Question 1: An article is purchased for Rs. 450 and sold for Rs. 500. Find the gain percent. STD-7,Sub-MATHS,CH-4,Day-3 Gajwani Schools & Colleges

Solution: Gain = SP – CP = 500 – 450 = 50. STD-7,Sub-MATHS,CH-4,Day-3 Gajwani Schools & Colleges

Question 2: A man sold a fan for Rs. 465. Find the cost price if he incurred a loss of 7%. STD-7,Sub-MATHS,CH-4,Day-3 Gajwani Schools & Colleges

Therefore, the cost price of the fan = (100/93)*465 = Rs. 500 Solution: CP = [100 / (100 – Loss %)] * SP Therefore, the cost price of the fan = (100/93)*465 = Rs. 500 STD-7,Sub-MATHS,CH-4,Day-3 Gajwani Schools & Colleges

Question 3: In a transaction, the profit percentage is 80% of the cost. If the cost further increases by 20% but the selling price remains the same, how much is the decrease in profit percentage? STD-7,Sub-MATHS,CH-4,Day-3 Gajwani Schools & Colleges

Then Profit = Rs. 80 and selling price = Rs. 180. Solution: Let us assume CP = Rs. 100. Then Profit = Rs. 80 and selling price = Rs. 180. The cost increases by 20% → New CP = Rs. 120, SP = Rs. 180. Profit % = 60/120 * 100 = 50%. Therefore, Profit decreases by 30%. STD-7,Sub-MATHS,CH-4,Day-3 Gajwani Schools & Colleges

Question 4: A man bought some toys at the rate of 10 for Rs. 40 and sold them at 8 for Rs. 35. Find his gain or loss percent. STD-7,Sub-MATHS,CH-4,Day-3 Gajwani Schools & Colleges

Cost price of 10 toys = Rs. 40 → CP of 1 toy = Rs. 4. Solution: Cost price of 10 toys = Rs. 40 → CP of 1 toy = Rs. 4. Selling price of 8 toys = Rs. 35 → SP of 1 toy = Rs. 35/8 Therefore, Gain = 35/8 – 4 = 3/8. Gain percent = (3/8)/4 * 100 = 9.375% STD-7,Sub-MATHS,CH-4,Day-3 Gajwani Schools & Colleges

Question 5: The cost price of 10 pens is the same as the selling price of n pens. If there is a loss of 40%, approximately what is the value of n? STD-7,Sub-MATHS,CH-4,Day-3 Gajwani Schools & Colleges

Let the price of each pen be Re. 1. Solution: Let the price of each pen be Re. 1. Then the cost price of n pens is Rs. n and the selling price of n pens is Rs. 10. Loss = n-10. Loss of 40% → (loss/CP)*100 = 40 Therefore, [(n-10)/n]*100 = 40 → n = 17 (approx) STD-7,Sub-MATHS,CH-4,Day-3 Gajwani Schools & Colleges

Question 6: A dishonest merchant sells his grocery using weights 15% less than the true weights and makes a profit of 20%. Find his total gain percentage. STD-7,Sub-MATHS,CH-4,Day-3 Gajwani Schools & Colleges

SP of 1 kg of bag = 120% of the true CP Solution: Let us consider 1 kg of grocery bag. Its actual weight is 85% of 1000 gm = 850 gm. Let the cost price of each gram be Re. 1. Then the CP of each bag = Rs. 850. SP of 1 kg of bag = 120% of the true CP Therefore, SP = 120/100 * 1000 = Rs. 1200 Gain = 1200 – 850 = 350 Hence Gain % = 350/850 * 100 = 41.17% STD-7,Sub-MATHS,CH-4,Day-3 Gajwani Schools & Colleges

Question 7: A man bought two bicycles for Rs. 2500 each. If he sells one at a profit of 5%, then how much should he sell the other so that he makes a profit of 20% on the whole? STD-7,Sub-MATHS,CH-4,Day-3 Gajwani Schools & Colleges

Let the other profit percent be x. Then, our equation looks like this. Solution: Before we start, it’s important to note here that it is not 15% to be added to 5% to make it a total of 20%. Let the other profit percent be x. Then, our equation looks like this. 105/100 * 2500 + [(100+x)/100] * 2500 = 120/100 * 5000 → x= 35. Hence, if he makes a profit of 35% on the second, it comes to a total of 20% profit on the whole. STD-7,Sub-MATHS,CH-4,Day-3 Gajwani Schools & Colleges

Question 8: A shopkeeper allows a discount of 10% on the marked price and still gains 17% on the whole. Find at what percent above the cost price did he mark his goods. STD-7,Sub-MATHS,CH-4,Day-3 Gajwani Schools & Colleges

Let the cost price be 100. Then SP = 117. Let the marked price be x. Solution: Let the cost price be 100. Then SP = 117. Let the marked price be x. So, 90% of x = 117 → x = 130. Therefore, he marked his goods 30% above the cost price. STD-7,Sub-MATHS,CH-4,Day-3 Gajwani Schools & Colleges

The marked price of the article and Question 9: A shopkeeper offers a discount of 20% on the selling price. On a special sale day, he offers an extra 25% off coupon after the first discount. If the article was sold for Rs. 3600, find The marked price of the article and The cost price if the shopkeeper still makes a profit of 80% on the whole after all discounts are applied. STD-7,Sub-MATHS,CH-4,Day-3 Gajwani Schools & Colleges

Let the marked price of the article be x. Solution: Let the marked price of the article be x. First a 20% discount was offered, on which another 25% discount was offered. So, 75% of 80% of x = 3600 75/100 * 80/100 * x = 3600 → x = 6000. So the article was marked at Rs. 6000. Cost price of the article = [100/(100+80)]*3600 = Rs. 2000. It is important to note here that this DOES NOT equal to a 45% discount on the whole. When different discounts are applied successively, they CANNOT be added. STD-7,Sub-MATHS,CH-4,Day-3 Gajwani Schools & Colleges