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MAT 1235 Calculus II Section 9.3 Separable Equations II Version 2

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Presentation on theme: "MAT 1235 Calculus II Section 9.3 Separable Equations II Version 2"— Presentation transcript:

1 MAT 1235 Calculus II Section 9.3 Separable Equations II Version 2 http://myhome.spu.edu/lauw

2 HW WebAssign 9.3 Part II (A) Due Tomorrow (4 problems, 74 min.) WebAssign 9.3 Part II (B) Due Monday (2 problems, 34 min.) Quiz: 9.3 Part II

3 Preview (Version 2, No second order chemical reaction) We are going to look into some applications of Separable Equations.

4 Example 1: Mixtures A tank contains 20 kg of salt dissolved in 5000 L of water. Brine that contains 0.03 kg of salt per liter of water enters the tank at a rate of 25 L/min.

5 Example 1: Mixtures The solution is kept thoroughly mixed and drains from the tank at the same rate. How much salt remains in the tank after half an hour?

6 Example 1: Mixtures Step 1 Define the variable.

7 Example 1: Mixtures Step 2 Find rate in and rate out.

8 Example 1: Mixtures Step 3 Set up the DE and solve it with the initial condition. (Do not erase this part!)

9 Example 1: Mixtures Step 4 Compute the amount of salt after 30 min. Conclusion:

10 Example 1: Mixtures Changes over time…

11 Example 2: Mixtures The air in a room with volume 180 m 3 contains 0.15% carbon dioxide initially. Fresher air with only 0.05% carbon dioxide flows into the room at a rate of 2 m 3 /min and the mixed air flows out at the same rate.

12 Example 2: Mixtures Find the percentage of carbon dioxide in the room as a function of time. What happens in the long run?

13 Example 2: Mixtures Step 1 Define the variable. (Note that percentage is a ratio, it does not make sense to talk about rate in, rate out.)

14 Example 2: Mixtures Step 2 Find rate in and rate out.

15 Example 2: Mixtures Step 3 Set up the DE and solve it with the initial condition.

16 Example 2: Mixtures Step 3 Set up the DE and solve it with the initial condition. (In WebAssign…)

17 Example 2: Mixtures Step 4 Compute the percentage of carbon dioxide in the long run? Conclusion:


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