4-9 Isosceles and Equilateral Triangles Warm Up Lesson Presentation

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4-9 Isosceles and Equilateral Triangles Warm Up Lesson Presentation 4-7 Isosceles and Equilateral Triangles Warm Up Lesson Presentation Lesson Quiz Holt McDougal Geometry Holt Geometry

1. Find each angle measure. 4-7 Warm Up 1. Find each angle measure. True or False. If false explain. 2. Every equilateral triangle is isosceles. 3. Every isosceles triangle is equilateral. 60°; 60°; 60° True False; an isosceles triangle can have only two congruent sides.

Objectives Prove theorems about isosceles and equilateral triangles. 4-7 Objectives Prove theorems about isosceles and equilateral triangles. Apply properties of isosceles and equilateral triangles.

4-7 Recall that an isosceles triangle has at least two congruent sides. The congruent sides are called the legs. The vertex angle is the angle formed by the legs. The side opposite the vertex angle is called the base, and the base angles are the two angles that have the base as a side. 3 is the vertex angle. and are the base angles. 1 2

4-7

4-7 The Isosceles Triangle Theorem is sometimes stated as “Base angles of an isosceles triangle are congruent.” Reading Math

Example 1: Astronomy Application 4-7 Example 1: Astronomy Application The length of YX is 20 feet. Explain why the length of YZ is the same. The mYZX = 180 – 140, so mYZX = 40°. Since YZX  X, ∆XYZ is isosceles by the Converse of the Isosceles Triangle Theorem. Thus YZ = YX = 20 ft.

4-7 Check It Out! Example 1 If the distance from Earth to a star in September is 4.2  1013 km, what is the distance from Earth to the star in March? Explain. 4.2  1013; since there are 6 months between September and March, the angle measures will be approximately the same between Earth and the star. By the Converse of the Isosceles Triangle Theorem, the triangles created are isosceles, and the distance is the same.

Example 2A: Finding the Measure of an Angle 4-7 Example 2A: Finding the Measure of an Angle Find mF. mF = mD = x° Isosc. ∆ Thm. mF + mD + mA = 180 ∆ Sum Thm. Substitute the given values. x + x + 22 = 180 Simplify and subtract 22 from both sides. 2x = 158 Divide both sides by 2. x = 79 Thus mF = 79°

Example 2B: Finding the Measure of an Angle 4-7 Example 2B: Finding the Measure of an Angle Find mG. mJ = mG Isosc. ∆ Thm. Substitute the given values. (x + 44) = 3x Simplify x from both sides. 44 = 2x Divide both sides by 2. x = 22 Thus mG = 22° + 44° = 66°.

4-7 Check It Out! Example 2A Find mH. Thus mH = 66°

4-7 Check It Out! Example 2B Find mN. mP = mN Isosc. ∆ Thm. Substitute the given values. (8y – 16) = 6y Subtract 6y and add 16 to both sides. 2y = 16 Divide both sides by 2. y = 8 Thus mN = 6(8) = 48°.

4-7 The following corollary and its converse show the connection between equilateral triangles and equiangular triangles.

4-7

Example 3A: Using Properties of Equilateral Triangles 4-7 Example 3A: Using Properties of Equilateral Triangles Find the value of x. ∆LKM is equilateral. Equilateral ∆  equiangular ∆ The measure of each  of an equiangular ∆ is 60°. (2x + 32) = 60 2x = 28 Subtract 32 both sides. x = 14 Divide both sides by 2.

Example 3B: Using Properties of Equilateral Triangles 4-7 Example 3B: Using Properties of Equilateral Triangles Find the value of y. ∆NPO is equiangular. Equiangular ∆  equilateral ∆ Definition of equilateral ∆. 5y – 6 = 4y + 12 Subtract 4y and add 6 to both sides. y = 18

4-7 Check It Out! Example 3 Find the value of JL. ∆JKL is equiangular. Equiangular ∆  equilateral ∆ Definition of equilateral ∆. 4t – 8 = 2t + 1 Subtract 4y and add 6 to both sides. 2t = 9 t = 4.5 Divide both sides by 2. Thus JL = 2(4.5) + 1 = 10.

4-7 A coordinate proof may be easier if you place one side of the triangle along the x-axis and locate a vertex at the origin or on the y-axis. Remember!

Draw a diagram and place the coordinates as shown. 4-7 Check It Out! Example 4 What if...? The coordinates of isosceles ∆ABC are A(0, 2b), B(-2a, 0), and C(2a, 0). X is the midpoint of AB, and Y is the midpoint of AC. Prove XY is half of BC. x A(0, 2b) B(–2a, 0) C(2a, 0) y X Y Z Proof: Draw a diagram and place the coordinates as shown.

Check It Out! Example 4 Continued 4-7 Check It Out! Example 4 Continued x A(0, 2b) B(–2a, 0) C(2a, 0) y X Y Z

Check It Out! Example 4 Continued 4-7 Check It Out! Example 4 Continued What do we need to know to find the distance of XY? x A(0, 2b) B(–2a, 0) C(2a, 0) y X Y Z We need to know the coordinates (-a,b) and (a,b)

Check It Out! Example 4 Continued 4-7 Check It Out! Example 4 Continued x A(0, 2b) B(–2a, 0) C(2a, 0) y X Y Z

Check It Out! Example 4 Continued 4-7 Check It Out! Example 4 Continued x A(0, 2b) B(–2a, 0) C(2a, 0) y X Y Z

4-7 Lesson Quiz: Part I Find each angle measure. 1. mR 2. mP Find each value. 3. x 4. y 5. x 28° 124° 6 20 26°

4-7 Lesson Quiz: Part II 6. The vertex angle of an isosceles triangle measures (a + 15)°, and one of the base angles measures 7a°. Find a and each angle measure. a = 11; 26°; 77°; 77°