Prof. Abel Esteban Ortega Luna. CASOS DE CONGRUENCIA PRIMER CASO: LADO – ÁNGULO – LADO (L – A – L) ABC DEF.

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Presentation transcript:

Prof. Abel Esteban Ortega Luna

CASOS DE CONGRUENCIA PRIMER CASO: LADO – ÁNGULO – LADO (L – A – L) ABC DEF

A B D C E 3 60º x ABE BDC x = 3 1) En la figura los triángulos ABC y BDE son equiláteros. Calcula CD, si AE = 3.

C A B D E 60º x 2x 60º x ABE DCE 3x = 60º x = 20º 2) En la figura, calcula el valor de x; si AB // CD; AB = DE y CD = AE

SEGUNDO CASO: ÁNGULO – LADO – ÁNGULO (A – L – A) ABC DEF

A B Q P C X =90º 1)En la figura mostrada, si AB = BC; BP = 4 y PQ = 3. Calcula PC. ABQ BPC x = x = 7

5 A B E L 3 2 C 3 x y y x x 2 2x = y x y = 1 2 2) En la figura, halla x/y ABL EBC

TERCER CASO: LADO – LADO – LADO (L – L – L) ABC DEF

A B C D E 50º x 50º + x 1) Encuentra x, si AB = BD, BC = BE, AE = DC ABE BDC 50º + 50º + x = 180º 100º + x = 180º x = 80º

45º 35º 50º x A B E L M 50–X ABM ALE 35º = 50º – x x = 50º – 35º x = 15º 2) Halla x

CASO ESPECIAL: ÁNGULO – LADO – LADO MAYOR (A – L – Lm) ABC DEF LADO MAYOR

x 3x 2x A M O R 60º 60º – x 60–3x 60–2x 120º+x 120º+x 1) En la figura, calcule x ARO MOR (A – L – L m ) x = 60º – 3x 4x = 60º x = 15º

B En el gráfico, calcula x, si AB = CD y BC AD 2X 45º3X A C D E 45º ABE CED (A – L – L m ) 3X 5x = 45º x = 9º