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Published byBeryl Owen Modified over 5 years ago

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Objective The student will be able to: solve equations using multiplication and division. Designed by Skip Tyler, Edited by Mr. Nealey

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1) Solve. -5t = 60 To get the variable by itself, which number needs to be moved? -5 To move the -5, you have to do the opposite operation. What operation will we use? division

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1) Solve -5t = 60 -5 -5 t = -12 -5(-12) = 60 1.Draw a line to separate the equation into 2 sides 2.Inverse Operations: Divide both sides by -5 3.Simplify 4.Check your answer

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2) Solve 15 = 6n 6 6 2.5 = n 15 = 6(2.5) 1.Draw a line. 2.Inverse Operations: Divide both sides by 6 3.Simplify 4.Check your answer

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3) Solve -3v = -129 1.v = -126 2.v = -43 3.v = 43 4.v = 126 Answer Now

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4) Solve You don’t like fractions? Let’s get rid of them! “Clear the fraction” by multiplying both sides of the equation by the denominator.

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4) Solve 4 · · 4 x = -48 1.Draw a line 2.Clear the fraction – multiply both sides by 4 3.Simplify 4.Check your answer

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3 · = 18 · 3 2x = 54 2 2 x = 27 1.Draw a line 2.Clear the fraction – multiply both sides by 3 3.Simplify 4.Inverse Operations: Divide both sides by 2 5.Simplify 6.Check your answer 5) Solve = 18

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6) Which step clears the fraction in 1.Multiply by 3 2.Multiply by 5 3.Multiply by -12 4.Multiply by -5 Answer Now

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7) Solve 1.b = -56 2.b = -14 3.b = 14 4.b = 56 Answer Now

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