11.1 – Probability – Basic Concepts

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Presentation transcript:

11.1 – Probability – Basic Concepts The study of the occurrence of random events or phenomena. It does not deal with guarantees, but with the likelihood of an occurrence of an event. Experiment: - Any observation or measurement of a random phenomenon. Outcomes: - The possible results of an experiment. Sample Space: - The set of all possible outcomes of an experiment. Event: - A particular collection of possible outcomes from a sample space.

11.1 – Probability – Basic Concepts Example: If a single fair coin is tossed, what is the probability that it will land heads up? Sample Space: S = {h, t} Event of Interest: E = {h} P(heads) = P(E) = 1/2 The probability obtained is theoretical as no coin was actually flipped Theoretical Probability: number of favorable outcomes n(E) P(E) = = total number of outcomes n(S)

11.1 – Probability – Basic Concepts Example: A cup is flipped 100 times. It lands on its side 84 times, on its bottom 6 times, and on its top 10 times. What is the probability that it lands on it top? number of top outcomes 10 1 P(top) = = = total number of flips 100 10 The probability obtained is experimental or empirical as the cup was actually flipped. Empirical or Experimental Probability: number of times event E occurs P(E) ͌ number of times the experiment was performed

11.1 – Probability – Basic Concepts Example: There are 2,598,960 possible five-card hand in poker. If there are 36 possible ways for a straight flush to occur, what is the probability of being dealt a straight flush? number of possible straight flushes P(straight flush) = total number of five-card hands 36 = = 0.0000139 2,598,960 This probability is theoretical as no cards were dealt.

11.1 – Probability – Basic Concepts Example: A school has 820 male students and 835 female students. If a student is selected at random, what is the probability that the student would be a female? number of possible female students P(female) = total number of students 835 835 167 = = = 820 + 835 1655 331 P(female) = 0.505 This probability is theoretical as no experiment was performed.

11.1 – Probability – Basic Concepts The Law of Large Numbers As an experiment is repeated many times over, the experimental probability of the events will tend closer and closer to the theoretical probability of the events. Flipping a coin Spinner Rolling a die

11.1 – Probability – Basic Concepts Odds A comparison of the number of favorable outcomes to the number of unfavorable outcomes. Odds are used mainly in horse racing, dog racing, lotteries and other gambling games/events. Odds in Favor: number of favorable outcomes (A) to the number of unfavorable outcomes (B). A to B A : B Example: What are the odds in favor of rolling a 2 on a fair six-sided die? 1 : 5 What is the probability of rolling a 2 on a fair six-sided die? 1/6

11.1 – Probability – Basic Concepts Odds Odds against: number of unfavorable outcomes (B) to the number of favorable outcomes (A). B to A B : A Example: What are the odds against rolling a 2 on a fair six-sided die? 5 : 1 What is the probability against rolling a 2 on a fair six-sided die? 5/6

11.1 – Probability – Basic Concepts Odds Example: Two hundred tickets were sold for a drawing to win a new television. If you purchased 10 tickets, what are the odds in favor of you winning the television? 10 Favorable outcomes 200 – 10 = 190 Unfavorable outcomes 10 : 190 = 1 : 19 What is the probability of winning the television? 10/200 = 1/20 = 0.05

11.1 – Probability – Basic Concepts Converting Probability to Odds Example: The probability of rain today is 0.43. What are the odds of rain today?   P(rain) = 0.43 Of the 100 total outcomes, 43 are favorable for rain. Unfavorable outcomes: 100 – 43 = 57 The odds for rain today: 43 : 57 The odds against rain today: 57 : 43

11.1 – Probability – Basic Concepts Converting Odds to Probability Example: The odds of completing a college English course are 16 to 9. What is the probability that a student will complete the course? The odds for completing the course: 16 : 9 Favorable outcomes + unfavorable outcomes = total outcomes 16 + 9 = 25   P(completing the course) = = 0.64

Properties of Probability 11.2 – Probability – Events Involving “Not” and “Or” Properties of Probability 1. The probability of an event is between 0 and 1, inclusive. 2. The probability of an impossible event is 0. 3. The probability of a certain event is 1. Examples: Rolling a fair die, what is the probability of each event? a) The number 3 is rolled. P(3) = 1/6 b) A number not 3 is rolled. P(not 3) = 5/6 c) The number 9 is rolled. P(9) = 0 d) A number < 7 is rolled. P(< 7) = 1

11.2 – Probability – Events Involving “Not” and “Or” Probability of a Complement The probability that an event E will not occur is equal to one minus the probability that it will occur. P(not E) = 1 – P(E) P(E) = 1 – P(E) Other forms of the equation: P(E) + P(E) = 1 P(E) = 1 – P(E) What is the probability of not drawing an ace from a standard deck of 52 cards? P(not an ace) = 1 – P(ace) P(not an ace) = 1 – (4/52) P(not an ace) = 48/52 = 12/13

Mutually Exclusive Events 11.2 – Probability – Events Involving “Not” and “Or” Events Involving “Or” The probability that one event or another event will occur usually involves the union and addition. Mutually Exclusive Events Two events, A and B, are mutually exclusive events if they have no outcomes in common. Mutually exclusive events can not occur simultaneously Addition Rule of Probability (for A and B) If A and B are any two events, then P(A or B) = P(A) + P(B) – P(A and B) If A and B are mutually exclusive, then P(A or B) = P(A) + P(B)

11.2 – Probability – Events Involving “Not” and “Or” Examples: 1. What is the probability of drawing a king or a diamond from a standard deck of 52 cards? P(king or diamond) = P(K) + P(D) – P(K and D) = 4/52 + 13/52 – 1/52 = 16/52 = 4/13

Mutually exclusive events 11.2 – Probability – Events Involving “Not” and “Or” Examples: 2. What is the probability of a 2 or an odd number being rolled on a fair die? Mutually exclusive events P(2 or odd) = P(2) + P(odd) = 1/6 + 3/6 = 4/6 = 2/3