Proj. Motion guidelines

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Presentation transcript:

Proj. Motion guidelines horiz. & vert. motion are considered SEPARATELY horiz motion: not affected by acceleration vert motion: affected by acceleration due to gravity (-9.8 m/s2) Air resistance is ignored tup = tdown (only when take-off and landing height are the same) Vv at apex = 0

What is the stuntman's velocity, displacement, and acceleration while falling. Given: times at 1,2,3 sec Horizontal motion dh= vh (t) Vertical motion vf = vi + at vf2 = vi2 + 2ad d = vit + (1/2)at2 Time velocity displacement acceleration 0 s 1 s 2 s 3 s -9.8 m/s -4.9 m -9.8 m/s2 -9.8 m/s2 d = vit + (1/2)at2 vf = vi + at d = o + (1/2) (-9.8 m/s2) (1s)2 vf = o + (-9.8 m/s2) (1s) d = -4.9 m vf = -9.8 m/s

What is the stuntman's velocity displacement and acceleration while falling at seconds 0-3? Horizontal motion dh= vh (t) Vertical motion vf = vi + at vf2 = vi2 + 2ad d = vit + (1/2)at2 Time velocity displacement acceleration 0 s 1 s 2 s 3 s -9.8 m/s -4.9 m -9.8 m/s2 -9.8 m/s2 -19.6 m -19.6 m/s -29.4 m/s -44.1 m d = vit + (1/2)at2 vf = vi + at d = o + (1/2) (-9.8 m/s2) (1s)2 vf = o + (-9.8 m/s2) (1s) d = -4.9 m vf = -9.8 m/s

Bungee jumping Skippers Canyon, NZ

Bungee jumping Skippers Canyon, NZ

What was the vertical velocity at the instant the bungee began to lengthen? Given: -102 meter drop Vi = -3.0 m/s Horizontal motion dh= vh (t) Vertical motion vf = vi + at vf2 = vi2 + 2ad d = vit + (1/2)at2 vf2 = vi2 + 2ad vf2 = -3.02 + 2(-9.8)(-102) vf2 = 9 + 1999 vf = -44.81m/s

. Trampolinist goes up.. What is the time to peak and how high did they jump? Given: Vi = 10.5 m/s Horizontal motion dh= vh (t) Vertical motion vf = vi + at vf2 = vi2 + 2ad d = vit + (1/2)at2 d = vit + (1/2)at2 vf = vi + at d = (5.0 m/s) (.51 s) + (1/2) (-9.8 m/s2) (.51s)2 0 = 5.0 m/s + (-9.8 m/s2) (t) -5.0 m/s -9.8 m/s2 = 0.51 s d = 1.28 m

Long jumper: How high and how far did they go? Step 1: resolve net velocity 9.8 m/s cos 23.2° * 9.8m/s vh = 9.01 m/s Sin 23.2° * 9.8m/s vv = 3.86 m/s 23.2° Given: tup = tdn Step 3: dv Step 2: tup dv = vit + (1/2)at2 dv= (3.86 m/s) (.394 s) + (1/2) (-9.8 m/s2) (.394 s)2 vf = vi + at vf = 3.86 m/s + (-9.8 m/s2) (tup) dv= .76 m -3.86 m/s -9.8 m/s2 = .394 s

Long jumper: How high and how far did they go? Step 4: total time 9.8 m/s tup = tdn 23.2° Given: tup = tdn .394 s + .394 s = .788 s Step 5: dh dh= vh (t) Dh = 7.10 m (9.01 m/s) (.788 s) =