 Mitosis 1875  Meiosis 1890s  Chromosomes being the “inheritance factors” that Mendel referred to 1902.

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Presentation transcript:

 Mitosis 1875  Meiosis 1890s  Chromosomes being the “inheritance factors” that Mendel referred to 1902

 Genes that often travel together during meiosis and because they are on the same chromosome  Why some traits are often seen together…

 By knowing recombination frequencies you can determine the approx. distance between genes on the same chromosome in map units  If you know the map units of traits on a chromosome you can create a genetic map (shows the order in which the genes appear on a chromosome NOT the exact distances apart the loci of the genes are)

 Snapdragons with genotypes CCDD and ccdd are crossed. The CcDd progeny were then crossed with ccdd plants and we obtain 30% CcDd, 20% ccD 20% Ccdd and 30% ccdd offspring. We conclude: A. Genes C and D are linked, separated by 20 map units B. Genes C and D are linked, separated by 30 map units C. Genes C and D are linked, separated by 40 map units D. Genes C and D are unlinked

 Snapdragons with genotypes CCDD and ccdd are crossed. The CcDd progeny were then crossed with ccdd plants and we obtain 30% CcDd, 20% ccD 20% Ccdd and 30% ccdd offspring. We conclude: A. Genes C and D are linked, separated by 20 map units B. Genes C and D are linked, separated by 30 map units C. Genes C and D are linked, separated by 40 map units (CORRECT 1% = 1 map unit, therefore 40% recombinants = 40 map units) D. Genes C and D are unlinked

 Snapdragons with genotypes DDEE and ddee are crossed. The DdEe progeny are then crossed with ddee plants and we obtain 45% DdEe, 5 % ddEe, 5% Ddee and 45% ddee. How far apart are genes D and E? a. 5 map units b. 10 map units c. 45 map units d. Genes D and E are not linked

 Snapdragons with genotypes DDEE and ddee are crossed. The DdEe progeny are then crossed with ddee plants and we obtain 45% DdEe, 5 % ddEe, 5% Ddee and 45% ddee. How far apart are genes D and E? a. 5 map units b. 10 map units (COREECT 1% = 1 map unit, therefore 10% recombinants = 10 map units) c. 45 map units d. Genes D and E are not linked

 Pg #s: 4, 5, 8, 9, 13