Chapter 12 Statistics 2012 Pearson Education, Inc.

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Presentation transcript:

Chapter 12 Statistics 2012 Pearson Education, Inc.

Chapter 12: Statistics 12.1 Visual Displays of Data 12.2 Measures of Central Tendency 12.3 Measures of Dispersion 12.4 Measures of Position 12.5 The Normal Distribution 2012 Pearson Education, Inc.

Measures of Central Tendency Section 12-2 Measures of Central Tendency 2012 Pearson Education, Inc.

Measures of Central Tendency Mean Median Mode Central Tendency from Stem-and-Leaf Displays Symmetry in Data Sets 2012 Pearson Education, Inc.

Measures of Central Tendency For a given set of numbers, it may be desirable to have a single number to serve as a kind of representative value around which all the numbers in the set tend to cluster, a kind of “middle” number or a measure of central tendency. Three such measures are discussed in this section. 2012 Pearson Education, Inc.

Mean The mean (more properly called the arithmetic mean) of a set of data items is found by adding up all the items and then dividing the sum by the number of items. (The mean is what most people associate with the word “average.”) The mean of a sample is denoted (read “x bar”), while the mean of a complete population is denoted (the lower case Greek letter mu). 2012 Pearson Education, Inc.

Mean The mean of n data items x1, x2,…, xn, is given by the formula We use the symbol for “summation,” (the Greek letter sigma). 2012 Pearson Education, Inc.

Example: Mean Number of Siblings Ten students in a math class were polled as to the number of siblings in their individual families and the results were: 3, 2, 2, 1, 3, 6, 3, 3, 4, 2. Find the mean number of siblings for the ten students. Solution The mean number of siblings is 2.9. 2012 Pearson Education, Inc.

Weighted Mean The weighted mean of n numbers x1, x2,…, xn, that are weighted by the respective factors f1, f2,…, fn is given by the formula 2012 Pearson Education, Inc.

Example: Grade Point Average In a common system for finding a grade-point average, an A grade is assigned 4 points, with 3 points for a B, 2 for C, and 1 for D. Find the grade-point average by multiplying the number of units for a course and the number assigned to each grade, and then adding these products. Finally, divide this sum by the total number of units. This calculation of a grade-point average in an example of a weighted mean. 2012 Pearson Education, Inc.

Example: Grade Point Average Find the grade-point average (weighted mean) for the grades below. Course Grade Points Units (credits) Math 4 (A) 5 History 3 (B) 3 Health 2 Art 2 (C) 2012 Pearson Education, Inc.

Example: Grade Point Average Solution Course Grade Pts Units (Grade pts)(units) Math 4 (A) 5 20 History 3 (B) 3 9 Health 2 8 Art 2 (C) 4 Grade-point average = 2012 Pearson Education, Inc.

Median Another measure of central tendency, which is not so sensitive to extreme values, is the median. This measure divides a group of numbers into two parts, with half the numbers below the median and half above it. 2012 Pearson Education, Inc.

Median To find the median of a group of items: Step 1 Rank the items. Step2 If the number of items is odd, the median is the middle item in the list. Step 3 If the number of items is even, the median is the mean of the two middle numbers. 2012 Pearson Education, Inc.

Example: Median Solution Ten students in a math class were polled as to the number of siblings in their individual families and the results were: 3, 2, 2, 1, 1, 6, 3, 3, 4, 2. Find the median number of siblings for the ten students. Solution In order: 1, 1, 2, 2, 2, 3, 3, 3, 4, 6 Median = (2+3)/2 = 2.5 2012 Pearson Education, Inc.

Position of the Median in a Frequency Distribution Position of median = Notice that this formula gives the position, and not the actual value. 2012 Pearson Education, Inc.

Example: Median for a Distribution Find the median for the distribution. Value 1 2 3 4 5 Frequency 6 8 Solution Position of median = The median is the 12th item, which is a 4. 2012 Pearson Education, Inc.

Mode The mode of a data set is the value that occurs the most often. Sometimes, a distribution is bimodal (literally, “two modes”). In a large distribution, this term is commonly applied even when the two modes do not have exactly the same frequency 2012 Pearson Education, Inc.

Example: Mode for a Set Solution Ten students in a math class were polled as to the number of siblings in their individual families and the results were: 3, 2, 2, 1, 3, 6, 3, 3, 4, 2. Find the mode for the number of siblings. Solution 3, 2, 2, 1, 3, 6, 3, 3, 4, 2 The mode for the number of siblings is 3. 2012 Pearson Education, Inc.

Example: Mode for Distribution Find the median for the distribution. Value 1 2 3 4 5 Frequency 6 8 Solution The mode is 5 since it has the highest frequency (8). 2012 Pearson Education, Inc.

Central Tendency from Stem-and-Leaf Displays We can calculate measures of central tendency from a stem-and-leaf display. The median and mode are easily identified when the “leaves” are ranked (in numerical order) on their “stems.” 2012 Pearson Education, Inc.

Example: Stem-and-Leaf Below is a stem-and-leaf display of some data. Find the median and mode. 1 5 6 2 0 7 8 9 9 3 6 6 7 7 4 0 2 2 2 3 6 5 1 6 8 8 Median Mode 2012 Pearson Education, Inc.

Symmetry in Data Sets The most useful way to analyze a data set often depends on whether the distribution is symmetric or non-symmetric. In a “symmetric” distribution, as we move out from a central point, the pattern of frequencies is the same (or nearly so) to the left and right. In a “non-symmetric” distribution, the patterns to the left and right are different. 2012 Pearson Education, Inc.

Some Symmetric Distributions 2012 Pearson Education, Inc.

Non-symmetric Distributions A non-symmetric distribution with a tail extending out to the left, shaped like a J, is called skewed to the left. If the tail extends out to the right, the distribution is skewed to the right. 2012 Pearson Education, Inc.

Some Non-symmetric Distributions 2012 Pearson Education, Inc.