Success Criteria:  I can use number operations to find and compare lengths  I can use the ruler and segment addition postulate to reason about length.

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Presentation transcript:

Success Criteria:  I can use number operations to find and compare lengths  I can use the ruler and segment addition postulate to reason about length Warm Up Solve each equation. 1. 2x + 3 = 9x – x = 4x – 5 1. Do Now 2. Check HW #1 3. Log on to Pearson book 4.Subscribe to calendar 5.Lesson HW - #2 2 5

coordinate. A point corresponds to one and only one number on a ruler.

The distance between any two points is the absolute value of the difference of the coordinates. If the coordinates of points A and B are a and b, then the distance between A and B is |a – b| or |b – a|. The distance between A and B is also called the length of AB, or AB. AB = |a – b| or |b - a| A a B b

Congruent segments are segments that have the same length. In the diagram, PQ = RS, so you can write PQ  RS. This is read as “segment PQ is congruent to segment RS.” Tick marks are used in a figure to show congruent segments.

In order for you to say that a point B is between two points A and C, all three points must lie on the same line, and AB + BC = AC.

Example 1: Finding the Length of a Segment Find each length. = 2 A. BCB. AC = |1 – 3| BC = |1 – 3| = 5 = |– 5| AC = |–2 – 3|

Example 2: Using the Segment Addition Postulate G is between F and H, FG = 6, and FH = 11. Find GH. 5 = GH FH = FG + GH Seg. Add. Postulate 11 = 6 + GH – 6 –6 Substitute 6 for FG and 11 for FH. Subtract 6 from both sides. Simplify.

Example 3: Using the Segment Addition Postulate M is between N and O. Find NO. 10 = 2x NM + MO = NO Seg. Add. Postulate 17 + (3x – 5) = 5x + 2 – 2 – 2 Substitute the given values Subtract 2 from both sides. Simplify. 3x + 12 = 5x + 2 3x + 10 = 5x –3x –3x = x Simplify. Subtract 3x from both sides. Divide both sides by 2.

Example 3 Continued M is between N and O. Find NO. NO = 5x + 2 Substitute 5 for x. Simplify. = 27 = 5(5) + 2

E is between D and F. Find DF. Check It Out! Example 4 DE + EF = DF Seg. Add. Postulate (3x – 1) + 13 = 6x – 3x Substitute the given values Subtract 3x from both sides. 3x + 12 = 6x 12 = 3x 4 = x Simplify. Divide both sides by x 3 3 =

E is between D and F. Find DF. Check It Out! Example 4 Continued DF = 6x Substitute 4 for x. Simplify. = 24 = 6(4)

Assignment #2 Pg #9-29 odds, 35, , odds iReady