Section 2.1 Instantaneous Rate of Change Applied Calculus,4/E, Deborah Hughes-Hallett Copyright 2010 by John Wiley and Sons, All Rights Reserved.

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Section 2.1 Instantaneous Rate of Change Applied Calculus,4/E, Deborah Hughes-Hallett Copyright 2010 by John Wiley and Sons, All Rights Reserved

Applied Calculus,4/E, Deborah Hughes-Hallett Copyright 2010 by John Wiley and Sons, All Rights Reserved

Applied Calculus,4/E, Deborah Hughes-Hallett Copyright 2010 by John Wiley and Sons, All Rights Reserved Figure 2.1: Average velocities over intervals on either side of t = 1 showing successively smaller intervals

Applied Calculus,4/E, Deborah Hughes-Hallett Copyright 2010 by John Wiley and Sons, All Rights Reserved

Applied Calculus,4/E, Deborah Hughes-Hallett Copyright 2010 by John Wiley and Sons, All Rights Reserved Figure 2.2: Visualizing the average rate of change of f between a and b Figure 2.3: Visualizing the instantaneous rate of change of f at a

Applied Calculus,4/E, Deborah Hughes-Hallett Copyright 2010 by John Wiley and Sons, All Rights Reserved Problem 11 (a) The function f is given in Figure At which of the labeled points is f’(x) positive? Negative? Zero? (b) At which labeled point is f’ largest? At which labeled point is f’ most negative? Figure 2.13

Applied Calculus,4/E, Deborah Hughes-Hallett Copyright 2010 by John Wiley and Sons, All Rights Reserved Problem 16 Table 2.4 gives the percent of households in the US with cable television t years since (a) Does f ’( 6) appear to be positive or negative? What does this tell you about the percent of households with cable television? (b) Estimate f ’ (2). Estimate f ’ (10). Explain what each is telling you, in terms of cable television. Table 2.4 t (years since 1990) P (% with cable)

Applied Calculus,4/E, Deborah Hughes-Hallett Copyright 2010 by John Wiley and Sons, All Rights Reserved Section 2.2 The Derivative Function

Applied Calculus,4/E, Deborah Hughes-Hallett Copyright 2010 by John Wiley and Sons, All Rights Reserved Figure 2.18 : Estimating the derivative graphically as the slope of the tangent line Table 2.5 Estimated values of derivative of function in Figure 2.18 x–2–2–1– Derivative of x62–1–1–2–2–2–2–1–114

Applied Calculus,4/E, Deborah Hughes-Hallett Copyright 2010 by John Wiley and Sons, All Rights Reserved Example 3 The graph of f is in Figure Which of the graphs (a) – (c) is a graph of the derivative f ’ ? Figure 2.21 Solution (a)(b) (c)

Applied Calculus,4/E, Deborah Hughes-Hallett Copyright 2010 by John Wiley and Sons, All Rights Reserved

Applied Calculus,4/E, Deborah Hughes-Hallett Copyright 2010 by John Wiley and Sons, All Rights Reserved Example 4 Table 2.6 gives values of c(t), the concentration (mg/cc) of a drug in the bloodstream at time t (min). Construct a table of estimated values for c ’ (t), the rate of change of c(t) with respect to t. Table 2.6 Concentration of a drug as a function of time t (min) c(t) (mg/cc) Solution (continued on next slide)

Applied Calculus,4/E, Deborah Hughes-Hallett Copyright 2010 by John Wiley and Sons, All Rights Reserved Example 4 (continued) Table 2.7 Derivative of concentration t c’(t) –0.3–0.7–1.1–1.6–2.2 We estimate the derivative for each value of t using a difference quotient. For example, Similarly, we get the estimates (mg/cc) per minute and so on. These values are tabulated in Table 2.7. Notice that the derivative has small positive values up until t = 0.4, and then it gets more and more negative, as we expected.

Applied Calculus,4/E, Deborah Hughes-Hallett Copyright 2010 by John Wiley and Sons, All Rights Reserved Section 2.3 Interpretations of the Derivative

Applied Calculus,4/E, Deborah Hughes-Hallett Copyright 2010 by John Wiley and Sons, All Rights Reserved

Applied Calculus,4/E, Deborah Hughes-Hallett Copyright 2010 by John Wiley and Sons, All Rights Reserved Example 2 Solution In the Leibniz notation, Since C is measured in dollars and T is measured in tons, dC/dT is measured in dollars per ton. You can think of dC as the extra cost of extracting an extra dT tons of ore. So the statement says that when 2000 tons of ore have already been extracted from the mine, the cost of extracting the next ton is approximately $100. Another way of saying this is that it costs about $100 to extract the 2001 st ton.

Applied Calculus,4/E, Deborah Hughes-Hallett Copyright 2010 by John Wiley and Sons, All Rights Reserved Local Linear Approximation If y = f(x) and Δy ≈ f’(x) Δx. Then for x near a and Δx = x – a f(x) ≈ f(a) + f’(a) Δx This is called the Tangent Line Approximation. Problem 27 Annual net sales, in billions of dollars, for the Hershey Company, the largest US producer of chocolate, is a function S = f(t) of time, t, in years since (a)Interpret the statements f(8) = 5.1 and f’(8) = 0.22 in terms of Hershey sales. (b)Estimate f(12) and interpret it in terms of Hershey sales.

Applied Calculus,4/E, Deborah Hughes-Hallett Copyright 2010 by John Wiley and Sons, All Rights Reserved Relative Rate of Change The relative rate of change of y = f(t) at t = a is defined to be Relative rate of change of y at a Problem 43 The number of active Facebook users hit 175 million at the end of February 2009 and 200 million at the end of April With t in months since the start of 2009, let f(t) be the number of active users in millions. Estimate f(4) and f’(4) and the relative rate of change of f at t = 4. Interpret your answers in terms of Facebook users.

Applied Calculus,4/E, Deborah Hughes-Hallett Copyright 2010 by John Wiley and Sons, All Rights Reserved Section 2.4 The Second Derivative

Applied Calculus,4/E, Deborah Hughes-Hallett Copyright 2010 by John Wiley and Sons, All Rights Reserved Figure 2.33: Meaning of f’’: The slope increases from negative to positive as you move from left to right, so f’’ is positive and f is concave up. Figure 2.34: Meaning of f’’: The slope decreases from positive to negative as you move from left to right, so f’’ is negative and f is concave down.

Applied Calculus,4/E, Deborah Hughes-Hallett Copyright 2010 by John Wiley and Sons, All Rights Reserved Problem 19 At exactly two of the labeled points in Figure 2.40, the derivative f’ is 0; the second derivative f’’ is not zero at any of the labeled points. On a copy of the table, give the signs of f, f’, f’’ at each marked point. Figure 2.40 Pointff’f’’ A B C D

Applied Calculus,4/E, Deborah Hughes-Hallett Copyright 2010 by John Wiley and Sons, All Rights Reserved Problem 23 A function f has f(5) = 20, f’(5) = 2 and f’’(x) < 0., for x ≥ 5. Which of the following are possible values for f(7) and which are impossible? (a)26 (b) 24(c) 22

Applied Calculus,4/E, Deborah Hughes-Hallett Copyright 2010 by John Wiley and Sons, All Rights Reserved Section 2.5 Marginal Cost and Revenue

Applied Calculus,4/E, Deborah Hughes-Hallett Copyright 2010 by John Wiley and Sons, All Rights Reserved Example 1 If cost, C, and revenue, R, are given by the graph in Figure 2.47, for what production quantities does the firm make a profit? Solution Figure 2.47: Costs and revenues

Applied Calculus,4/E, Deborah Hughes-Hallett Copyright 2010 by John Wiley and Sons, All Rights Reserved Figure 2.48: Marginal cost: Slope of one of these lines Suppose C(q) is the function giving the cost of running q flights. If the airline had originally planned to run 100 flights, its costs would be C(100). With the additional flight, its costs would be C(101). Therefore, Marginal cost = C(101) – C(100). Now and this quantity is the average rate of change of cost between 100 and 101 flights.

Applied Calculus,4/E, Deborah Hughes-Hallett Copyright 2010 by John Wiley and Sons, All Rights Reserved In Figure 2.48, Figure 2.48: Marginal cost: Slope of one of these lines

Applied Calculus,4/E, Deborah Hughes-Hallett Copyright 2010 by John Wiley and Sons, All Rights Reserved Problem 12 Cost and revenue functions for a charter bus company are shown in Figure Should the company add a 50 th bus? How about a 90 th ? Explain your answers using marginal revenue and marginal cost. Figure 2.57