The Hardware/Software Interface CSE351 Winter 2013

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Presentation transcript:

The Hardware/Software Interface CSE351 Winter 2013 Buffer Overflow

Buffer Overflow Buffer overflows are possible because C doesn’t check array boundaries Buffer overflows are dangerous because buffers for user input are often stored on the stack Probably the most common type of security vulnerability Today we’ll go over: Address space layout Input buffers on the stack Overflowing buffers and injecting code Defenses against buffer overflows Winter 2013 Buffer Overflow

IA32 Linux Memory Layout Stack Heap Data Text not drawn to scale FF Runtime stack (8MB limit) Heap Dynamically allocated storage Allocated by malloc(), calloc(), new() Data Statically allocated data Read-only: string literals Read/write: global arrays and variables Text Executable machine instructions Read-only 8MB The segment between addresses 0x00… and 0x08… is where shared libraries are mapped into the address space on IA32, I think. Heap Data Upper 2 hex digits = 8 bits of address Text 08 00 Winter 2013 Buffer Overflow

Memory Allocation Example not drawn to scale Memory Allocation Example FF Stack char big_array[1<<24]; /* 16 MB */ char huge_array[1<<28]; /* 256 MB */ int beyond; char *p1, *p2, *p3, *p4; int useless() { return 0; } int main() { p1 = malloc(1 <<28); /* 256 MB */ p2 = malloc(1 << 8); /* 256 B */ p3 = malloc(1 <<28); /* 256 MB */ p4 = malloc(1 << 8); /* 256 B */ /* Some print statements ... */ } Heap Data Text Where does everything go? 08 00 Winter 2013 Buffer Overflow

IA32 Example Addresses address range ~232 not drawn to scale FF Stack $esp 0xffffbcd0 p3 0x65586008 p1 0x55585008 p4 0x1904a110 p2 0x1904a008 &p2 0x18049760 beyond 0x08049744 big_array 0x18049780 huge_array 0x08049760 main() 0x080483c6 useless() 0x08049744 final malloc() 0x006be166 80 Heap Data malloc() is dynamically linked address determined at runtime Text 08 00 Winter 2013 Buffer Overflow

Internet Worm These characteristics of the traditional IA32 Linux memory layout provide opportunities for malicious programs Stack grows “backwards” in memory Data and instructions both stored in the same memory November, 1988 Internet Worm attacks thousands of Internet hosts. How did it happen? The Internet Worm was based on stack buffer overflow exploits! Many Unix functions do not check argument sizes Allows target buffers to overflow http://en.wikipedia.org/wiki/Morris_worm Winter 2013 Buffer Overflow

String Library Code Implementation of Unix function gets() What could go wrong in this code? /* Get string from stdin */ char *gets(char *dest) { int c = getchar(); char *p = dest; while (c != EOF && c != '\n') { *p++ = c; c = getchar(); } *p = '\0'; return dest; Winter 2013 Buffer Overflow

String Library Code Implementation of Unix function gets() No way to specify limit on number of characters to read Similar problems with other Unix functions strcpy: Copies string of arbitrary length scanf, fscanf, sscanf, when given %s conversion specification /* Get string from stdin */ char *gets(char *dest) { int c = getchar(); char *p = dest; while (c != EOF && c != '\n') { *p++ = c; c = getchar(); } *p = '\0'; return dest; The man page for gets(3) now says “BUGS: Never use gets().” Winter 2013 Buffer Overflow

Vulnerable Buffer Code /* Echo Line */ void echo() { char buf[4]; /* Way too small! */ gets(buf); puts(buf); } int main() { printf("Type a string:"); echo(); return 0; } unix>./bufdemo Type a string:1234567 1234567 unix>./bufdemo Type a string:12345678 Segmentation Fault unix>./bufdemo Type a string:123456789ABC Segmentation Fault Winter 2013 Buffer Overflow

Buffer Overflow Disassembly 080484f0 <echo>: 80484f0: 55 push %ebp 80484f1: 89 e5 mov %esp,%ebp 80484f3: 53 push %ebx 80484f4: 8d 5d f8 lea 0xfffffff8(%ebp),%ebx 80484f7: 83 ec 14 sub $0x14,%esp 80484fa: 89 1c 24 mov %ebx,(%esp) 80484fd: e8 ae ff ff ff call 80484b0 <gets> 8048502: 89 1c 24 mov %ebx,(%esp) 8048505: e8 8a fe ff ff call 8048394 <puts@plt> 804850a: 83 c4 14 add $0x14,%esp 804850d: 5b pop %ebx 804850e: c9 leave 804850f: c3 ret 0xfffffffc = -4 0xfffffff8 = -8 Why subtract 20 bytes from %esp? So that after call instruction, echo’s stack frame will occupy 4 + 4 + 20 + 4 = 32 bytes (16-byte aligned) 80485f2: e8 f9 fe ff ff call 80484f0 <echo> 80485f7: 8b 5d fc mov 0xfffffffc(%ebp),%ebx 80485fa: c9 leave 80485fb: 31 c0 xor %eax,%eax 80485fd: c3 ret Winter 2013 Buffer Overflow

Buffer Overflow Stack Before call to gets Stack Frame for main /* Echo Line */ void echo() { char buf[4]; /* Way too small! */ gets(buf); puts(buf); } Return Address Saved %ebp %ebp Saved %ebx Why subtract 20 bytes from %esp? So that after call instruction, echo’s stack frame will occupy 4 + 4 + 20 + 4 = 32 bytes (16-byte aligned) [3] [2] [1] [0] buf echo: pushl %ebp # Save %ebp on stack movl %esp, %ebp pushl %ebx # Save %ebx leal -8(%ebp),%ebx # Compute buf as %ebp-8 subl $20, %esp # Allocate stack space movl %ebx, (%esp) # Push buf addr on stack call gets # Call gets . . . buf Winter 2013 Buffer Overflow

Buffer Overflow Stack Example Before call to gets Before call to gets 0xffffc658 Stack Frame for main Stack Frame for main Return Address f7 85 04 08 Saved %ebp 0xfffffffc = -4 58 c6 ff ff 0xffffc638 Saved %ebx Saved %ebx [3] [2] [1] [0] buf xx xx xx xx buf buf 0xffffc630 80485f2: call 80484f0 <echo> 80485f7: mov 0xfffffffc(%ebp),%ebx # Return Point Winter 2013 Buffer Overflow

Buffer Overflow Example #1 Before call to gets Input 1234567 0xffffc658 Stack Frame for main 0xffffc658 Stack Frame for main f7 85 04 08 f7 85 04 08 58 c6 ff ff 0xffffc638 58 c6 ff ff 0xffffc638 Saved %ebx 00 37 36 35 xx xx xx xx buf 34 33 32 31 buf 0xffffc630 0xffffc630 Overflow buf, and corrupt saved %ebx, but no problem Winter 2013 Buffer Overflow

Buffer Overflow Example #2 Before call to gets Input 12345678 0xffffc658 Stack Frame for main 0xffffc658 Stack Frame for main f7 85 04 08 f7 85 04 08 58 c6 ff ff 0xffffc638 58 c6 ff 00 0xffffc638 Saved %ebx 38 37 36 35 [slide 10: code for main() that uses %ebp] xx xx xx xx buf 34 33 32 31 buf 0xffffc630 0xffffc630 Frame pointer corrupted . . . 804850a: 83 c4 14 add $0x14,%esp # deallocate space 804850d: 5b pop %ebx # restore %ebx 804850e: c9 leave # movl %ebp, %esp; popl %ebp 804850f: c3 ret # Return Winter 2013 Buffer Overflow

Buffer Overflow Example #3 Before call to gets Input 123456789ABC 0xffffc658 Stack Frame for main 0xffffc658 Stack Frame for main f7 85 04 08 f7 85 04 00 58 c6 ff ff 0xffffc638 43 42 41 39 0xffffc638 Saved %ebx 38 37 36 35 xx xx xx xx buf 34 33 32 31 buf 0xffffc630 0xffffc630 Return address corrupted 080485f2: call 80484f0 <echo> 080485f7: mov 0xfffffffc(%ebp),%ebx # Return Point Winter 2013 Buffer Overflow

Malicious Use of Buffer Overflow Stack after call to gets() void foo(){ bar(); ... } foo stack frame return address A B (was A) pad int bar() { char buf[64]; gets(buf); ... return ...; } data written by gets() exploit code bar stack frame B Input string contains byte representation of executable code Overwrite return address A with address of buffer (need to know B) When bar() executes ret, will jump to exploit code (instead of A) Winter 2013 Buffer Overflow

Exploits Based on Buffer Overflows Buffer overflow bugs allow remote machines to execute arbitrary code on victim machines Internet worm Early versions of the finger server (fingerd) used gets() to read the argument sent by the client: finger droh@cs.cmu.edu Worm attacked fingerd server by sending phony argument: finger “exploit-code padding new-return-address” exploit code: executed a root shell on the victim machine with a direct TCP connection to the attacker Winter 2013 Buffer Overflow

Avoiding Overflow Vulnerability /* Echo Line */ void echo() { char buf[4]; /* Way too small! */ fgets(buf, 4, stdin); puts(buf); } Use library routines that limit string lengths fgets instead of gets (second argument to fgets sets limit) strncpy instead of strcpy Don’t use scanf with %s conversion specification Use fgets to read the string Or use %ns where n is a suitable integer Winter 2013 Buffer Overflow

System-Level Protections not drawn to scale System-Level Protections FF Stack Randomized stack offsets At start of program, allocate random amount of space on stack Makes it difficult for exploit to predict beginning of inserted code Use techniques to detect stack corruption Nonexecutable code segments Only allow code to execute from “text” sections of memory Do NOT execute code in stack, data, or heap regions Hardware support needed Heap Data Text 08 00 Winter 2013 Buffer Overflow

Winter 2013 Buffer Overflow