Chapter 5 Section 3.

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Presentation transcript:

Chapter 5 Section 3

Polynomial Functions, Graphs and Composition 5.3 Polynomial Functions, Graphs and Composition Recognize and evaluate polynomial functions. Use a polynomial function to model data. Add and subtract polynomial functions. Find the composition of functions. Graph basic polynomial functions.

Use a polynomial function to model data. Objective 2 Use a polynomial function to model data. Slide 5.3- 3

Add and subtract polynomial functions. The operations of addition, subtraction, multiplication, and division are also defined for functions. For example, businesses use the equation “profit equals revenue minus cost,” written in function notation as P (x) = R (x) – C (x) where x is the number of items produced and sold. Profit function Revenue function Cost function Slide 5.3- 4

Adding and Subtracting Functions Add and subtract polynomial functions. Adding and Subtracting Functions If f (x) and g (x) define functions, then (f + g)(x) = f(x) + g(x) Sum function and (f – g)(x) = f(x) – g(x). Difference function In each case, the domain of the new function is the intersection of the domains of f (x) and g (x). Slide 5.3- 5

(f + g)(x) = f(x) + g(x) = (3x2 + 8x – 6) + (–4x2 + 4x – 8) CLASSROOM EXAMPLE 3 Adding and Subtracting Functions For f(x) = 3x2 + 8x – 6 and g(x) = –4x2 + 4x – 8, find each of the following. (f + g)(x) = f(x) + g(x) = (3x2 + 8x – 6) + (–4x2 + 4x – 8) = –x2 + 12x – 14 (f – g)(x) = f(x) – g(x) = (3x2 + 8x – 6)  (–4x2 + 4x – 8) = 3x2 + 8x – 6 + 4x2 – 4x + 8 = 7x2 + 4x + 2 Solution: Slide 5.3- 6

(f + g)(x) and (f + g)(–1) (f – g)(x) and (f – g)(1) (f + g)(x) CLASSROOM EXAMPLE 4 Adding and Subtracting Functions For f(x) = 18x2 – 24x and g(x) = 3x, find each of the following. (f + g)(x) and (f + g)(–1) (f – g)(x) and (f – g)(1) (f + g)(x) = f(x) + g(x) = 18x2 – 24x + 3x = 18x2 – 21x (f + g)(–1) = f(−1) + g(−1) = [18(–1)2 – 24(–1)] + 3(–1) = [18 + 24] – 3 = 39 Solution: (f – g)(x) = f(x) – g(x) = 18x2 – 24x – 3x = 18x2 – 27x (f – g)(1) = f(1) – g(1) = [18(1)2 – 24(1)] – 3(1) = [18 – 24] – 3 = – 9 Slide 5.3- 7

Find the composition of functions. Objective 4 Find the composition of functions. Slide 5.3- 8

Composition of Functions Find the composition of functions. Composition of Functions If f and g are functions, then the composite function, or composition, of g and f is defined by for all x in the domain of f such that f (x) is in the domain of g. Slide 5.3- 9

Evaluating a Composite Function CLASSROOM EXAMPLE 5 Evaluating a Composite Function Let f(x) = x – 4 and g(x) = x2. Find Evaluate the “inside” function value first. Solution: Now evaluate the “outside” function. Slide 5.3- 10

Finding Composite Functions CLASSROOM EXAMPLE 6 Finding Composite Functions Let f(x) = 3x + 6 and g(x) = x3. Find the following. Solution: Slide 5.3- 11

Graph basic polynomial functions. Objective 5 Graph basic polynomial functions. Slide 5.3- 12

Graph basic polynomial functions. The simplest polynomial function is the identity function, defined by f(x) = x and graphed below. This function pairs each real number with itself. The domain (set of x-values) is all real numbers, (, ). The range (set of y-values) is also (, ). x f(x) = x 2 1 1 2 Slide 5.3- 13

Graph basic polynomial functions. Another polynomial function, defined by f(x) = x2 and graphed below, is the squaring function. For this function, every real number is paired with its square. The graph of the squaring function is a parabola. The domain is all real numbers, (, ). The range is [0, ). x f(x) = x2 2 4 1 1 2 Slide 5.3- 14

Graph basic polynomial functions. The cubing function is defined by f(x) = x3 and graphed below. This function pairs every real number with its cube. The domain and range are both (, ). x f(x) = x3 2 8 1 1 2 8 Slide 5.3- 15

Graphing Variations of Polynomial Functions CLASSROOM EXAMPLE 7 Graphing Variations of Polynomial Functions Graph f(x) = –2x2. Give the domain and range. Solution: x f(x) = –2x2 2 8 1 1 –2 2 –8 Domain Range The domain is (, ). The range is (, 0]. Slide 5.3- 16