AN ANECDOTE “How do you get to the Lincoln Center for the Performing Arts ?” “ Practice, practice, practice….” An `out-of-towner’ visiting NYC for the.

Slides:



Advertisements
Similar presentations
Empirical and Molecular Formulas
Advertisements

More Unit conversions Convert 45.7 kg to g 4.57*104 g
Empirical and Molecular Formulas
Empirical Formula From percentage to formula. The Empirical Formula The lowest whole number ratio of elements in a compound. The molecular formula the.
Empirical and Molecular Formulas Empirical and Molecular Formulas An empirical formula shows the simplest whole number ratio of atoms of each element.
Chemistry Notes Empirical & Molecular Formulas. Empirical Formula The empirical formula gives you the lowest, whole number ratio of elements in the compound.
Chapter 8 Chemical Composition Chemistry B2A. Atomic mass unit (amu) = × g Atomic Weight Atoms are so tiny. We use a new unit of mass:
The Mole: A Shortcut for Chemists S-C-8-1_The Mole Presentation Source:
The Mole & Chemical Formulas A chemical formula represents the ratio of atoms that always exists for that compound Example: Water – H 2 O Always 2 H atoms.
Empirical and Molecular Formulas
Mass Conservation in Chemical Reactions Mass and atoms are conserved in every chemical reaction. Molecules, formula units, moles and volumes are not always.
Percent Composition and Empirical Formulas What is 73% of 150? 110 The relative amounts of each element in a compound are expressed as the percent composition.
Calculating Percentage Composition Suppose we wish to find the percent of carbon by mass in oxalic acid – H 2 C 2 O 4. 1.First we calculate the formula.
Chapter 3 Molecules, Compounds, & Chemical Equations CHE 123: General Chemistry I Dr. Jerome Williams, Ph.D. Saint Leo University.
Empirical and Molecular Formulas. Empirical Formula What are we talking about??? Empirical Formula represents the smallest ratio of atoms in a formula.
Stoichiometry By Ellis Benjamin. Definitions I Compounds - is a pure substance that is composed of two or more elements Molecules – is a combination of.
Body parts Mole calculations: Moles level 2(continued)
8 | 1 CHAPTER 8 CHEMICAL COMPOSITION. 8 | 2 Atomic Masses Balanced equations tell us the relative numbers of molecules of reactants and products. C +
1 Percent Composition: Identifies the elements present in a compound as a mass percent of the total compound mass. The mass percent is obtained by dividing.
Percent Composition Like all percents: Part x 100 % whole Find the mass of each component, divide by the total mass.
What Could It Be? Empirical Formulas The empirical formula is the simplest whole number ratio of the atoms of each element in a compound. Note: it is.
Chemistry Warm Up: Mole / Mass / Particles 1.What is the mass of one mole of water? 2.If one milliliter of water has a mass of 1.00grams, how many moles.
Unit 6: Chemical Quantities
Percent Composition, Empirical and Molecular Formulas.
Empirical Formula Calculations Problem: A compound is found to contain the following % by mass: 69.58% Ba 6.090% C 24.32% O What is the empirical formula?
Mass % and % Composition Mass % = grams of element grams of compound X 100 % 8.20 g of Mg combines with 5.40 g of O to form a compound. What is the mass.
Chapter 3 sample problems. Average atomic mass Calculate the average atomic mass of magnesium given the following isotopic mass and mass percent data.
Take your periodic table out. What is atomic mass of Carbon Point where you can find it in the periodic table! 6 is atomic number not atomic mass Atomic.
Ch. 11 The Mole The Mol House The Mol House Atoms in a molecule molecules molgrams Molar Mass Avogadro’s number Chemical formula.
Mole/Grams Conversion Find mass ratios Review the calculation of gram formula mass. Define moles in terms of mass and grams in terms of moles. Calculate.
The Mole, part II Glencoe, Chapter 11 Sections 11.3 & 11.4.
Empirical Formulas Definition Ex: A formula that gives the simplest whole number ratio of the different atoms in a compound. H 2 O 2 = hydrogen peroxide.
Formulas Ethane Formula C 2 H 6 Why don’t we simplify it? CH 3 StructureH | H ---- C ---- C ---- H | H.
Calculating Empirical Formula Using percentage or mass to find the Empirical Formula.
Percent Composition What is the % mass composition (in grams) of the green markers compared to the all of the markers? % green markers = grams of green.
RR: How many ways can you count to 100?. Do you know how to count? In chemistry, the unit that helps us count is the mole (mol). The mole represents
Brain Teaser Using the students present in class today, complete the data table below total# girls # boys % girls % boys students Describe how one could.
Empirical and Molecular Formulas Topic #20. Empirical and Molecular Formulas Empirical --The lowest whole number ratio of elements in a compound. Molecular.
Take your periodic table out. What is atomic mass of Carbon Point where you can find it in the periodic table! 6 is atomic number not atomic mass Atomic.
Empirical Formulas Definition Ex:
Bell Ringer How many moles of Nitric acid are there in 250 g?
Ch. 7.4 Determining Chemical Formulas
6/17/2018.
Calculating Empirical Formulas
EMPIRICAL FORMULA VS. MOLECULAR FORMULA .
% Composition & Empirical Formulas
Welcome back…try not to slump in week 4….
Homework 5 posted-due Wednesday 21 Feb
Empirical Formula Molecular Formula
Homework 5 posted-due Wednesday 21 Feb
Section 3.1 The Mole and Molar Mass
Chapter 3 Composition of Substances and Solutions
EMPIRICAL FORMULA The empirical formula represents the smallest ratio of atoms present in a compound. The molecular formula gives the total number of atoms.
From percentage to formula
From percentage to formula
Ch. 8 – The Mole Empirical formula.
Percent Composition Empirical Formula Molecular Formula
Homework 5 due today Wednesday 21 Feb
Empirical Formulas Unit 5.
mole (symbolized mol) = 6.02 x particles
The Mole: A Shortcut for Chemists
2/19/2019.
2/23/2019.
From percentage to formula
Molecular Formula number and type of atoms covalent compounds
What Could It Be? Finding Empirical and Molecular Formulas.
Empirical and Molecular Formulas
Empirical and Molecular Formulas
Final Review Day 2 Ch 11, 12 & 13.
Molecular Formula.
Presentation transcript:

AN ANECDOTE “How do you get to the Lincoln Center for the Performing Arts ?” “ Practice, practice, practice….” An `out-of-towner’ visiting NYC for the first time asks Joshua Bell (world’s greatest violinist): Joshua’s answer (supposedly):

Some “Sweet” Mole Calculations Sucrose  2 glucose C 11 H 22 O 11 2 C 6 H 12 O 6 In CokeWhat your body burns

The result of steady Coke drinking……

a)weight per mole (MW): what does a mole of C 6 H 12 O 6 weigh ? (C=12; H=1; O=16) 6* *1 + 6*16 = 180 g/mol 1.1) mole to mass: how many g C 6 H 12 O 6 of are present in mole of C 6 H 12 O 6 ? mol * 180 g/mol = 1 g 1.2) mass to mole: how many moles of C 6 H 12 O 6 are in 360 g of C 6 H 12 O 6 ? mole calculations part g/180 g mol -1 = 2 moles

mole calculations part 1 (continued) 1.3) mole to # molecule: how many molecules of C 6 H 12 O 6 are in 0.5 mol of C 6 H 12 O 6 ? 0.5 mol *6*10 23 molecules/mol = 3*10 23 molecules 1.4) mass to # molecules: how many molecules of C 6 H 12 O 6 are in 120 g of C 6 H 12 O 6 ? (120/180) mol * 6*10 23 molecules =4*10 23 molecules mol

1.5) # molecules to moles: how many moles in 3*10 24 molecules of C 6 H 12 O 6 ? 3*10 24 molecules/ 6*10 23 molecules/mol = 5 moles 1.6) # molecules to mass : How many grams of C 6 H 12 O 6 are in 2.0 *10 22 molecules of C 6 H 12 O 6 ? 2*10 22 molecules * 180 g 6*10 23 molecules/mol mol = * 180 = 6 grams mole calculations part 1 (continued)

A.7.27*10 21 B C.82.9 D.2.48* E.My answer isn’t above The gram molecular mass of of ‘crystal meth’) is g/mol. How many moles of crystal meth are in a typical street `teenth’ = 1/16 of an ounce= 1.80 grams ? (1 mol count=6.022*10 23.)

B1-Aflatoxin (MW=328.2 g/mol) is a naturally occurring, horribly toxic poison derived from Aspergillus fungi, a common contaminant in corn. It causes cancer in most humans at the staggeringly low exposure level of 1*10 17 molecules. What is the equivalent mass of aflatoxin represented by this count ? ( 1 mol count=6.022*10 23.) A.3.28* g B.1.84*10 -4 g C. 5.45*10 -5 g D.5.06* g E.1.98* g F.6.02*10 6 g G.My answer isn’t above

Micro chip manufacture requires nearly oxygen- free conditions wherein the concentration of O 2 is at or below 17 pg/L. Given that the atomic mass of O is 16 g/mol, about how many molecules of O 2 /L does this represent ? Note: 1 mol count=6.022*10 23 A.5.4*10 24 B.3.5*10 22 C.5.3*10 22 D.3.2*10 11 E.6.4*10 12 F.1.9*10 13 G.My answer isn’t above

Moles: part 2 body parts (mole ratio) math: the knee bone is connected to the thigh bone….

11 people How many hands ??? hands 1 people x = 22 hands

How many toes connected to the hands (assuming no deformities) ? hands 1 person hand x 10 toes person x = 50 toes

Simplest `body’ parts example : mole  Mole Octane = C 8 H 18 How many H are in 20 moles of octane ? 20 mols octane * 18 mol H = 360 mol H mol octane

Isohexane has the formula C 6 H 14. How many C moles are present if we have moles of isohexane ? A mol C B.1.00 mol C C.36 mol C D mol E.None of the above

`body’ parts example 2 : Weight  moles first, then mol  Mol Octane = C 8 H 18 How many moles of octane contain 24 grams of C (at. wt. = 12 g/mol) 24 g = 2 moles C 12 g/mol C Step 1) Convert grams C to moles C (all roads lead through moles divide up)

`body’ parts example 2 : (continued) Octane = C 8 H 18 How many moles of octane contain 24 grams of C (at. wt. = 12 g/mol) Step 2) 2 moles C => how many moles octane? 1 mol octane = x 8 mol C 2 x= 2/8=0.25 moles octane (body parts relationship ?)

Isohexane has the formula C 6 H 14. How many moles of isohexane are formed with 24 grams of C (1 mol C=12 g) A moles isohexane B.2 moles isohexane C moles isohexane D.3 moles isohexane E.Stoichiometry blows F. None of the above

`body’ parts example 3 : Weight  moles, then mol  Mol  weight Octane = C 8 H 18 (MW=114) How many grams of H are in 10 grams of Octane ? (1 mole H=1 g H) Step 1) Convert grams octane to moles octane All roads lead through moles; divide up 10 g = mol octane 114 g/mol

`body’ parts example 3 (continued) : Octane = C 8 H 18 (MW=114) How many grams of H are in 10 grams of Octane ? (1 mole H=1 g H) Step 2) Relate moles H to moles octane (body parts relationship ?) 14 mol H = x 1 octane x= 14*0.0877=1.228 mol H

`body’ parts example 3 (continued) : Octane = C 8 H 18 (MW=114) How many grams of H are in 10 grams of Octane ? (1 mole H=1 g H) Step 3) convert moles H to grams H (multiply down) mol H * 1 g H/mol=1.228 mol H

Isohexane has the formula C 6 H 14. How many grams of H (at. Wt. = 1 g/mol) are combined in 300 grams of C 6 H 14 (MW=86 g/mol) A g H B.1.32 g H C g H D g H E g H