Chapter 11: Stoichiometry

Slides:



Advertisements
Similar presentations
Stoichiometry The calculation of quantities using chemical reactions
Advertisements

Section 11.1 Defining Stoichiometry
Section 3: Limiting Reactants
1 Chapter 5 Chemical Reactions 5.9a The Mole Relationships in Chemical Equations.
CHAPTER THREE CHEMICAL EQUATIONS & REACTION STOICHIOMETRY Goals Chemical Equations Calculations Based on Chemical Equations The Limiting Reactant Concept.
Chapter 12 Stoichiometry part 1. Stoichiometry The study of quantitative relationships between amounts of reactants used and products formed by a chemical.
Chapter 11 Stoichiometry.
2 Eggs + 4 Bacon + 1 OJ + 2 Toast  1 Breakfast.
STOICHIOMETRY Calculations Based on Chemical Equations.
CHEMISTRY Matter and Change
Stoichiometry Section 12.1.
Stoichiometry Devon Bateman. Essential Question Why is a foot…a foot? –King Henry I had a foot 12 inches long.
Chapter12 Stoichiometry. I. What is Stoichiometry? The study of quantitative relationships between amounts of reactants used and products formed by a.
Bell Work: Mole Ratios 2 C 4 H 10 + ___ O 2 → ___ CO 2 + ___ H 2 O 1. Finish balancing the equation. How many moles of oxygen will react? 3. water.
STOICHIOMETRY Calculations Based on Chemical Equations.
Section 2Chemical Reactions Describing Reactions 〉 What is a chemical equation? 〉 A chemical equation uses symbols to represent a chemical reaction and.
What is stoichiometry Chapter Vocabulary Word stoichiometery: the study of quantitative relationships btwn the amounts of reactants and products.
Chapter 11: Stoichiometry
Unit 12: Stoichiometry Stoicheion = element Metron = to measure.
STOICHIOMETR Y is G LAM O R O US ARE YOU READY? A. _______________________ involves the study of the relationships between ________________ and _______________.
Stoichiometry Ch. 12 Page 352. What is “stoichiometry”?  A way of figuring out how much of a product can be made from a given amount of reactant  Based.
Learning Objectives Perform stoichiometric calculations to determine – Mass relationships between products and reactants Stoichiometric Calculations.
Chapter 12 Stoichiometry. Stoichiometry Topics Conservation of mass and the balanced chemical equation Mole ratios in a chemical equation Stoichiometric.
Stoichiometry. The study of quantitative relationships between amounts of reactants used and products formed by a chemical reaction is called Stoichiometry.
Chemistry Ch 12 Stoichiometry Notes #1. What is stoichiometry? Study of quantitative relationships btwn amounts of reactants used and products formed.
Chemistry 1 – Notes #3b Chapter 12 Stoichiometry.
Stoichiometry Chemistry – Chapter 12.
Stoichiometry: the study of the quantitative relationships that exist between the amounts of reactants and products in a chemical reaction. Stoichiometry.
Stoichiometry Coach Cox.
Stoichiometry Chemistry – Chapter 12.
7.6 Mole Relationships in Chemical Equations
UNIT 11 STOICHIOMETRY Stoichiometry is the study of quantitative relationships between the amounts of reactants used and amounts of products formed by.
Stoichiometry Section 12.1.
Lecture 60 Defining Stoichiometry Ozgur Unal
Stoichiometry.
12.1 – What is Stoichiometry?
11.1 Defining Stoichiometry Ashley Lardizabal Discovery School
Click a hyperlink or folder tab to view the corresponding slides.
Stoichiometry Chapter 11.
Calculations Based on Chemical Equations
Chapter 5 Chemical Reactions and Quantities
Chapter 8 Chemical Quantities in Reactions
Stoichiometry.
Calculations Based on Chemical Equations
Stoichiometry Unit 8 Lesson 1.
Stoichiometry Notes.
Stoichiometry Unit 8 Lesson 1.
FORMING NEW SUBSTANCES
FORMING NEW SUBSTANCES
FORMING NEW SUBSTANCES
Stoichiometry II.
9.1 NOTES Stoichiometry.
Stoichiometry Notes.
Stoichiometry based on the law of conservation of mass
Chapter 5 Chemical Quantities and Reactions
Stoichiometry Section 12.1.
Chemical Reactions and Quantities
Calculations Based on Chemical Equations
Chapter 6 Chemical Reactions and Quantities
Chapter 5 Chemical Quantities and Reactions
Reaction Stoichiometry
Chapter 11: Stoichiometry
Stoichiometry.
Stoichiometry Chapter 12.
Stoichiometry.
Stoichiometry Unit 8 Lesson 1.
Stoichiometry Chapter 11.
FORMING NEW SUBSTANCES
STOICHIOMETRY.
The mole ratio.
Presentation transcript:

Chapter 11: Stoichiometry Section 1: Defining Stoichiometry

Particle and Mole Relationships The study of quantitative relationships between the amounts of reactants used and amounts of products formed by a chemical reaction is called stoichiometry. Based on the Law of Conservation of Mass…matter is neither created nor destroyed in a chemical reaction. Mass of reactants = Mass of products

Stoichiometry Relationships Derived From a Balanced Chemical Equation 4Fe(s) + 3O2(g)  2Fe2O3(s) Iron + Oxygen  Iron (III) Oxide 4 atoms of Fe + 3 molecules O2  2 molecules Fe2O3 4 moles Fe + 3 moles O2  2 moles Fe2O3 223.4g Fe + 96.00g O2  319.4g Fe2O3 319.4g reactants  319.4 g products

Mole Ratios The coefficients in a balanced chemical reaction indicate the relationships between moles of reactants and products. We can use this information to derive conversion factors called mole ratios. A mole ratio is a ratio between the number of moles of any two substances in a balanced chemical reaction.

Mole Ratios 2K(s) + Br2(l)  2KBr(s)

Chapter 11 Section 3 Limiting Reactants

Limiting and Excess Reactants The limiting reactant in the reaction limits the extent of the reaction and thereby determines the amount of product formed. A portion of all the other reactants remain after the reaction stops. Reactants left over when the reaction stops are excess reactants.

Determining the Limiting Reactant These problems are very similar to stoichiometry problems…they follow the same steps. In this case, you will be given two starting amounts and have to determine which reactant is limiting.

Example 1 If 200.0 g of sulfurs reacts with 100.0 g of chlorine, what mass of disulfide dichloride is formed? S8(l) + 4Cl2(g)  4S2Cl2(l)

Example 2 Determine the mass of P4O10 formed if 25.0 g of P4 and 50.0 g of O2 are combined. P4(s) + 5O2(g)  P4O10(s)