MATHPOWER TM 12, WESTERN EDITION 5.5 5.5.1 Chapter 5 Trigonometric Equations.

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Presentation transcript:

MATHPOWER TM 12, WESTERN EDITION Chapter 5 Trigonometric Equations

5.5.2 Sum and Difference Identities sin(A + B) = sin A cos B + cos A sin B sin(A - B) = sin A cos B - cos A sin B cos(A + B) = cos A cos B - sin A sin B cos(A - B) = cos A cos B + sin A sin B

5.5.3 Simplifying Trigonometric Expressions Express cos cos sin 80 0 sin as a trig function of a single angle. This function has the same pattern as cos (A - B), with A = and B = cos 100 cos 80 + sin 80 sin 100 = cos( ) = cos 20 0 Express as a single trig function. This function has the same pattern as sin(A - B), with 1. 2.

5.5.4 Finding Exact Values 1. Find the exact value for sin Think of the angle measures that produce exact values: 30 0, 45 0, and Use the sum and difference identities. Which angles, used in combination of addition or subtraction, would give a result of 75 0 ? sin 75 0 = sin( ) = sin 30 0 cos cos 30 0 sin 45 0

5.5.5 Finding Exact Values 2. Find the exact value for cos cos 15 0 = cos( ) = cos 45 0 cos sin 45 0 sin Find the exact value for

5.5.6 Using the Sum and Difference Identities Prove L.S. = R.S.

5.5.7 Using the Sum and Difference Identities x = 3 r = 5 r 2 = x 2 + y 2 y 2 = r 2 - x 2 = = 16 y = ± 4

5.5.8 Using the Sum and Difference Identities xyrxyr A B

5.5.9 Double-Angle Identities sin 2A = sin (A + A) = sin A cos A + cos A sin A = 2 sin A cos A cos 2A = cos (A + A) = cos A cos A - sin A sin A = cos 2 A - sin 2 A The identities for the sine and cosine of the sum of two numbers can be used, when the two numbers A and B are equal, to develop the identities for sin 2A and cos 2A. Identities for sin 2x and cos 2x: sin 2x = 2sin x cos xcos 2x = cos 2 x - sin 2 x cos 2x = 2cos 2 x - 1 cos 2x = 1 - 2sin 2 x

Double-Angle Identities Express each in terms of a single trig function. a) 2 sin 0.45 cos 0.45 sin 2x = 2sin x cos x sin 2(0.45) = 2sin 0.45 cos 0.45 sin 0.9 = 2sin 0.45 cos 0.45 b) cos sin 2 5 cos 2x = cos 2 x - sin 2 x cos 2(5) = cos sin 2 5 cos 10 = cos sin 2 5 Find the value of cos 2x for x = cos 2x = cos 2 x - sin 2 x cos 2(0.69) = cos sin cos 2x =

Double-Angle Identities Verify the identity L.S = R.S.

Double-Angle Identities Verify the identity L.S = R.S.

Double-Angle Equations y = cos 2A 22 

Double-Angle Equations y = sin 2A

Graph the function Using Technology and predict the period. The period is  Rewrite f(x) as a single trig function:f(x) = sin 2x

Prove Identities L.S. = R.S

Applying Skills to Solve a Problem The horizontal distance that a soccer ball will travel, when kicked at an angle , is given by, where d is the horizontal distance in metres, v 0 is the initial velocity in metres per second, and g is the acceleration due to gravity, which is 9.81 m/s 2. a) Rewrite the expression as a sine function. Use the identity sin 2A = 2sin A cos A:

b) Find the distance when the initial velocity is 20 m/s. Applying Skills to Solve a Problem [cont’d] Distance Angle  From the graph, the maximum distance occurs when  = The maximum distance is m. The graph of sin  reaches its maximum when Sin 2  will reach a maximum when

Suggested Questions: Pages A 1-16, odd B 17-24, 37-40, 43, 47,