates, i.e., states which are simultaneous eigenstates of all three of its operator components.

Having explored the relationship between rotations and angular momenta, we now undertake a systematic study of the eigenstates and eigenvalues of a vector operator J obeying angular momentum commutation relations of the type that we have derived. As we will see, the process for obtaining this information is very similar to that used to determine the spectrum of the eigenstates of the harmonic oscillator. We consider, therefore, an arbitrary angular momentum operator J whose components satisfy the relations We then note, as we did for the orbital angular momentum ℓ that, since the components do not commute with one another, cannot possess an ONB of eigenstates, i.e., states which are simultaneous eigenstates of all three of its operator components.

Having explored the relationship between rotations and angular momenta, we now undertake a systematic study of the eigenstates and eigenvalues of a vector operator J obeying angular momentum commutation relations of the type that we have derived. As we will see, the process for obtaining this information is very similar to that used to determine the spectrum of the eigenstates of the harmonic oscillator. We consider, therefore, an arbitrary angular momentum operator J whose components satisfy the relations We then note, as we did for the orbital angular momentum ℓ that, since the components do not commute with one another, cannot possess an ONB of eigenstates, i.e., states which are simultaneous eigenstates of all three of its operator components.

In fact, one can show that the only possible eigenstates of J are those for which the angular momentum is identically zero (an 𝑠-state, in the language of spectroscopy). Nonetheless, since, each component of commutes with , it is possible to find an ONB of eigenstates common to and to the component of J along any single chosen direction. Usually the component of J along the 𝑧-axis is chosen, because of the simple form taken by the differential operator representing that component of orbital angular momentum in spherical coordinates. Note, however, that due to the cyclical nature of the commutation relations, anything deduced about the spectrum and eigenstates of and must also apply to the eigenstates common to and to any other component of .

In fact, one can show that the only possible eigenstates of J are those for which the angular momentum is identically zero (an 𝑠-state, in the language of spectroscopy). Nonetheless, since, each component of commutes with , it is possible to find an ONB of eigenstates common to and to the component of J along any single chosen direction. Usually the component of J along the 𝑧-axis is chosen, because of the simple form taken by the differential operator representing that component of orbital angular momentum in spherical coordinates. Note, however, that due to the cyclical nature of the commutation relations, anything deduced about the spectrum and eigenstates of and must also apply to the eigenstates common to and to any other component of .

In fact, one can show that the only possible eigenstates of J are those for which the angular momentum is identically zero (an 𝑠-state, in the language of spectroscopy). Nonetheless, since, each component of commutes with , it is possible to find an ONB of eigenstates common to and to the component of J along any single chosen direction. Usually the component of J along the 𝑧-axis is chosen, because of the simple form taken by the differential operator representing that component of orbital angular momentum in spherical coordinates. Note, however, that due to the cyclical nature of the commutation relations, anything deduced about the spectrum and eigenstates of and must also apply to the eigenstates common to and to any other component of .

In fact, one can show that the only possible eigenstates of J are those for which the angular momentum is identically zero (an 𝑠-state, in the language of spectroscopy). Nonetheless, since, each component of commutes with , it is possible to find an ONB of eigenstates common to and to the component of J along any single chosen direction. Usually the component of J along the 𝑧-axis is chosen, because of the simple form taken by the differential operator representing that component of orbital angular momentum in spherical coordinates. Note, however, that due to the cyclical nature of the commutation relations, anything deduced about the spectrum and eigenstates of and must also apply to the eigenstates common to and to any other component of .

We note also, that, as with , the operator is Hermitian and positive definite, and thus its eigenvalues must be greater than or equal to zero. For the moment, we will ignore other quantum numbers and simply denote a common eigenstate of and as , where, by definition, which shows that quantum number is the associated eigenvalue of the operator , while the quantum number labels, but is not equal to the corresponding eigenvalue of . Writing the eigenvalue of in this odd way, initially, will result in simple values for the quantum number . Note that we can write any positive eigenvalue of for some .

We note also, that, as with , the operator is Hermitian and positive definite, and thus its eigenvalues must be greater than or equal to zero. For the moment, we will ignore other quantum numbers and simply denote a common eigenstate of and as , where, by definition, which shows that quantum number is the associated eigenvalue of the operator , while the quantum number labels, but is not equal to the corresponding eigenvalue of . Writing the eigenvalue of in this odd way, initially, will result in simple values for the quantum number . Note that we can write any positive eigenvalue of for some .

We note also, that, as with , the operator is Hermitian and positive definite, and thus its eigenvalues must be greater than or equal to zero. For the moment, we will ignore other quantum numbers and simply denote a common eigenstate of and as , where, by definition, which shows that quantum number is the associated eigenvalue of the operator , while the quantum number labels, but is not equal to the corresponding eigenvalue of . Writing the eigenvalue of in this odd way, initially, will result in simple values for the quantum number . Note that we can write any positive eigenvalue of for some .

We note also, that, as with , the operator is Hermitian and positive definite, and thus its eigenvalues must be greater than or equal to zero. For the moment, we will ignore other quantum numbers and simply denote a common eigenstate of and as , where, by definition, which shows that quantum number is the associated eigenvalue of the operator , while the quantum number labels, but is not equal to the corresponding eigenvalue of . Writing the eigenvalue of in this odd way, initially, will result in simple values for the quantum number . Note that we can write any positive eigenvalue of for some .

We note also, that, as with , the operator is Hermitian and positive definite, and thus its eigenvalues must be greater than or equal to zero. For the moment, we will ignore other quantum numbers and simply denote a common eigenstate of and as , where, by definition, which shows that quantum number is the associated eigenvalue of the operator , while the quantum number labels, but is not equal to the corresponding eigenvalue of . Writing the eigenvalue of in this odd way, initially, will result in simple values for the quantum number . Note that we can write any positive eigenvalue of for some .

We note also, that, as with , the operator is Hermitian and positive definite, and thus its eigenvalues must be greater than or equal to zero. For the moment, we will ignore other quantum numbers and simply denote a common eigenstate of and as , where, by definition, which shows that quantum number is the associated eigenvalue of the operator , while the quantum number labels, but is not equal to the corresponding eigenvalue of . Writing the eigenvalue of in this odd way, initially, will result in simple values for the quantum number . Note that we can write any positive eigenvalue of for some .

We note also, that, as with , the operator is Hermitian and positive definite, and thus its eigenvalues must be greater than or equal to zero. For the moment, we will ignore other quantum numbers and simply denote a common eigenstate of and as , where, by definition, which shows that quantum number is the associated eigenvalue of the operator , while the quantum number labels, but is not equal to the corresponding eigenvalue of . Writing the eigenvalue of in this odd way, initially, will result in simple values for the quantum number . Note that we can write any positive eigenvalue of for some .

We note also, that, as with , the operator is Hermitian and positive definite, and thus its eigenvalues must be greater than or equal to zero. For the moment, we will ignore other quantum numbers and simply denote a common eigenstate of and as , where, by definition, which shows that quantum number is the associated eigenvalue of the operator , while the quantum number labels, but is not equal to the corresponding eigenvalue of . Writing the eigenvalue of in this odd way, initially, will result in simple values for the quantum number . Note that we can write any positive eigenvalue of as for some .

In the interest of brevity, we will refer to a state satisfying the eigenvalue equations as a “state of angular momentum ". To proceed further, it is convenient to trade in the two components of along the 𝑥 and 𝑦 axes for the non-Hermitian operator and its adjoint Of course when needed, we can always get back to the original operators and Thus, in determining the spectrum and common eigenstates of and ,we will find it convenient to work with the set of operators rather than the set

In the interest of brevity, we will refer to a state satisfying the eigenvalue equations as a “state of angular momentum ". To proceed further, it is convenient to trade in the two components of along the 𝑥 and 𝑦 axes for the non-Hermitian operator and its adjoint Of course when needed, we can always get back to the original operators and Thus, in determining the spectrum and common eigenstates of and ,we will find it convenient to work with the set of operators rather than the set

In the interest of brevity, we will refer to a state satisfying the eigenvalue equations as a “state of angular momentum ". To proceed further, it is convenient to trade in the two components of along the 𝑥 and 𝑦 axes for the non-Hermitian operator and its adjoint Of course when needed, we can always get back to the original operators and Thus, in determining the spectrum and common eigenstates of and ,we will find it convenient to work with the set of operators rather than the set

In the interest of brevity, we will refer to a state satisfying the eigenvalue equations as a “state of angular momentum ". To proceed further, it is convenient to trade in the two components of along the 𝑥 and 𝑦 axes for the non-Hermitian operator and its adjoint Of course when needed, we can always get back to the original operators and Thus, in determining the spectrum and common eigenstates of and ,we will find it convenient to work with the set of operators rather than the set

In the interest of brevity, we will refer to a state satisfying the eigenvalue equations as a “state of angular momentum ". To proceed further, it is convenient to trade in the two components of along the 𝑥 and 𝑦 axes for the non-Hermitian operator and its adjoint Of course when needed, we can always get back to the original operators and Thus, in determining the spectrum and common eigenstates of and ,we will find it convenient to work with the set of operators rather than the set

To solve this problem, we will need commutation relations for the operators in this new set. We note first that , being a linear combination of and , must commute with , since each of those operators do as well. The commutator of with is also readily established; we find that or

To solve this problem, we will need commutation relations for the operators in this new set. We note first that , being a linear combination of and , must commute with , since each of those operators do as well. The commutator of with is also readily established; we find that or

To solve this problem, we will need commutation relations for the operators in this new set. We note first that , being a linear combination of and , must commute with , since each of those operators do as well. The commutator of with is also readily established; we find that or

To solve this problem, we will need commutation relations for the operators in this new set. We note first that , being a linear combination of and , must commute with , since each of those operators do as well. The commutator of with is also readily established; we find that or

To solve this problem, we will need commutation relations for the operators in this new set. We note first that , being a linear combination of and , must commute with , since each of those operators do as well. The commutator of with is also readily established; we find that or

To solve this problem, we will need commutation relations for the operators in this new set. We note first that , being a linear combination of and , must commute with , since each of those operators do as well. The commutator of with is also readily established; we find that or

To solve this problem, we will need commutation relations for the operators in this new set. We note first that , being a linear combination of and , must commute with , since each of those operators do as well. The commutator of with is also readily established; we find that or

To solve this problem, we will need commutation relations for the operators in this new set. We note first that , being a linear combination of and , must commute with , since each of those operators do as well. The commutator of with is also readily established; we find that or

To solve this problem, we will need commutation relations for the operators in this new set. We note first that , being a linear combination of and , must commute with , since each of those operators do as well. The commutator of with is also readily established; we find that or

Note that these can be written in the following useful form: and Similarly, the commutator of and is Thus the commutation relations of interest take the form

Note that these can be written in the following useful form: and Similarly, the commutator of and is Thus the commutation relations of interest take the form

Note that these can be written in the following useful form: and Similarly, the commutator of and is Thus the commutation relations of interest take the form

Note that these can be written in the following useful form: and Similarly, the commutator of and is Thus the commutation relations of interest take the form

Note that these can be written in the following useful form: and Similarly, the commutator of and is Thus the commutation relations of interest take the form

Note that these can be written in the following useful form: and Similarly, the commutator of and is Thus the commutation relations of interest take the form

Note that these can be written in the following useful form: and Similarly, the commutator of and is Thus the commutation relations of interest take the form

Note that these can be written in the following useful form: and Similarly, the commutator of and is Thus the commutation relations of interest take the form

Note that these can be written in the following useful form: and Similarly, the commutator of and is Thus the commutation relations of interest take the form

It will also be necessary in what follows to express the operator in terms of the new "components“ rather than the old components . To this end we note that and so Similarly Adding these last two results, dividing by two and adding gives the relation

It will also be necessary in what follows to express the operator in terms of the new "components“ rather than the old components . To this end we note that and so Similarly Adding these last two results, dividing by two and adding gives the relation

It will also be necessary in what follows to express the operator in terms of the new "components“ rather than the old components . To this end we note that and so Similarly Adding these last two results, dividing by two and adding gives the relation

It will also be necessary in what follows to express the operator in terms of the new "components“ rather than the old components . To this end we note that and so Similarly Adding these last two results, dividing by two and adding gives the relation

It will also be necessary in what follows to express the operator in terms of the new "components“ rather than the old components . To this end we note that and so Similarly Adding these last two results, dividing by two and adding gives the relation

It will also be necessary in what follows to express the operator in terms of the new "components“ rather than the old components . To this end we note that and so Similarly Adding these last two results, dividing by two and adding gives the relation

It will also be necessary in what follows to express the operator in terms of the new "components“ rather than the old components . To this end we note that and so Similarly Adding these last two results, dividing by two and adding gives the relation

It will also be necessary in what follows to express the operator in terms of the new "components“ rather than the old components . To this end we note that and so Similarly Adding these last two results, dividing by two and adding gives the relation

It will also be necessary in what follows to express the operator in terms of the new "components“ rather than the old components . To this end we note that and so Similarly Adding these last two results, dividing by two and adding gives the relation

It will also be necessary in what follows to express the operator in terms of the new "components“ rather than the old components . To this end we note that and so Similarly Adding these last two results, dividing by two and adding gives the relation

It will also be necessary in what follows to express the operator in terms of the new "components“ rather than the old components . To this end we note that and so Similarly Adding these last two results, dividing by two and adding gives the relation

It will also be necessary in what follows to express the operator in terms of the new "components“ rather than the old components . To this end we note that and so Similarly Adding these last two results, dividing by two and adding gives the relation

It will also be necessary in what follows to express the operator in terms of the new "components“ rather than the old components . To this end we note that and so Similarly Adding these last two results, dividing by two and adding gives the relation

With these relations we can now proceed to deduce allowed values in the spectrum of and . Let be an arbitrary nonzero eigenvector of and with angular momentum , where the eigenvalues of satisfy the inequalities with Using this, and the commutation relations, we now prove a few theorems. For a given value of , the eigenvalue must lie in the range To show this, consider the vectors and whose squared norms are and

With these relations we can now proceed to deduce allowed values in the spectrum of and . Let be an arbitrary nonzero eigenvector of and with angular momentum , where the eigenvalues of satisfy the inequalities with Using this, and the commutation relations, we now prove a few theorems. For a given value of , the eigenvalue must lie in the range To show this, consider the vectors and whose squared norms are and

With these relations we can now proceed to deduce allowed values in the spectrum of and . Let be an arbitrary nonzero eigenvector of and with angular momentum , where the eigenvalues of satisfy the inequalities with Using this, and the commutation relations, we now prove a few theorems. For a given value of , the eigenvalue must lie in the range To show this, consider the vectors and whose squared norms are and

With these relations we can now proceed to deduce allowed values in the spectrum of and . Let be an arbitrary nonzero eigenvector of and with angular momentum , where the eigenvalues of satisfy the inequalities with Using this, and the commutation relations, we now prove a few theorems. For a given value of , the eigenvalue must lie in the range To show this, consider the vectors and whose squared norms are and

With these relations we can now proceed to deduce allowed values in the spectrum of and . Let be an arbitrary nonzero eigenvector of and with angular momentum , where the eigenvalues of satisfy the inequalities with Using this, and the commutation relations, we now prove a few theorems. For a given value of , the eigenvalue must lie in the range To show this, consider the vectors and whose squared norms are and

With these relations we can now proceed to deduce allowed values in the spectrum of and . Let be an arbitrary nonzero eigenvector of and with angular momentum , where the eigenvalues of satisfy the inequalities with Using this, and the commutation relations, we now prove a few theorems. For a given value of , the eigenvalue must lie in the range To show this, consider the vectors and whose squared norms are and

With these relations we can now proceed to deduce allowed values in the spectrum of and . Let be an arbitrary nonzero eigenvector of and with angular momentum , where the eigenvalues of satisfy the inequalities with Using this, and the commutation relations, we now prove a few theorems. For a given value of , the eigenvalue must lie in the range To show this, consider the vectors and whose squared norms are and

But we have already shown that so the statement can be written which clearly requires . With this implies that for positive , we must have . This is also clearly satisfied for negative . Thus, for any such state we have the upper bound

But we have already shown that so the statement can be written which clearly requires . With this implies that for positive , we must have . This is also clearly satisfied for negative . Thus, for any such state we have the upper bound

But we have already shown that so the statement can be written which clearly requires . With this implies that for positive , we must have . This is also clearly satisfied for negative . Thus, for any such state we have the upper bound

But we have already shown that so the statement can be written which clearly requires . With this implies that for positive , we must have . This is also clearly satisfied for negative . Thus, for any such state we have the upper bound

But we have already shown that so the statement can be written which clearly requires . With this implies that for positive , we must have . This is also clearly satisfied for negative . Thus, for any such state we have the upper bound

But we have already shown that so the statement can be written which clearly requires . With this implies that for positive , we must have . This is also clearly satisfied for negative . Thus, for any such state we have the upper bound

But we have already shown that so the statement can be written which clearly requires . With this implies that for positive , we must have . This is also clearly satisfied for negative . Thus, for any such state we have the upper bound

But we have already shown that so the statement can be written which clearly requires . With this implies that for positive , we must have . This is also clearly satisfied for negative . Thus, for any such state we have the upper bound

Similarly, we have shown that so the statement can be written which clearly requires . With and negative , introduce the positive quantity so that which then requires , Multiplying this last inequality by -1 reverses that inequality and gives the lower bound which is also obviously satisfied for any positive value of .

Similarly, we have shown that so the statement can be written which clearly requires . With and negative , introduce the positive quantity so that which then requires , Multiplying this last inequality by -1 reverses that inequality and gives the lower bound which is also obviously satisfied for any positive value of .

Similarly, we have shown that so the statement can be written which clearly requires . With and negative , introduce the positive quantity so that which then requires , Multiplying this last inequality by -1 reverses that inequality and gives the lower bound which is also obviously satisfied for any positive value of .

Similarly, we have shown that so the statement can be written which clearly requires . With and negative , introduce the positive quantity so that which then requires , Multiplying this last inequality by -1 reverses that inequality and gives the lower bound which is also obviously satisfied for any positive value of .

Similarly, we have shown that so the statement can be written which clearly requires . With and negative , introduce the positive quantity so that which then requires , Multiplying this last inequality by -1 reverses that inequality and gives the lower bound which is also obviously satisfied for any positive value of .

Similarly, we have shown that so the statement can be written which clearly requires . With and negative , introduce the positive quantity so that which then requires , Multiplying this last inequality by -1 reverses that inequality and gives the lower bound which is also obviously satisfied for any positive value of .

Similarly, we have shown that so the statement can be written which clearly requires . With and negative , introduce the positive quantity so that which then requires , Multiplying this last inequality by -1 reverses that inequality and gives the lower bound which is also obviously satisfied for any positive value of .

Similarly, we have shown that so the statement can be written which clearly requires . With and negative , introduce the positive quantity so that which then requires , Multiplying this last inequality by -1 reverses that inequality and gives the lower bound which is also obviously satisfied for any positive value of .

Similarly, we have shown that so the statement can be written which clearly requires . With and negative , introduce the positive quantity so that which then requires , Multiplying this last inequality by -1 reverses that inequality and gives the lower bound which is also obviously satisfied for any positive value of .

Similarly, we have shown that so the statement can be written which clearly requires . With and negative , introduce the positive quantity so that which then requires , Multiplying this last inequality by -1 reverses that inequality and gives the lower bound which is also obviously satisfied for any positive value of .

Similarly, we have shown that so the statement can be written which clearly requires . With and negative , introduce the positive quantity so that which then requires , Multiplying this last inequality by -1 reverses that inequality and gives the lower bound which is also obviously satisfied for any positive value of .

Combining the upper and lower bounds obtained in this way, we verify that for a given value of , any state of angular momentum has a value of satisfying Having narrowed the range for the eigenvalues of , we now prove a second theorem. 2. The vector vanishes if and only if . Otherwise, is an eigenvector of and with angular momentum , i.e., it is an eigenvector of with the same eigenvalue , but it is an eigenvector of with eigenvalue that is greater by one relative to the state .

Combining the upper and lower bounds obtained in this way, we verify that for a given value of , any state of angular momentum has a value of satisfying Having narrowed the range for the eigenvalues of , we now prove a second theorem. 2. The vector vanishes if and only if . Otherwise, is an eigenvector of and with angular momentum , i.e., it is an eigenvector of with the same eigenvalue , but it is an eigenvector of with eigenvalue that is greater by one relative to the state .

Combining the upper and lower bounds obtained in this way, we verify that for a given value of , any state of angular momentum has a value of satisfying Having narrowed the range for the eigenvalues of , we now prove a second theorem. 2. The vector vanishes if and only if . Otherwise, is an eigenvector of and with angular momentum , i.e., it is an eigenvector of with the same eigenvalue , but it is an eigenvector of with eigenvalue that is greater by one relative to the state .

Combining the upper and lower bounds obtained in this way, we verify that for a given value of , any state of angular momentum has a value of satisfying Having narrowed the range for the eigenvalues of , we now prove a second theorem. 2. The vector vanishes if and only if . Otherwise, is an eigenvector of and with angular momentum , i.e., it is an eigenvector of with the same eigenvalue , but it is an eigenvector of with eigenvalue that is greater by one relative to the state .

Combining the upper and lower bounds obtained in this way, we verify that for a given value of , any state of angular momentum has a value of satisfying Having narrowed the range for the eigenvalues of , we now prove a second theorem. 2. The vector vanishes if and only if . Otherwise, is an eigenvector of and with angular momentum , i.e., it is an eigenvector of with the same eigenvalue , but it is an eigenvector of with eigenvalue that is greater by one relative to the state .

To show the first half of the statement, we note from our previous expression that Since , given the bounds on , it follows that vanishes if and only if . To prove the second part, we first use the commutation relation in the form to write showing that is an eigenvector of with eigenvalue , and then observe that, because , showing that is then also an eigenvector of with eigenvalue .

To show the first half of the statement, we note from our previous expression that Since , given the bounds on , it follows that vanishes if and only if . To prove the second part, we first use the commutation relation in the form to write showing that is an eigenvector of with eigenvalue , and then observe that, because , showing that is then also an eigenvector of with eigenvalue .

To show the first half of the statement, we note from our previous expression that Since , given the bounds on , it follows that vanishes if and only if . To prove the second part, we first use the commutation relation in the form to write showing that is an eigenvector of with eigenvalue , and then observe that, because , showing that is then also an eigenvector of with eigenvalue .

To show the first half of the statement, we note from our previous expression that Since , given the bounds on , it follows that vanishes if and only if . To prove the second part, we first use the commutation relation in the form to write showing that is an eigenvector of with eigenvalue , and then observe that, because , showing that is then also an eigenvector of with eigenvalue .

To show the first half of the statement, we note from our previous expression that Since , given the bounds on , it follows that vanishes if and only if . To prove the second part, we first use the commutation relation in the form to write showing that is an eigenvector of with eigenvalue , and then observe that, because , showing that is then also an eigenvector of with eigenvalue .

To show the first half of the statement, we note from our previous expression that Since , given the bounds on , it follows that vanishes if and only if . To prove the second part, we first use the commutation relation in the form to write showing that is an eigenvector of with eigenvalue , and then observe that, because , showing that is then also an eigenvector of with eigenvalue .

To show the first half of the statement, we note from our previous expression that Since , given the bounds on , it follows that vanishes if and only if . To prove the second part, we first use the commutation relation in the form to write showing that is an eigenvector of with eigenvalue , and then observe that, because , showing that is then also an eigenvector of with eigenvalue .

To show the first half of the statement, we note from our previous expression that Since , given the bounds on , it follows that vanishes if and only if . To prove the second part, we first use the commutation relation in the form to write showing that is an eigenvector of with eigenvalue , and then observe that, because , showing that is then also an eigenvector of with eigenvalue .

To show the first half of the statement, we note from our previous expression that Since , given the bounds on , it follows that vanishes if and only if . To prove the second part, we first use the commutation relation in the form to write showing that is an eigenvector of with eigenvalue , and then observe that, because , showing that is then also an eigenvector of with eigenvalue .

To show the first half of the statement, we note from our previous expression that Since , given the bounds on , it follows that vanishes if and only if . To prove the second part, we first use the commutation relation in the form to write showing that is an eigenvector of with eigenvalue , and then observe that, because , showing that is then also an eigenvector of with eigenvalue .

We then prove a third final theorem: 3. The vector vanishes if and only if . Otherwise, is an eigenvector of and with angular momentum , i.e., it is an eigenvector of with the same eigenvalue , but it is an eigenvector of with eigenvalue that is lower by one relative to the state . To show the first half of the statement, we note from our previous expression that Since , given the bounds on , it follows that vanishes if and only if , for which

We then prove a third final theorem: 3. The vector vanishes if and only if . Otherwise, is an eigenvector of and with angular momentum , i.e., it is an eigenvector of with the same eigenvalue , but it is an eigenvector of with eigenvalue that is lower by one relative to the state . To show the first half of the statement, we note from our previous expression that Since , given the bounds on , it follows that vanishes if and only if , for which

We then prove a third final theorem: 3. The vector vanishes if and only if . Otherwise, is an eigenvector of and with angular momentum , i.e., it is an eigenvector of with the same eigenvalue , but it is an eigenvector of with eigenvalue that is lower by one relative to the state . To show the first half of the statement, we note from our previous expression that Since , given the bounds on , it follows that vanishes if and only if , for which

We then prove a third final theorem: 3. The vector vanishes if and only if . Otherwise, is an eigenvector of and with angular momentum , i.e., it is an eigenvector of with the same eigenvalue , but it is an eigenvector of with eigenvalue that is lower by one relative to the state . To show the first half of the statement, we note from our previous expression that Since , given the bounds on , it follows that vanishes if and only if , for which

We then prove a third final theorem: 3. The vector vanishes if and only if . Otherwise, is an eigenvector of and with angular momentum , i.e., it is an eigenvector of with the same eigenvalue , but it is an eigenvector of with eigenvalue that is lower by one relative to the state . To show the first half of the statement, we note from our previous expression that Since , given the bounds on , it follows that vanishes if and only if , for which

We then prove a third final theorem: 3. The vector vanishes if and only if . Otherwise, is an eigenvector of and with angular momentum , i.e., it is an eigenvector of with the same eigenvalue , but it is an eigenvector of with eigenvalue that is lower by one relative to the state . To show the first half of the statement, we note from our previous expression that Since , given the bounds on , it follows that vanishes if and only if , for which

We then prove a third final theorem: 2. The vector vanishes if and only if . Otherwise, is an eigenvector of and with angular momentum , i.e., it is an eigenvector of with the same eigenvalue , but it is an eigenvector of with eigenvalue that is lower by one relative to the state . To show the first half of the statement, we note from our previous expression that Since , given the bounds on , it follows that vanishes if and only if , for which

To prove the second part, we first use the commutation relation in the form to write showing that is an eigenvector of with eigenvalue , and then observe that, because , showing that is also an eigenvector of with eigenvalue . With these three theorems in hand, we now proceed to restrict even further the spectra of and .

To prove the second part, we first use the commutation relation in the form to write showing that is an eigenvector of with eigenvalue , and then observe that, because , showing that is also an eigenvector of with eigenvalue . With these three theorems in hand, we now proceed to restrict even further the spectra of and .

To prove the second part, we first use the commutation relation in the form to write showing that is an eigenvector of with eigenvalue , and then observe that, because , showing that is also an eigenvector of with eigenvalue . With these three theorems in hand, we now proceed to restrict even further the spectra of and .

To prove the second part, we first use the commutation relation in the form to write showing that is an eigenvector of with eigenvalue , and then observe that, because , showing that is also an eigenvector of with eigenvalue . With these three theorems in hand, we now proceed to restrict even further the spectra of and .

To prove the second part, we first use the commutation relation in the form to write showing that is an eigenvector of with eigenvalue , and then observe that, because , showing that is also an eigenvector of with eigenvalue . With these three theorems in hand, we now proceed to restrict even further the spectra of and .

To prove the second part, we first use the commutation relation in the form to write showing that is an eigenvector of with eigenvalue , and then observe that, because , showing that is also an eigenvector of with eigenvalue . With these three theorems in hand, we now proceed to restrict even further the spectra of and .

To prove the second part, we first use the commutation relation in the form to write showing that is an eigenvector of with eigenvalue , and then observe that, because , showing that is also an eigenvector of with eigenvalue . Because of their effects on the states , the operator is referred to as the raising operator, since it acts to increase the component of angular momentum along the z-axis by one unit and is referred to as the lowering operator, since it acts to decrease it by one.

With these three theorems in hand, we now proceed to restrict even further the spectra of and . We note, e.g., that, given any state of angular momentum we can produce a sequence of eigenvectors of and with eigenvalues This sequence must terminate, or else produce eigenvectors of with eigenvalues violating the upper bound . But termination can only occur when acts on the last nonzero vector of the sequence, , with eigenvalue say, and takes it on to the null vector. But, this only occurs if .

With these three theorems in hand, we now proceed to restrict even further the spectra of and . We note, e.g., that, given any state of angular momentum we can produce a sequence of eigenvectors of and with eigenvalues This sequence must terminate, or else produce eigenvectors of with eigenvalues violating the upper bound . But termination can only occur when acts on the last nonzero vector of the sequence, , with eigenvalue say, and takes it on to the null vector. But, this only occurs if .

With these three theorems in hand, we now proceed to restrict even further the spectra of and . We note, e.g., that, given any state of angular momentum we can produce a sequence of eigenvectors of and with eigenvalue This sequence must terminate, or else produce eigenvectors of with eigenvalues violating the upper bound . But termination can only occur when acts on the last nonzero vector of the sequence, , with eigenvalue say, and takes it on to the null vector. But, this only occurs if .

With these three theorems in hand, we now proceed to restrict even further the spectra of and . We note, e.g., that, given any state of angular momentum we can produce a sequence of eigenvectors of and with eigenvalue This sequence must terminate, or else produce eigenvectors of with eigenvalues violating the upper bound . But termination can only occur when acts on the last nonzero vector of the sequence, , with eigenvalue say, and takes it on to the null vector. But, this only occurs if .

With these three theorems in hand, we now proceed to restrict even further the spectra of and . We note, e.g., that, given any state of angular momentum we can produce a sequence of eigenvectors of and with eigenvalue This sequence must terminate, or else produce eigenvectors of with eigenvalues violating the upper bound . But termination can only occur when acts on the last nonzero vector of the sequence, , with eigenvalue say, and takes it on to the null vector. But, this only occurs if .

With these three theorems in hand, we now proceed to restrict even further the spectra of and . We note, e.g., that, given any state of angular momentum we can produce a sequence of eigenvectors of and with eigenvalue This sequence must terminate, or else produce eigenvectors of with eigenvalues violating the upper bound . But termination can only occur when acts on the last nonzero vector of the sequence, , with eigenvalue say, and takes it on to the null vector. But, this only occurs if .

With these three theorems in hand, we now proceed to restrict even further the spectra of and . We note, e.g., that, given any state of angular momentum we can produce a sequence of eigenvectors of and with eigenvalues This sequence must terminate, or else produce eigenvectors of with eigenvalues violating the upper bound . But termination can only occur when acts on the last nonzero vector of the sequence, , with eigenvalue say, and takes it on to the null vector. But, this only occurs if .

With these three theorems in hand, we now proceed to restrict even further the spectra of and . We note, e.g., that, given any state of angular momentum we can produce a sequence of eigenvectors of and with eigenvalues This sequence must terminate, or else produce eigenvectors of with eigenvalues violating the upper bound . But termination can only occur when acts on the last nonzero vector of the sequence, , with eigenvalue say, and takes it on to the null vector. But, this only occurs if .

With these three theorems in hand, we now proceed to restrict even further the spectra of and . We note, e.g., that, given any state of angular momentum we can produce a sequence of eigenvectors of and with eigenvalues This sequence must terminate, or else produce eigenvectors of with eigenvalues violating the upper bound . But termination can only occur when acts on the last nonzero vector of the sequence, , with eigenvalue say, and takes it on to the null vector. But, this only occurs if .

Thus, there exists an integer such that Similar arguments can be made for the sequence of eigenvectors of J² and J_{z} with eigenvalues To now avoid violating the lower bound , the operator must act on the last nonzero vector of the sequence, with eigenvalue to take it onto the null vector. But this only occurs if . Thus, there exists an integer such that

Thus, there exists an integer such that Similar arguments can be made for the sequence of eigenvectors of and with eigenvalue To now avoid violating the lower bound , the operator must act on the last nonzero vector of the sequence, with eigenvalue to take it onto the null vector. But this only occurs if . Thus, there exists an integer such that

Thus, there exists an integer such that Similar arguments can be made for the sequence of eigenvectors of and with eigenvalues To now avoid violating the lower bound , the operator must act on the last nonzero vector of the sequence, with eigenvalue to take it onto the null vector. But this only occurs if . Thus, there exists an integer such that

Thus, there exists an integer such that Similar arguments can be made for the sequence of eigenvectors of and with eigenvalues To now avoid violating the lower bound , the operator must act on the last nonzero vector of the sequence, with eigenvalue to take it onto the null vector. But this only occurs if . Thus, there exists an integer such that

Thus, there exists an integer such that Similar arguments can be made for the sequence of eigenvectors of and with eigenvalues To now avoid violating the lower bound , the operator must act on the last nonzero vector of the sequence, with eigenvalue to take it onto the null vector. But this only occurs if . Thus, there exists an integer such that

Thus, there exists an integer such that Similar arguments can be made for the sequence of eigenvectors of and with eigenvalues To now avoid violating the lower bound , the operator must act on the last nonzero vector of the sequence, with eigenvalue to take it onto the null vector. But this only occurs if . Thus, there exists an integer such that

Thus, there exists an integer such that Similar arguments can be made for the sequence of eigenvectors of and with eigenvalues To now avoid violating the lower bound , the operator must act on the last nonzero vector of the sequence, with eigenvalue to take it onto the null vector. But this only occurs if . Thus, there exists an integer such that

Thus, there exists an integer such that Similar arguments can be made for the sequence of eigenvectors of and with eigenvalues To now avoid violating the lower bound , the operator must act on the last nonzero vector of the sequence, with eigenvalue to take it onto the null vector. But this only occurs if . Thus, there exists an integer such that

Adding the two relations we deduce that there exists an integer such that or Thus, j must be either an integer or a half-integer. If N is an even integer, then j is itself a non-negative integer in the set For this situation, the results of the proceeding analysis indicate that m must also be an integer and, for a given integer value of j, the values must take on each of the integer values

Adding the two relations we deduce that there exists an integer such that or Thus, j must be either an integer or a half-integer. If N is an even integer, then j is itself a non-negative integer in the set For this situation, the results of the proceeding analysis indicate that m must also be an integer and, for a given integer value of j, the values must take on each of the integer values

Adding the two relations we deduce that there exists an integer such that or Thus, j must be either an integer or a half-integer. If N is an even integer, then j is itself a non-negative integer in the set For this situation, the results of the proceeding analysis indicate that m must also be an integer and, for a given integer value of j, the values must take on each of the integer values

Adding the two relations we deduce that there exists an integer such that or Thus, j must be either an integer or a half-integer. If N is an even integer, then j is itself a non-negative integer in the set For this situation, the results of the proceeding analysis indicate that m must also be an integer and, for a given integer value of j, the values must take on each of the integer values

Adding the two relations we deduce that there exists an integer such that or Thus, j must be either an integer or a half-integer. If N is an even integer, then in this case, and is said to be an integral value of angular momentum. For this situation, the results of the proceeding analysis indicate that the values must also be an integer and take on each of the integer values

Adding the two relations we deduce that there exists an integer such that or Thus, j must be either an integer or a half-integer. If N is an even integer, then in this case, and is said to be an integral value of angular momentum. For this situation, the results of the proceeding analysis indicate that must also be an integer and take on each of the integer values

If is an odd integer, then differs from an integer by 1/2, i. e If is an odd integer, then differs from an integer by 1/2, i.e., it is in the set and is then said to be half-integral (short for half-odd- integral). For a given half-integral value of , the values of must then take on each of the half-odd-integer values . Thus, we have deduced the values of and that are consistent with the commutation relations. In particular, the allowed values of that can occur are the non-negative integers and the positive half-odd-integers. For each value of j, the eigenvectors of and always come in sets, or multi- plets, of fold mutually-orthogonal eigenvectors

If is an odd integer, then differs from an integer by 1/2, i. e If is an odd integer, then differs from an integer by 1/2, i.e., it is in the set and is then said to be half-integral (short for half-odd- integral). For a given half-integral value of , the values of must then take on each of the half-odd-integer values . Thus, we have deduced the values of and that are consistent with the commutation relations. In particular, the allowed values of that can occur are the non-negative integers and the positive half-odd-integers. For each value of j, the eigenvectors of and always come in sets, or multi- plets, of fold mutually-orthogonal eigenvectors

If is an odd integer, then differs from an integer by 1/2, i. e If is an odd integer, then differs from an integer by 1/2, i.e., it is in the set and is then said to be half-integral (short for half-odd- integral). For a given half-integral value of , the values of must then take on each of the half-odd-integer values . Thus, we have deduced the values of and that are consistent with the commutation relations. In particular, the allowed values of that can occur are the non-negative integers and the positive half-odd-integers. For each value of j, the eigenvectors of and always come in sets, or multi- plets, of fold mutually-orthogonal eigenvectors

If is an odd integer, then differs from an integer by 1/2, i. e If is an odd integer, then differs from an integer by 1/2, i.e., it is in the set and is then said to be half-integral (short for half-odd- integral). For a given half-integral value of , the values of must then take on each of the half-odd-integer values . Thus, we have deduced the values of and that are consistent with the commutation relations. In particular, the allowed values of that can occur are the non-negative integers and half-odd-integers. For each value of j, the eigenvectors of and always come in sets, or multi- plets, of fold mutually-orthogonal eigenvectors

If is an odd integer, then differs from an integer by 1/2, i. e If is an odd integer, then differs from an integer by 1/2, i.e., it is in the set and is then said to be half-integral (short for half-odd- integral). For a given half-integral value of , the values of must then take on each of the half-odd-integer values . Thus, we have deduced the values of and that are consistent with the commutation relations. In particular, the allowed values of that can occur are the non-negative integers and half-odd-integers. For each value of j, the eigenvectors of and always come in sets, or multiplets, of fold mutually-orthogonal eigenvectors

In any given problem involving an angular momentum it must be determined which of the allowed values of and how many multiplets (corresponding to different values of other quantum numbers) for each such value of actually occur. All the integer values of angular momentum do, in fact, arise as we will see in our study of the orbital angular momentum of a single particle. Half-integral values of angular momentum, on the other hand, are associated with the internal or spin degrees of freedom of particles of the class of particles referred to as fermions. Other particles, referred to as bosons, are particles that are empirically found to have integer spins.

In any given problem involving an angular momentum it must be determined which of the allowed values of and how many multiplets (corresponding to different values of other quantum numbers) for each such value of actually occur. All the integer values of angular momentum do, in fact, occur in nature as we will see in our study of the orbital angular momentum of a single particle. Half-integral values of angular momentum, on the other hand, are associated with the internal or spin degrees of freedom of particles of the class of particles referred to as fermions. Other particles, referred to as bosons, are particles that are empirically found to have integer spins.

In any given problem involving an angular momentum it must be determined which of the allowed values of and how many multiplets (corresponding to different values of other quantum numbers) for each such value of actually occur. All the integer values of angular momentum do, in fact, occur in nature as we will see in our study of the orbital angular momentum of a single particle. Half-integral values of angular momentum, on the other hand, are associated with the internal or spin degrees of freedom of the class of particles referred to as fermions. Other particles, referred to as bosons, are particles that are empirically found to have integer spins.

In any given problem involving an angular momentum it must be determined which of the allowed values of and how many multiplets (corresponding to different values of other quantum numbers) for each such value of actually occur. All the integer values of angular momentum do, in fact, occur in nature as we will see in our study of the orbital angular momentum of a single particle. Half-integral values of angular momentum, on the other hand, are associated with the internal or spin degrees of freedom of the class of particles referred to as fermions. Other particles, referred to as bosons, are particles that are empirically found to have integer spins.

The total angular momentum of a system of particles will generally have contributions from both orbital and spin angular momenta and can be either integral or half-integral, depending upon the number and type of particles in the system. Thus, generally speaking, there actually exist different systems in which the possible values of j and m deduced above are actually realized. In other words, there appear to be no super-selection rules in nature that further restrict the allowed values of angular momentum from those allowed by the fundamental commutation relations. This is sometimes said to arise from physicist Murray Gell-Mann’s Totalitarian Principle which states that (in physics at any rate) Everything not forbidden is compulsory.

The total angular momentum of a system of particles will generally have contributions from both orbital and spin angular momenta and can be either integral or half-integral, depending upon the number and type of particles in the system. Thus, generally speaking, there actually exist different systems in which the possible values of and deduced above are actually realized. In other words, there appear to be no super-selection rules in nature that further restrict the allowed values of angular momentum from those allowed by the fundamental commutation relations. This is sometimes said to arise from physicist Murray Gell-Mann’s Totalitarian Principle which states that (in physics at any rate) Everything not forbidden is compulsory.

The total angular momentum of a system of particles will generally have contributions from both orbital and spin angular momenta and can be either integral or half-integral, depending upon the number and type of particles in the system. Thus, generally speaking, there actually exist different systems in which the possible values of and deduced above are actually realized. In other words, there appear to be no super-selection rules in nature that might further restrict the values of angular momentum from those allowed by the fundamental commutation relations. This is sometimes said to arise from physicist Murray Gell-Mann’s Totalitarian Principle which states that (in physics at any rate) Everything not forbidden is compulsory.

The total angular momentum of a system of particles will generally have contributions from both orbital and spin angular momenta and can be either integral or half-integral, depending upon the number and type of particles in the system. Thus, generally speaking, there actually exist different systems in which the possible values of and deduced above are actually realized. In other words, there appear to be no super-selection rules in nature that might further restrict the values of angular momentum from those allowed by the fundamental commutation relations. This is sometimes said to arise from the so-called Totalitarian Principle, first enunciated by physicist Murray Gell-Mann which states that (in physics at any rate) Everything not forbidden is compulsory.

The total angular momentum of a system of particles will generally have contributions from both orbital and spin angular momenta and can be either integral or half-integral, depending upon the number and type of particles in the system. Thus, generally speaking, there actually exist different systems in which the possible values of and deduced above are actually realized. In other words, there appear to be no super-selection rules in nature that might further restrict the values of angular momentum from those allowed by the fundamental commutation relations. This is sometimes said to arise from the so-called Totalitarian Principle, first enunciated by physicist Murray Gell-Mann which states that (in physics at any rate) Everything not forbidden is compulsory.