Solving Quadratic Equations by Factoring

Slides:



Advertisements
Similar presentations
Factoring Polynomials.
Advertisements

Factoring Polynomials.
Solving Quadratic Equations by Factoring
Solving Quadratic Equations by Finding Square Roots
1.5 Quadratic Equations Start p 145 graph and model for #131 & discuss.
Factoring Polynomials
Algebra 2 Chapter 5 Notes Quadratic Functions.
Day 5 Simplify each expression: Solving Quadratic Equations I can solve quadratic equations by graphing. I can solve quadratic equations by using.
QUADRATIC FUNCTIONS Unit 5.
Factoring Polynomials
16 Days. Two Days  Review - Use FOIL and the Distributive Property to multiply polynomials.
Chapter 4 Review. What shape does a Quadratic Function make What shape does a Quadratic Function make when it is graphed? when it is graphed?1. 2. What.
Chapter 10 Quadratic Equations and Functions
Graph quadratic equations. Complete the square to graph quadratic equations. Use the Vertex Formula to graph quadratic equations. Solve a Quadratic Equation.
Solving Quadratic Equations Section 1.3
Copyright © Cengage Learning. All rights reserved.
Algebra 2 Chapter 5 Notes Quadratic Functions.
Factoring Polynomials
Chapter 8 Review Quadratic Functions.
9.1 – Solving Quadratics by Square Roots
U4L3 Solving Quadratic Equations by Completing the Square.
Solving Quadratic Equations.
On Page 234, complete the Prerequisite skills #1-14.
6.1 Using Properties of Exponents What you should learn: Goal1 Goal2 Use properties of exponents to evaluate and simplify expressions involving powers.
Three simple methods for solving quadratic equations
CHAPTER 5 EXPRESSIONS AND FUNCTIONS GRAPHING FACTORING SOLVING BY: –GRAPHING –FACTORING –SQUARE ROOTS –COMPLETING THE SQUARE –QUADRATIC FORMULA.
Quadratics Review Day 1. Multiplying Binomials Identify key features of a parabola Describe transformations of quadratic functions Objectives FOILFactored.
Factoring and Finding Roots of Polynomials
Factoring a polynomial means expressing it as a product of other polynomials.
Objective: Solving Quadratic Equations by Finding Square Roots This lesson comes from chapter 9.1 from your textbook, page 503.
Algebra 2: Unit 5 Continued
Warm Up  Find the roots. Solving Quadratic Equations by Completing the Square.
WARM UP SOLVE USING THE QUADRATIC EQUATION, WHAT IS THE EXACT ANSWER. DON’T ROUND.
Lesson 1 Contents Example 1Graph a Quadratic Function Example 2Axis of Symmetry, y-Intercept, and Vertex Example 3Maximum or Minimum Value Example 4Find.
Solving Quadratic Equations by Finding Square Roots.
PERFECT SQUARE TRINOMIALS
Types of factoring put the title 1-6 on the inside of your foldable and #7 on the back separating them into sum and cubes 1.Greatest Common Factor 2.Difference.
A “Difference of Squares” is a binomial ( *2 terms only*) and it factors like this:
ALGEBRA 2 – CHAPTER 5 QUADRATICS. 5-2 PROPERTIES OF PARABOLAS.
Solving Quadratic Equations by Factoring. Zero Product Property For any real numbers a and b, if the product ab = 0, then either a = 0, b = 0, or both.
CHAPTER 5 EXPRESSIONS AND FUNCTIONS GRAPHING FACTORING SOLVING BY: –GRAPHING –FACTORING –SQUARE ROOTS –COMPLETING THE SQUARE –QUADRATIC FORMULA.
Lesson 2-3 The Quadratic Equation Objective: To learn the various ways to solve quadratic equations, including factoring, completing the square and the.
5.2 Solving Quadratic Equations by Factoring 5.3 Solving Quadratic Equations by Finding Square Roots.
Graphing Parabolas and Completing the Square. Warm-Up Solve each quadratic below (Hint: When you take the square-root you will get 2 answers; one positive.
Dear Power point User, This power point will be best viewed as a slideshow. At the top of the page click on slideshow, then click from the beginning.
Graphing Quadratic Functions Solving by: Factoring
Polynomial Equations and Factoring
Solving Quadratic Equations by Completing the Square
Factoring Polynomials
Solving Quadratic Equations by Finding Square Roots
Complete the Square Lesson 1.7
Solving Quadratic Equations by Factoring
Solving Quadratic Equations by Factoring
Solving Quadratic Equations by Factoring
Solving Quadratic Equations by Completing the Square
Factoring Polynomials
Solving Quadratic Equations by Factoring
4.3 Solving Quadratic Equations by Factoring
Solving Quadratic Equations by Factoring
The Square Root Property and Completing the Square
Solving Quadratic Equations by Factoring
Solving Quadratic Equations by Factoring
Solving Quadratic Equations by Factoring
Factoring Polynomials.
Factoring Polynomials.
3.4 Solve by Factoring (Part 1)
SAT Solving Quadratic Equations by Factoring
Solving Quadratic Equations by Factoring
Section 9.1 “Properties of Radicals”
Presentation transcript:

Solving Quadratic Equations by Factoring

Ways of finding the factors/ zeros Quadratic formula Factorization using zero property By taking square roots By squaring

Imaginary roots/ complex roots Fractions Decimals Types of solutions Real roots Imaginary roots/ complex roots Fractions Decimals

For any real numbers a and b, if ab=0, then either a=0, b=0, or both. Zero Product Property For any real numbers a and b, if ab=0, then either a=0, b=0, or both.

STEPS Solving a Quadratic Equation by Factoring Step 1 Write the equation in standard form. Step 2 Factor completely. Step 3 Use the zero-factor property. Set each factor with a variable equal to zero. Step 4 Solve each equation produced in step 3.

Quadratic Equations Standard Form

The solutions are -3 and 1/2. In this first example, the equation is already factored and is set equal to zero. To solve, simply set the individual factors equal to zero. The solutions are -3 and 1/2.

Factor using “difference of two squares.” In this example, you must first factor the equation. Notice the familiar pattern. After factoring, set the individual factors equal to zero. Factor using “difference of two squares.”

Now, try several problems Now, try several problems. Write these on your own paper, showing all steps carefully.

Here are the answers. If all are correct, you’re finished!

Solutions… work it out 1.

2.

3.

4.

How to factor a quadratic equation? Factoring a polynomial means expressing it as a product of other polynomials.

Factoring Method using difference of squares Factoring polynomials that are a difference of squares.

A “Difference of Squares” is a binomial (. 2 terms only A “Difference of Squares” is a binomial (*2 terms only*) and it factors like this:

To factor, express each term as a square of a monomial then apply the rule...

Here is another example:

Try these on your own:

Factoring Method Finding gcf Factoring polynomials with a common monomial factor (using GCF). **Always look for a GCF before using any other factoring method.

Steps: 1. Find the greatest common factor (GCF). 2. Divide the polynomial by the GCF. The quotient is the other factor. 3. Express the polynomial as the product of the quotient and the GCF.

This one uses a different technique than the previous ones This one uses a different technique than the previous ones. Really, this is something you should consider at the beginning of every factoring problem. See if you can solve it. Did you take out GCF?

Step 1: Step 2: Divide by GCF

The answer should look like this:

Factor these on your own looking for a GCF.

Factoring Method Factoring a trinomial in the form:

Solve by factoring into two binomials Step 1: Make one side zero, if not already Step 2: Factor into two binomials (x + __)(x + ___) = 0 Step 3: Set each factor to zero and solve.

2. Product of first terms of both binomials Factoring a trinomial: 1. Write two sets of parenthesis, ( )( ). These will be the factors of the trinomial. 2. Product of first terms of both binomials must equal first term of the trinomial. Next

Factoring a trinomial: 3. The product of last terms of both binomials must equal last term of the trinomial (c). 4. Think of the FOIL method of multiplying binomials, the sum of the outer and the inner products must equal the middle term (bx).

x -2 -4 Factors of +8: 1 & 8 2 & 4 -1 & -8 -2 & -4 2x + 4x = 6x O + I = bx ? Factors of +8: 1 & 8 2 & 4 -1 & -8 -2 & -4 1x + 8x = 9x 2x + 4x = 6x -1x - 8x = -9x -2x - 4x = -6x

Check your answer by using FOIL

In the next example, you must set the equation equal to zero before factoring. Then set the individual factors equal to zero and solve.

Re-write this example in the proper form Re-write this example in the proper form. Notice that the leading coefficient is not one. Use an appropriate factoring technique. Then solve as you have done before.

One side needs to be zero first! Practice Solve One side needs to be zero first!

Divide both sides by GCF first! Practice Solve Divide both sides by GCF first!

Factoring a perfect square trinomial in the form: Factoring Technique continued Factoring a perfect square trinomial in the form:

Perfect Square Trinomials can be factored just like other trinomials (guess and check), but if you recognize the perfect squares pattern, follow the formula!

a b Does the middle term fit the pattern, 2ab? Yes, the factors are (a + b)2 :

One side needs to be zero first! Practice Solve One side needs to be zero first!

a b Does the middle term fit the pattern, 2ab? Yes, the factors are (a - b)2 :

Try these on your own:

Answers:

Solve

Solve. BACK

Solve.

Solve

Number Of Solutions The degree of a polynomial is equal to the number of solutions. Three solutions!!!

Solve. BACK

x2 – 9x + 20 = 0 (x – 4)(x – 5) = 0 x – 4 = 0 x = 4 x – 5 = 0 x = 5 Example: x2 – 9x + 20 = 0 (x – 4)(x – 5) = 0 x – 4 = 0 x = 4 x – 5 = 0 x = 5 x = {5, 4} Standard form Factor Set each factor = 0 Solve Write the solution set

4x2 – 49 = 0 (2x + 7)(2x – 7) = 0 2x + 7 = 0 2x – 7 = 0 Example Standard form Factor Set each factor = 0 Solve Write the solution set SOLUTION IS

Step 1: Factor the polynomial. (x - 6)(x + 6) = 0 How would you solve the following equation? x2 – 36 = 0 Step 1: Factor the polynomial. (x - 6)(x + 6) = 0

This equation has two solutions or zeros: x = 6 or x = -6. Step 2: Apply the zero product property which states that For all numbers a and b, if ab = 0, then a = 0, b = 0, or both a and b equal 0. (x - 6)(x + 6) = 0 Therefore (x – 6) = 0 or (x + 6) = 0. x – 6 = 0 + 6 +6 x + 6 = 0 - 6 -6 or x = 6 x = -6 This equation has two solutions or zeros: x = 6 or x = -6.

x2 – 25 = 0 x2 + 7x – 8 = 0 x2 – 12x + 36 = 0 c2 – 8c = 0 You Try It Solve the following equations. x2 – 25 = 0 x2 + 7x – 8 = 0 x2 – 12x + 36 = 0 c2 – 8c = 0

Summary of Steps Get a value of zero on one side of the equation. Factor the polynomial if possible. Apply the zero product property by setting each factor equal to zero. Solve for the variable.

SOLVING QUADRATIC EQUATIONS- When to use what??? Get the equation in standard form: If there is no middle term (b = 0) then get the x2 alone and square root both sides (if you get a negative under the square root there are no real solutions). If there is no constant term (c = 0) then factor out the common x and solve (set each factor = 0). If a, b and c are non-zero, see if you can factor and use the factor law to solve. If it doesn't factor or is hard to factor, use the quadratic formula to solve (if you get a negative under the square root there are no real solutions).

Vocabulary If b2 = a then b is a square root of a. All positive real numbers have two square roots A positive square root (or principle square root) and a negative square root. This is written as

Vocabulary A square root is written with the radical symbol The number or expression inside the radical symbol is the radicand.

Vocabulary Give some examples of perfect squares The square of an integer is called a perfect square. Give some examples of perfect squares

Simplify each expression:

Solving Quadratic Equations: Solving by Taking Square Roots Isolate the squared variable term Put the number over on the other side

Solving quadratics by taking square roots Solve each equation. a. x2=4 b. x2=5 c. x2=0 d. x2=-1 x2=4 has two solutions, x = 2, x = -2 x2=5 has two solutions, x =√5, x =- √5 x2=0 has one solution, x = 0 x2=-1 has no real solution

Then the solution is x = ± 2 x2 – 4 = 0 
x2 = 4 I know that, when solving an equation, I can do whatever I like to that equation as long as I do the same thing to both sides of the equation. On the left-hand side of this particular equation, I have an x2, and I need a plain x. To turn an x2 into an x, I can take the square root of each side of the equation: 
x = ± 2 Then the solution is x = ± 2

Example 2: Solve 9m2 = 169

Example 1: Solve the equation: x2 – 7 = 9 z2 + 13 = 5

Solve x2 – 50 = 0. This quadratic has a squared part and a number part. I'll start by adding the numerical term to the other side of the equaion (so the squared part is by itself), and then I'll square-root both sides. I'll need to remember to simplify the square root:

Solve by rewriting equation Solve 3x2 – 48 = 0 3x2 – 48 + 48 = 0 + 48 3x2 = 48 3x2 / 3 = 48 / 3 x2 = 16 After taking square root of both sides, x = ± 4

Solving Quadratics by Using Square Roots Solve each equation. Ex. 5 Ex. 6 Ex. 7 Can’t take the square root of a negative.

Solving Quadratics by Using Square Roots Solve the following for x. Ex. 4 Add 98 to both sides. Divide both sides by 2. Square root both sides. Remember: When you square root something, it gives you a plus and a minus answer.

Example 3: Solve 2x2 + 5 = 15

Example 4: Solve 3(x + 3)2 = 39

You Try: w2 – 9 = 0 4r2 – 7 = 9 2(y + 4)2 = 18

Equation of a falling object When an object is dropped, the speed with which it falls continues to increase. Ignoring air resistance, its height h can be approximated by the falling object model. h is the height in feet above the ground t is the number of seconds the object has been falling s is the initial height from which the object was dropped

Application An engineering student is in an “egg dropping contest.” The goal is to create a container for an egg so it can be dropped from a height of 32 feet without breaking the egg. To the nearest tenth of a second, about how long will it take for the egg’s container to hit the ground? Assume there is no air resistance.

The question asks to find the time it takes for the container to hit the ground. Initial height (s) = 32 feet Height when its ground (h) = 0 feet Time it takes to hit ground (t) = unknown

Substitute 0 = -16t2 + 32 -32 + 0 = -16t2 + 32 – 32 -32 = -16t2 -32 / -16 = -16t2 / -16 2 = t2 t = √2 seconds or approx. 1.4 seconds

Solving Quadratic Equations by Completing the Square

Perfect Square Trinomials Examples x2 + 6x + 9 x2 - 10x + 25 x2 + 12x + 36

Creating a Perfect Square Trinomial In the following perfect square trinomial, the constant term is missing. X2 + 14x + ____ Find the constant term by squaring half the coefficient of the linear term. (14/2)2 X2 + 14x + 49

Perfect Square Trinomials Create perfect square trinomials. x2 + 20x + ___ x2 - 4x + ___ x2 + 5x + ___ 100 4 25/4

Solving Quadratic Equations by Completing the Square Solve the following equation by completing the square: Step 1: Move quadratic term, and linear term to left side of the equation

Solving Quadratic Equations by Completing the Square Step 2: Find the term that completes the square on the left side of the equation. Add that term to both sides.

Solving Quadratic Equations by Completing the Square Step 3: Factor the perfect square trinomial on the left side of the equation. Simplify the right side of the equation.

Solving Quadratic Equations by Completing the Square Step 4: Take the square root of each side

Solving Quadratic Equations by Completing the Square Step 5: Set up the two possibilities and solve

Completing the Square-Example #2 Solve the following equation by completing the square: Step 1: Move quadratic term, and linear term to left side of the equation, the constant to the right side of the equation.

Solving Quadratic Equations by Completing the Square Step 2: Find the term that completes the square on the left side of the equation. Add that term to both sides. The quadratic coefficient must be equal to 1 before you complete the square, so you must divide all terms by the quadratic coefficient first.

Solving Quadratic Equations by Completing the Square Step 3: Factor the perfect square trinomial on the left side of the equation. Simplify the right side of the equation.

Solving Quadratic Equations by Completing the Square Step 4: Take the square root of each side

Ex 4 Solve by completing the square

Solving Quadratic Equations by Completing the Square: Try the following examples. Do your work on your paper and then check your answers.

Solving Equations by graphing When we talk about solving these equations, we want to find the value of x when y = 0. These values, where the graph crosses the x-axis, are called the x-intercepts. These values are also referred to as solutions, zeros, or roots.

Quadratic Solutions The number of real solutions is at most two. No solutions One solution Two solutions

Graphing Quadratic Equations The graph of a quadratic equation is a parabola. The roots or zeros are the x-intercepts. The vertex is the maximum or minimum point. All parabolas have an axis of symmetry.

Vertex: (-1, 9) Roots: (-4, 0) (2, 0) Viewing window: Xmin= -10 Graph y= -x2 - 2x + 8 and find its roots. Vertex: (-1, 9) Roots: (-4, 0) (2, 0) Viewing window: Xmin= -10 Xmax=10 Ymin= -10 Ymax= 10

Identifying Solutions Example f(x) = x2 - 4 Solutions are -2 and 2.

Identifying Solutions Now you try this problem. f(x) = 2x - x2 Solutions are 0 and 2.

Graphing Quadratic Equations Graph y = x2 - 4x Roots 0 and 4 , Vertex (2, -4) , Axis of Symmetry x = 2

Solving Quadratics by Graphing

Solving Quadratics by Graphing Ex. 3

I can solve quadratic equations by graphing. I can solve quadratic equations by using square roots.