9.3 Altitude-On-Hypotenuse Theorems (a.k.a Geometry Mean)

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Presentation transcript:

9.3 Altitude-On-Hypotenuse Theorems (a.k.a Geometry Mean)

Index Card: When an altitude is drawn from a vertex to a hypotenuse, then three similar triangles are formed. **Identify the three similar triangles! Which theorem can they be proven similar?

Remember: Given two numbers a and b, x is the geometric mean if MEANS EXTREMES

Find the geometric mean of 9 and 16

A B C Altitudes!!!! What do you remember? An Altitude *Starts at a vertex *Forms a right angle D

A B C The hypotenuse is split into two pieces BD and DA D CD (the altitude) is the geometric mean of those two pieces

A B C D If the altitude is in the means place, put the two segments of the hypotenuse into the extremes.

A B C D Index Card Theorem: The altitude to the hypotenuse is the mean proportional (or geometric mean) between the segments of the hypotenuse. h x y a b h = altitude x and y are segments of the hypotenuse

the LEG is the geometric mean A BC D If the leg is in the means place, put the whole hyp. and segment adjacent to that leg into the extremes. AB AC AD

A BC D x b b c y x c b a

the LEG is the geometric mean A BC D AB CB BD Using the other part of the hypotenuse: Remember: You can use similar triangles…compare the hypotenuse and the long leg using the large triangle and the medium-sized triangle.

A B C D 9 16 x EX: 1 Find x x x9 16

EX: 2 Find the length of AB. A BC D x 32 x

A B C D 3 x 4 EX 3: Solve for x x

EX: 4 Find the length of CB. A B C D x x = x50 x x 2 = 1600

A B C D x 12 5 EX: 5 Solve for x x x = 25

Homework p. 379 #1-5, 16, 17