Ch. 4: “Cells & Their Environment”

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Presentation transcript:

Ch. 4: “Cells & Their Environment” Science Skills

EXPERIMENT A A selectively permeable membrane separates the solutions in the arms of the U-tube shown at right. The membrane is permeable to water and to substance A but not to substance B. Forty grams of substance A and 20 g of substance B have been added to the water on side 1 of the U-tube. Twenty grams of substance A and 40 g of substance B have been added to the water on side 2 of the U-tube. Assume that after a period of time, the solutions on either side of the membrane have reached equilibrium.

1. How many grams of substance A will be in solution on side 1 of the U-tube? How many grams of substance A will be in solution on side 2? Explain. Thirty grams of substance A will be in solution on side 1, and 30 g will be in solution on side 2. Because the membrane is permeable to substance A, diffusion will take place. Molecules of substance A will move from the side of the membrane where they are less concentrated until equilibrium is reached.

2. How many grams of substance B will be in solution on side 1 of the U-tube? How many grams of substance B will be in solution on side 2? Explain. The original 20 g of substance B will remain in solution on side 1, and the original 40 g will remain in solution on side 2 because substance B cannot pass through the membrane.

3. What has happened to the water level in the U-tube? Explain. The water level will be higher on side 2 of the U-tube. As substance A molecules move across the membrane from side 1 to side 2, there will be more dissolved molecules on side 2 than on side 1. This will cause water to move across the membrane by osmosis from side 1 to side 2.

EXPERIMENT B The cell membrane of red blood cells is permeable to water but not to sodium chloride, NaCl. Suppose that you have three flasks: • Flask X contains a solution that is 0.5 percent NaCl. • Flask Y contains a solution that is 0.9 percent NaCl. • Flask Z contains a solution that is 1.5 percent NaCl. To each flask, you add red blood cells, which contain a solution that is 0.9 percent NaCl.

4. Predict what will happen to the red blood cells in flask X. The cells will swell and will take in water until they and the flask solution are isotonic.

5. Predict what will happen to the red blood cells in flask Y. The cells will remain the same size because the solutions are isotonic.

6. Predict what will happen to the red blood cells in flask Z. The cells will shrink, and water will move out of the cells until they and the flask solution are isotonic.