6.1 Alternating current and power

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Presentation transcript:

6.1 Alternating current and power AC is used for power distribution because the peak voltage can be easily changed using transformers * An AC repeatedly reverses its direction * In one cycle the charge carriers move in one direction then the other. AC measurements * Mains frequency is 50 Hz , one cycle lasts 1/50 sec = 0.02 sec = time period T Frequency: f (Hz) f = 1 T Peak value Peak to peak value

6.1 Alternating current and power AC is used for power distribution because the peak voltage can be easily changed using transformers * An AC repeatedly reverses its direction * In one cycle the charge carriers move in one direction then the other. AC measurements * Mains frequency is 50 Hz , one cycle lasts 1/50 sec = 0.02 sec = time period T Frequency: f (Hz) f = 1 T Peak value Peak to peak value

6.1 Alternating current and power AC is used for power distribution because the peak voltage can be easily changed using transformers * An AC repeatedly reverses its direction * In one cycle the charge carriers move in one direction then the other. AC measurements * Mains frequency is 50 Hz , Frequency: f (Hz) Peak value Peak to peak value

6.1 Alternating current and power AC is used for power distribution because the peak voltage can be easily changed using transformers * An AC repeatedly reverses its direction * In one cycle the charge carriers move in one direction then the other. AC measurements * Mains frequency is 50 Hz , Frequency: f (Hz)

6.1 Alternating current and power AC is used for power distribution because the peak voltage can be easily changed using transformers * An AC repeatedly reverses its direction * In one cycle the charge carriers move in one direction then the other. AC measurements * Mains frequency is 50 Hz , Frequency: f (Hz) Peak value

6.1 Alternating current and power AC is used for power distribution because the peak voltage can be easily changed using transformers * An AC repeatedly reverses its direction * In one cycle the charge carriers move in one direction then the other. AC measurements * Mains frequency is 50 Hz , Frequency: f (Hz) Peak value Peak to peak value

6.1 Alternating current and power * Mains frequency is 50 Hz , one cycle lasts 1/50 sec = 0.02 sec = time period T One cycle f = 1 T Peak value Peak to peak value

P = I V = I2R R = resistance of heater 6.1 Alternating current and power The heating effect of an alternating current: varies according to the square of the current P = I V = I2R R = resistance of heater At peak current Io maximum power is supplied = Io2 R At zero current zero power is supplied Equal areas above and below mean value also Av value of a sin 2 plot = 1/2 Mean power supplied = ½ Io2 R

P = I V = I2R R = resistance of heater 6.1 Alternating current and power The heating effect of an alternating current: varies according to the square of the current P = I V = I2R R = resistance of heater At peak current Io maximum power is supplied = Io2 R At zero current zero power is supplied Equal areas above and below mean value also Av value of a sin 2 plot = 1/2 Mean power supplied = ½ Io2 R

P = I V = I2R R = resistance of heater 6.1 Alternating current and power The heating effect of an alternating current: varies according to the square of the current P = I V = I2R R = resistance of heater At peak current Io maximum power is supplied = Io2 R At zero current zero power is supplied Equal areas above and below mean value also Av value of a sin 2 plot = 1/2 Mean power supplied = ½ Io2 R

P = I V = I2R R = resistance of heater 6.1 Alternating current and power The heating effect of an alternating current: varies according to the square of the current P = I V = I2R R = resistance of heater At peak current Io maximum power is supplied = Io2 R At zero current zero power is supplied Equal areas above and below mean value also Av value of a sin 2 plot = 1/2 Mean power supplied = ½ Io2 R

P = I V = I2R R = resistance of heater 6.1 Alternating current and power The heating effect of an alternating current: varies according to the square of the current P = I V = I2R R = resistance of heater At peak current Io maximum power is supplied = Io2 R At zero current zero power is supplied Equal areas above and below mean value Mean power supplied = ½ Io2 R

P = I V = I2R R = resistance of heater 6.1 Alternating current and power The heating effect of an alternating current: varies according to the square of the current P = I V = I2R R = resistance of heater At peak current Io maximum power is supplied = Io2 R At zero current zero power is supplied Equal areas above and below mean value also Av value of a sin 2 plot = 1/2 Mean power supplied = ½ Io2 R

6.1 Alternating current and power

6.1 Alternating current and power

6.1 Alternating current and power

6.1 Alternating current and power

6.1 Alternating current and power

6.1 Alternating current and power

The mean power supplied to a resistor: 6.1 Alternating current and power The mean power supplied to a resistor:

The mean power supplied to a resistor: 6.1 Alternating current and power The mean power supplied to a resistor:

6.1 Alternating current and power

6.1 Alternating current and power