Solve the equation. 1. = 4 x 6 15 3. x(x – 4) = 3(x – 4) + x ANSWER 10

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Solve the equation. 1. = 4 x 6 15 3. x(x – 4) = 3(x – 4) + x ANSWER 10 ANSWER 2,6 2. 5(3x – 2) = 4(4x – 1) 4. 2x2 + 5x – 12 = 0 ANSWER – 4, 3 2 ANSWER –6

Solve a rational equation by cross multiplying EXAMPLE 1 Solve a rational equation by cross multiplying Solve: 3 x + 1 = 9 4x + 1 3 x + 1 = 9 4x + 1 Write original equation. 3(4x + 5) = 9(x + 1) Cross multiply. 12x + 15 = 9x + 9 Distributive property 3x + 15 = 9 Subtract 9x from each side. 3x = – 6 Subtract 15 from each side. x = – 2 Divide each side by 3. The solution is –2. Check this in the original equation. ANSWER

The solution is – 3 . Check this in the original equation ANSWER GUIDED PRACTICE for Examples 1 and 2 1. 3 5x = 2 x – 7 SOLUTION 3 5x = 2 x – 7 Write original equation. 3(x – 7) = 2(5x ) Cross multiply. 3x – 21 = 10x Distributive property – 7x – 21 = 0 Subtract 10x from each side. – 7x = 21 Subtract 21 from each side. x = – 3 Divide each side by 7. The solution is – 3 . Check this in the original equation ANSWER

The solution is . Check this in the original equation – 1 3 ANSWER GUIDED PRACTICE for Examples 1 and 2 – 4 x + 3 5 x – 3 = 2. SOLUTION – 4 x + 3 5 x – 3 = Write original equation. – 4(x – 3) = 5(x + 3) Cross multiply. – 4x + 12 = 5x + 15 Distributive property – 9x + 12 = 15 Subtract 5x from each side. – 9x = 3 Subtract 12 from each side. x = – 1 3 Divide each side by 9. The solution is . Check this in the original equation – 1 3 ANSWER

GUIDED PRACTICE for Examples 1 and 2 1 2x +5 x 11x+ 8 = 3. SOLUTION 1 Write original equation. 1(11x + 8) = x(2x + 5) Cross multiply. 11x + 8 = 2x2 + 5x Distributive property 2x2 – 6x2 +8 = 0 Subtract 2x2 , and 5 from each side. x2 – 3x2 +4= 0 (x – 4)(x + 1) = 0

GUIDED PRACTICE for Examples 1 and 2 x = 4 , x = –1 ANSWER x = 4 , x = –1

( ) EXAMPLE 3 Standardized Test Practice SOLUTION 5 x + 7 4 = – 9 – 9 Write original equation. – 9 x 4x 5 + 7 4 ( ) = Multiply each side by the LCD, 4x. 20 + 7x = –36 Simplify. 7x = – 56 Subtract 20 from each side. x = – 8 Divide each side by 7.

EXAMPLE 3 Standardized Test Practice ANSWER The correct answer is B.

( ) EXAMPLE 4 Solve a rational equation with two solutions 1 – 8 x – 5 = 3 x Solve: 1 – 8 x – 5 = 3 x Write original equation. x(x – 5) 1– 8 x – 5 ( ) = 3 x Multiply each side by the LCD, x(x–5). x(x –5) – 8x = 3(x – 5) Simplify. x2 – 5x – 8x = 3x – 15 Simplify. x2 – 16x +15 = 0 Write in standard form. (x – 1)(x – 15) = 0 Factor. x = 1 or x = 15 Zero product property

EXAMPLE 4 Solve a rational equation with two solutions ANSWER The solutions are 1 and 15. Check these in the original equation.

EXAMPLE 5 Check for extraneous solutions 6 x – 3 = 8x2 x2 – 9 – 4x x + 3 Solve: SOLUTION Write each denominator in factored form. The LCD is (x + 3)(x – 3). = 8x2 (x + 3)(x – 3) – 4x x + 3 6 x –3 x + 3 (x + 3)(x – 3) 6 x –3 = 8x2 (x + 3)(x – 3) 4x 6(x + 3) = 8x2 – 4x(x – 3) 6x + 18 = 8x2 – 4x2 + 12x

EXAMPLE 5 Check for extraneous solutions 0 = 4x2 + 6x –18 0 = 2x2 + 3x – 9 0 = (2x – 3)(x + 3) 2x – 3 = 0 or x + 3 = 0 x = 3 2 or x = –3 You can use algebra or a graph to check whether either of the two solutions is extraneous. Algebra The solution checks, but the apparent solution –3 is extraneous, because substituting it in the equation results in division by zero, which is undefined. 3 2

GUIDED PRACTICE for Examples 3, 4 and 5 Solve the equation by using the LCD. Check for extraneous solutions. 7 2 + 3 x = 3 5. SOLUTION Write each denominator in factored form. The LCD is 2x 7 2 + 3 x = 3 2x + 2x = 2x 3 7 2 3 x 7x + 6 = 6x x = – 6

GUIDED PRACTICE for Examples 3, 4 and 5 2 x + 4 3 = 2 6. SOLUTION Write each denominator in factored form. The LCD is 3x 2 x + 4 3 = 2 3x + 3x = 3x 2 2 x 4 3 6 + 4x = 6x 6 = 2x x = 3

GUIDED PRACTICE for Examples 3, 4 and 5 3x x +1 – 5 2x = 3 9. SOLUTION Write each denominator in factored form. The LCD is (x + 1)(2x) 3x 5 3 x +1 – 2x = 3 2 x 2x (x + 1) – 2x (x +1) = 2x (x +1) 3x x +1 5

GUIDED PRACTICE for Examples 3, 4 and 5 6x2 – 5x – 5 = 3x + 3 0 = 3x + 3 – 6x2 +5x + 5 0 = – 6x2 + 8x + 8 0 = (3x +2) (x – 2) 3x + 2 = 0 x = 2 3 – x – 2 = 0 x = 2 or

GUIDED PRACTICE for Examples 3, 4 and 5 5x x –2 = 7 + 10 10. SOLUTION Write each denominator in factored form. The LCD is x – 2 5x x –2 = 7 + 10 x – 2 = (x – 2) 7 + (x – 2) 10 x – 2 5x x –2 5x = 7x – 14 + 10 4 = 2x x = 2 x=2 results in no solution.

Solve a rational equation given a function EXAMPLE 6 Solve a rational equation given a function Video Game Sales From 1995 through 2003, the annual sales S (in billions of dollars) of entertainment software can be modeled by S(t) = 848t2 + 3220 115t2 + 1000 0 < t < 8 where t is the number of years since 1995. For which year were the total sales of entertainment software about $5.3 billion? SOLUTION S(t) = 848t2 + 3220 115t2 + 1000 Write given function. 848t2 + 3220 115t2 + 1000 5.3 = Substitute 5.3 for S(t).

Solve a rational equation given a function EXAMPLE 6 Solve a rational equation given a function 5.3(115t2 + 1000) = 848t2 + 3220 Multiply each side by 115t2 + 1000. 609.5t2 + 5300 = 848t2 + 3220 Simplify. 5300 = 238.5t2 + 3220 Subtract 609.5t2 from each side. 2080 = 238.5t2 Subtract 3220 from each side. 8.72 t2 Divide each side by 238.5. ±2.95 t Take square roots of each side. Because –2.95 is not in the domain (0 < t < 8), the only solution is 2.95.

Daily Homework Quiz Solve the equation. 1. 5 2x + 3 = 6 x – 2 ANSWER – 4 2. 5 – x + 3 6 = 12 x ANSWER 12 5 – , 3 3. 1 x + 2 x2 = 3 x3 ANSWER – 3 , 1 4. x – 1 x – 2 + x + 1 x = x2 – 1 38 ANSWER – 4 , 5

Daily Homework Quiz 5. So far this season, a baseball team has won 36 of its first 64 games. How many consecutive games does the need to win to raise its winning percentage to 60%? ANSWER 6 games