Searching Graphs ORD SFO LAX DFW Spring 2007

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Searching Graphs ORD SFO LAX DFW 1843 802 1743 337 1233 Spring 2007 7/29/2018 3:16 AM Searching Graphs 1843 ORD SFO 802 1743 337 LAX 1233 DFW Spring 2007 Graphs

Depth-First Search Depth-first search (DFS) is a general technique for traversing a graph A DFS traversal of a graph G Visits all the vertices and edges of G Determines whether G is connected Computes the connected components of G Computes a spanning forest of G DFS on a graph with n vertices and m edges takes O(n + m ) time DFS can be further extended to solve other graph problems Find and report a path between two given vertices Find a cycle in the graph Spring 2007 Graphs

DFS Algorithm The algorithm uses a mechanism for setting and getting “labels” of vertices and edges Algorithm DFS(G, v) Input graph G and a start vertex v of G Output labeling of the edges of G in the connected component of v as discovery edges and back edges setLabel(v, VISITED) for all e  G.incidentEdges(v) if getLabel(e) = UNEXPLORED w  opposite(v,e) if getLabel(w) = UNEXPLORED setLabel(e, DISCOVERY) DFS(G, w) else setLabel(e, BACK) Algorithm DFS(G) Input graph G Output labeling of the edges of G as discovery edges and back edges for all u  G.vertices() setLabel(u, UNEXPLORED) for all e  G.edges() setLabel(e, UNEXPLORED) for all v  G.vertices() if getLabel(v) = UNEXPLORED DFS(G, v) Spring 2007 Graphs

Example unexplored vertex visited vertex unexplored edge B A C E A visited vertex unexplored edge discovery edge back edge D B A C E D B A C E Spring 2007 Graphs

Example (cont.) D B A C E D B A C E D B A C E D B A C E Spring 2007 Graphs

DFS and Maze Traversal The DFS algorithm is similar to a classic strategy for exploring a maze We mark each intersection, corner and dead end (vertex) visited We mark each corridor (edge ) traversed We keep track of the path back to the entrance (start vertex) by means of a rope (recursion stack) Spring 2007 Graphs

Properties of DFS Property 1 Property 2 DFS(G, v) visits all the vertices and edges in the connected component of v Property 2 The discovery edges labeled by DFS(G, v) form a spanning tree of the connected component of v D B A C E Spring 2007 Graphs

Proof of Property 1 Suppose (for contradiction) that at least one vertex s in v’s connected component is not visited. There is some path from v to s in G. Let w be first unvisited vertex on this path (w may be s) Since w is first unvisited vertex, it has a neighbor u that was visited. Spring 2007 Graphs

Proof of Property 1 But when visiting u, we must have considered edge (u,w), thus it cannot be correct that w is unvisited. Thus, there can be no unvisited vertices in the connected component of v. Spring 2007 Graphs

Proof of Property 2 Note that we only mark edges as discovery when we go to unvisited vertices. Thus we can never form a cycle with discovery edges. I.e. the discovery edges form a tree. This is a spanning tree because we visit each tree in the connected component of v Spring 2007 Graphs

Analysis of DFS Setting/getting a vertex/edge label takes O(1) time Each vertex is labeled twice once as UNEXPLORED once as VISITED Each edge is labeled twice once as DISCOVERY or BACK Method incidentEdges is called once for each vertex DFS runs in O(n + m) time provided the graph is represented by the adjacency list structure Recall that Sv deg(v) = 2m Spring 2007 Graphs

Path Finding We can specialize the DFS algorithm to find a path between two given vertices u and z We call DFS(G, u) with u as the start vertex We use a stack S to keep track of the path between the start vertex and the current vertex As soon as destination vertex z is encountered, we return the path as the contents of the stack Algorithm pathDFS(G, v, z) setLabel(v, VISITED) S.push(v) if v = z return S.elements() for all e  G.incidentEdges(v) if getLabel(e) = UNEXPLORED w  opposite(v,e) if getLabel(w) = UNEXPLORED setLabel(e, DISCOVERY) S.push(e) pathDFS(G, w, z) S.pop(e) else setLabel(e, BACK) S.pop(v) Spring 2007 Graphs

Cycle Finding Algorithm cycleDFS(G, v, z) setLabel(v, VISITED) S.push(v) for all e  G.incidentEdges(v) if getLabel(e) = UNEXPLORED w  opposite(v,e) S.push(e) if getLabel(w) = UNEXPLORED setLabel(e, DISCOVERY) pathDFS(G, w, z) S.pop(e) else T  new empty stack repeat o  S.pop() T.push(o) until o = w return T.elements() S.pop(v) We can specialize the DFS algorithm to find a simple cycle We use a stack S to keep track of the path between the start vertex and the current vertex As soon as a back edge (v, w) is encountered, we return the cycle as the portion of the stack from the top to vertex w Spring 2007 Graphs

Breadth-First Search L0 L1 L2 C B A E D F Spring 2007 Graphs Graphs 7/29/2018 3:16 AM Breadth-First Search C B A E D L0 L1 F L2 Spring 2007 Graphs

Breadth-First Search Breadth-first search (BFS) is a general technique for traversing a graph A BFS traversal of a graph G Visits all the vertices and edges of G Determines whether G is connected Computes the connected components of G Computes a spanning forest of G BFS on a graph with n vertices and m edges takes O(n + m ) time BFS can be further extended to solve other graph problems Find and report a path with the minimum number of edges between two given vertices Find a simple cycle, if there is one Spring 2007 Graphs

BFS Algorithm Algorithm BFS(G, s) L0  new empty sequence L0.insertLast(s) setLabel(s, VISITED) i  0 while Li.isEmpty() Li +1  new empty sequence for all v  Li.elements() for all e  G.incidentEdges(v) if getLabel(e) = UNEXPLORED w  opposite(v,e) if getLabel(w) = UNEXPLORED setLabel(e, DISCOVERY) setLabel(w, VISITED) Li +1.insertLast(w) else setLabel(e, CROSS) i  i +1 The algorithm uses a mechanism for setting and getting “labels” of vertices and edges Algorithm BFS(G) Input graph G Output labeling of the edges and partition of the vertices of G for all u  G.vertices() setLabel(u, UNEXPLORED) for all e  G.edges() setLabel(e, UNEXPLORED) for all v  G.vertices() if getLabel(v) = UNEXPLORED BFS(G, v) Spring 2007 Graphs

Example unexplored vertex visited vertex unexplored edge C B A E D L0 L1 F A unexplored vertex A visited vertex unexplored edge discovery edge cross edge L0 L0 A A L1 L1 B C D B C D E F E F Spring 2007 Graphs

Example (cont.) L0 L1 L0 L1 L2 L0 L1 L2 L0 L1 L2 C B A E D F C B A E D Spring 2007 Graphs

Example (cont.) L0 L1 L2 L0 L1 L2 L0 L1 L2 C B A E D F A B C D E F C B Spring 2007 Graphs

Properties Notation Property 1 Property 2 Property 3 Gs: connected component of s Property 1 BFS(G, s) visits all the vertices and edges of Gs Property 2 The discovery edges labeled by BFS(G, s) form a spanning tree Ts of Gs Property 3 For each vertex v in Li The path of Ts from s to v has i edges Every path from s to v in Gs has at least i edges (i.e. the path above is the shortest possible) A B C D E F L0 A L1 B C D L2 E F Spring 2007 Graphs

Analysis Setting/getting a vertex/edge label takes O(1) time Each vertex is labeled twice once as UNEXPLORED once as VISITED Each edge is labeled twice once as DISCOVERY or CROSS Each vertex is inserted once into a sequence Li Method incidentEdges is called once for each vertex BFS runs in O(n + m) time provided the graph is represented by the adjacency list structure Recall that Sv deg(v) = 2m Spring 2007 Graphs

Applications We can specialize the BFS traversal of a graph G to solve the following problems in O(n + m) time Compute the connected components of G Compute a spanning forest of G Find a simple cycle in G, or report that G is a forest Given two vertices of G, find a path in G between them with the minimum number of edges, or report that no such path exists Spring 2007 Graphs

DFS vs. BFS Applications DFS BFS DFS BFS Spanning forest, connected components, paths, cycles  Shortest paths Biconnected components C B A E D L0 L1 F L2 A B C D E F DFS BFS Spring 2007 Graphs

DFS vs. BFS (cont.) Back edge (v,w) Cross edge (v,w) DFS BFS w is an ancestor of v in the tree of discovery edges Cross edge (v,w) w is in the same level as v or in the next level in the tree of discovery edges C B A E D L0 L1 F L2 A B C D E F DFS BFS Spring 2007 Graphs