Tuesday September 22, 2015 Algebra I.

Slides:



Advertisements
Similar presentations
An equation is a mathematical statement that two expressions are equal. A solution of an equation is a value of the variable that makes the equation true.
Advertisements

Solving Linear Equations
Solving One Step Equations using inverse operations. 2-2
ALGEBRA EQUATIONS ► Goals for solving equations – Isolate the variable, and use the inverse operations to undo the operation performed on the variable.
ALGEBRAIC EQUATIONS. EQUATIONS AND SOLUTIONS  A correct equation is like a balance scale.  In order to determine if a given value for a variable is.
An equation is a mathematical statement that two expressions are equal. A solution of an equation is a value of the variable that makes the equation true.
Warm Up  – Evaluate.  (0.29)
4. ; $22, $11, $10 5. C6. F7. B An equation is a mathematical statement that two expressions are equal. A solution of an equation is a value of the variable.
The Multiplication Principle of Equality 2.3a 1.Solve linear equations using the multiplication principle. 2.Solve linear equations using both the addition.
Holt Algebra Solving Two-Step and Multi-Step Equations 2-3 Solving Two-Step and Multi-Step Equations Holt Algebra 1 Warm Up Warm Up Lesson Quiz Lesson.
One step equations using multiplication and division.
Section 2.2 More about Solving Equations. Objectives Use more than one property of equality to solve equations. Simplify expressions to solve equations.
4. ; $22, $11, $10 5. C6. F7. B An equation is a mathematical statement that two expressions are equal. A solution of an equation is a value of the variable.
Holt McDougal Algebra 1 Solving Two-Step and Multi-Step Equations Warm Up Evaluate each expression –3(–2) 2. 3(–5 + 7) – 4(7 – 5) Simplify.
Solving Two-Step and 3.1 Multi-Step Equations Warm Up
Solving equations with Rational Coefficients
An equation is a mathematical statement that two expressions are equal. A solution of an equation is a value of the variable that makes the equation true.
Warm Up Simplify each expression. 1.10c + c 2. 5m + 2(2m – 7) 11c 9m – 14.
Lesson 8.1. » A statement where two mathematical expressions are. » Think of an equation as a balance scale or teeter-totter. The left side must always.
Solving Two-Step and Multi-Step Equations Warm Up Lesson Presentation
Holt McDougal Algebra Solving Equations by Adding or Subtracting Warm Up Evaluate. 1.   (0.29) Give the opposite of each number.
Opener (5 + 6) • 2 a + (b + c) + (d • e) 18k x2 + 5x + 4y + 7
1.4 Solving Equations.
Solving Two-Step and Multi-Step Equations Warm Up Lesson Presentation
3. 3 Solving Equations Using Addition or Subtraction 3
Solving Equations A-REI.B.3:Solving equations with a variable on one side, using inverse operations.
6-3: Solving Equations with variables on both sides of the equal sign
Quiz  .
Graphing and Solving Inequalities
Linear Equations Sections 10.1 – 10.3.
Solving Multi-Step Equations
LESSON 1.11 SOLVING EQUATIONS
Properties of Equality and Solving One-Step Equations
2-1 Solving 1 step equations
Preview Warm Up California Standards Lesson Presentation.
Solving 2 Step Equations.
Solving Equations with Variables on Both Sides 1-5
Solving Multi-Step Equations
Solving Two-Step and 1-4 Multi-Step Equations Warm Up
Solving Two-Step and 1-4 Multi-Step Equations Warm Up
Solving 1-Step Integer Equations
Solving Two- Step Equations
Objective Solve equations in one variable that contain more than one operation.
Solving Equations with the Variable on Both Sides
Solving Equations by 2-1 Adding or Subtracting Warm Up
Solving Algebraic Equations
Example 2 4 m 8 m 5m 12 m x y.
1.3 Solving Linear Equations
Solving Two-Step Equations Lesson 2-2 Learning goal.
Algebra /19-20/16 EQ: How do I solve Multi-Step Equations?
Lesson Objective: I will be able to …
Objective Solve equations in one variable that contain more than one operation.
1.  2.  (0.29) Give the opposite of each number. 
Solving Equations Finding Your Balance
Objective translate verbal sentences into equations.
Warm Up Solve each equation. 1. 2x – 5 = –17 2. –6 14
Objective Solve equations in one variable that contain more than one operation.
Do Now 10/13/11 In your notebook, simplify the expressions below.
Multi-Step Inequalities
Solving Equations by 1-2 Adding or Subtracting Warm Up
Objective Solve equations in one variable that contain more than one operation.
Do Now 10/4/11 In your notebook, answer the following question:
Lesson 1.1 Objective: To solve equations using addition, subtraction, multiplication, and division Vocab: Inverse operations: Are operations that undo.
Objective 3.4 solve equations with variables on both sides.
10/3/11 In your notebook, answer completely the following:
Solving Equations.
Solving Equations by 2-1 Adding or Subtracting Warm Up
Involving One Operation
Chapter 3.2 and 3.3 – Solving One-Step Equations
Multi-Step equations with fractions and decimals
Presentation transcript:

Tuesday September 22, 2015 Algebra I

2.3 Multi-Step Equations Vocabulary: An equation is a mathematical statement that two expressions are equal. A solution of an equation is a value of the variable that makes the equation true. To find solutions, isolate the variable. A variable is isolated when it appears by itself on one side of an equation, and not at all on the other side.

Inverse Operations Operation Inverse Operation Isolate a variable by using inverse operations which "undo" operations on the variable. An equation is like a balanced scale. To keep the balance, perform the same operation on both sides. Inverse Operations Operation Inverse Operation Addition Subtraction Subtraction Addition

Inverse Operations Operation Inverse Operation Solving an equation that contains multiplication or division is similar to solving an equation that contains addition or subtraction. Use inverse operations to undo the operations on the variable. Inverse Operations Operation Inverse Operation Multiplication Division Division Multiplication

-2(x-1)+1=5 Steps to Solve: Simplify the expression on each side. Use inverse operations in reverse PEMDAS order. (undo addition/subtraction) (undo multiplication/division) -Always check your answer!

Example 2: Solve -2(x-1)+1=5 . -2x+2+1 = 5 Simplify each side. -2x + 3 = 5 –3 – 3 Undo addition by 3. Subtract 3 from both sides. -2x = 2 -2 Undo multiplication by -2. Divide both sides by -2. x= -1

Example 3: Solve 10y – (4y + 8) = –20 10y + (–1)(4y + 8) = –20 Write subtraction as addition of the opposite. 10y + (–1)(4y + 8) = –20 10y + (–1)(4y) + (–1)( 8) = –20 Distribute –1 on the left side. 10y – 4y – 8 = –20 Simplify. 6y – 8 = –20 Combine like terms. + 8 + 8 Since 8 is subtracted from 6y, add 8 to both sides to undo the subtraction. 6y = –12 6 6 6y = –12 Since y is multiplied by 6, divide both sides by 6 to undo the multiplication. y = –2

Example 4: a. If 5t – 2 = –32, find the value of 3t+10 5t – 2 = –32 First t is multiplied by 5. Then 2 is subtracted. Work backward: Add 2 to both sides. + 2 + 2 5t = –30 Since t is multiplied by 5, divide both sides by 5 to undo the multiplication. 5t = –30 5 t = –6 3t+10 = 3(–6) + 10 = -18 +10 = -8

Example 5: Solve 8x – 21 + 5x = –15. 8x – 21 – 5x = –15 8x – 5x – 21 = –15 3x – 21 = –15 Combine like terms. + 21 +21 Since 21 is subtracted from 3x, add 21 to both sides to undo the subtraction. 3x = 6 Since x is multiplied by 3, divide both sides by 3 to undo the multiplication. x = 2

You Try: Example 6 Solve 4(x – 2) + 2x = 40 4(x – 2) + 2x = 40 Distribute 4 on the left side. 4x – 8 + 2x = 40 Simplify. 4x + 2x – 8 = 40 Commutative Property of Addition. 6x – 8 = 40 Combine like terms. + 8 + 8 Since 8 is subtracted from 6x, add 8 to both sides to undo the subtraction. 6x = 48 6 6 6x = 48 Since x is multiplied by 6, divide both sides by 6 to undo the multiplication. x = 8

2.3 Practice B/C Define your variables, write an equation, and solve. Write your solution in a complete sentence. 6.The two angles shown form a right angle. Write and solve an equation to find the value of x.    

Work on Practice 2.3 B Don’t forget to show check steps for each problem!

7. For her cellular phone service, Vera pays $32 a month, plus $0 7. For her cellular phone service, Vera pays $32 a month, plus $0.75 for each minute over the allowed minutes in her plan. Vera received a bill for $47 last month. For how many minutes did she use her phone beyond the allowed minutes?

You try: Example 4 - Clearing Fractions First! Solve . Multiply by the LCD to clear the fractions. Multiply both sides by 12, the LCD of the fractions. Distribute 12 on the left side. 8r + 9 = 7 Simplify. Since 9 is added to 8r, subtract 9 from both sides to undo the addition. –9 –9 8r = –2

You Try: Example 4 Continued Solve . 8r = –2 Since r is multiplied by 8, divide both sides by 8 to undo the multiplication. 8 8

Example 3: Clearing Fractions First! Solve . Multiply by the LCD to clear the fractions. Multiply both sides by 24, the LCD of the fractions. Distribute 24 on the left side. Simplify. 3y – 18 = 14 Since 18 is subtracted from 3y, add 18 to both sides to undo the subtraction. +18 +18 3y = 32

You Try: Example 5 Continued Solve . 4x = 55 Simplify. Since 4 is multiplied by x, divide both sides by 4 to undo the multiplication. 4 4

Method 2 Multiply by the LCD to clear the fractions. You Try: Example 5 Solve . Method 2 Multiply by the LCD to clear the fractions. Multiply both sides by 10, the LCD of the fractions. Distribute 10 on the left side. 4x – 5 = 50 Simplify. + 5 + 5 Since 5 is subtracted from 4x, add 5 to both sides to undo the subtraction. 4x = 55

Equations that are more complicated may have to be simplified before they can be solved. You may have to… use the Distributive Property and/or combine like terms before you begin using inverse operations.