Download presentation

Presentation is loading. Please wait.

Published byKatelyn Nash Modified over 2 years ago

1
C.L.I.L. MODULE: ANALYSIS AND DESIGN OF FIRST ORDER RC FILTERS Subjects: ELECTRONICS/ENGLISH Teachers: Miria Bovino and Roberto Versari Class: 4AEL ISTITUTO TECNICO INDUSTRIALE STATALE GUGLIELMO MARCONI - Forlì School Year 2009/2010

2
Outline of the CLIL module Lesson 1: RC low pass filter schematic and transfer function (with C.A.D. example) Lesson 2: frequency response graphical representation (with excel example) Lesson 3: Analysis of the CR high-pass filter (with excel + C.A.D. example) Lesson 4: An introduction to active filters and circuit simulations (with C.A.D. example) Istituto Tecnico Industriale Statale G. Marconi - Forlì

3
Lesson 1 Targets: Istituto Tecnico Industriale Statale G. Marconi - Forlì Lesson 1: RC low pass filter schematic and transfer function (2h) Learn how to draw the schematic of an RC low-pass filter. Learn how to calculate its transfer function G(jw) Learn the filter constant time ( ) definition Learn how to calculate the RC low-pass filter output for any sinusoidal input. Learn how to realize an RC low pass filter with a C.A.D. tool

4
The first order passive RC low pass filter is made of only two components: Istituto Tecnico Industriale Statale G. Marconi - Forlì RC low pass filter schematic VO(jw) VI(jw) R C stimulus or input sinusoidal voltage output sinusoidal voltage VI and VO can be represented by the corresponding vector quantities: VI=V I e j, VO= V O e j OI

5
Transfer function calculation (1/2) Istituto Tecnico Industriale Statale G. Marconi - Forlì The RC low pass filter can be easily seen as a simple impedance divider with Z 1 =R and Z 2 =1/jwC The impedance divider formula provides: VO/VI=Z 2 /(Z 1 +Z 2 ). VO/VI is the transfer function G(jw) of the RC filter. Hence it is: G(jw)=Z 2 /(Z 1 +Z 2 ) VO(jw) VI(jw) Z 1 =R Z 2 =1/jwC

6
Transfer function calculation (2/2) Istituto Tecnico Industriale Statale G. Marconi - Forlì Lets substitute Z 1 =R and Z 2 =1/jwC in G(jw) expression R C= [s] is defined as the time constant of the low-pass filter. Hence:.

7
Output calculation (1/2) Istituto Tecnico Industriale Statale G. Marconi - Forlì G(jw) is a complex number with: Amplitude: Phase: VO=G(jw) VI can be written using complex numbers properties:. VO Amplitude: VO Phase: G(jw) depends only on and f (input signal frequency)

8
Output calculation (2/2) Istituto Tecnico Industriale Statale G. Marconi - Forlì. V I, I, f RC low-pass filter =R CV O, O, f sinusoidal inputsinusoidal output 1) V I, I and f are given 2) the filter schematic is known is calculated. 3) f and are known G(jw) and G(jw) are calculated 4) V O =|G(jw)| V I is calculated 5) O = G(jw) + I is calculated G(jw).

9
Output calculation example Istituto Tecnico Industriale Statale G. Marconi - Forlì Exercise: calculate the output VO of the circuit corresponding to the given sinusoidal input VI 1) V I =1V, I =0 0, f=10KHz 2) =RC=320 *50nF=16 s 3) |G(10KHz)|=1/ 1+(2* *10KHz*16 s) 2 =0,7 G(10KHz) =-artg(2* *10KHz*16 s)= ) V O =0,7*1V=0,7V 5) O = =-45 0 The output voltage is attenuated of a factor of 0,7 and delayed of 45 degrees when f=10KHz. remember:

10
LTspiceIV CAD tool Istituto Tecnico Industriale Statale G. Marconi - Forlì Download free from: CAD tools: schematic implementation and real time simulation needed to decrease electronic circuit time to market. English language prerequisite for most CAD tools.

11
Lesson 2 Targets: Istituto Tecnico Industriale Statale G. Marconi - Forlì Lesson 2: RC low pass filter frequency response graphical representation (2h) Learn the graphical method to calculate any filter output. Learn the low-pass filter cutoff frequency (f C ) definition, its bandwidth (Bw) and the relationship between f C and. Learn how to read and draw first-order low pass filters amplitude diagrams in logarithmic scale. Learn how to design an RC low-pass filter for a given bandwidth and/or f C. Learn how to draw the amplitude and phase diagrams of first-order RC low-pass filters with MS-excel.

12
Istituto Tecnico Industriale Statale G. Marconi - Forlì The graphical approach to the calculation of filter output Lesson 1 result: the filter output voltage can be derived by the knowledge of the input voltage and the analitycal calculation of the filter transfer function G(jw) – both amplitude and phase. Disadvantages of the analitycal approach: - two calculations (amplitude and phase) for each input frequency. - G(jw) analitycal expression depends on filter topology. New graphical approach: two plots, namely |G(jw)| vs. f and G(jw) vs. f are associated to each filter. The calculation of the output voltage does not need G(jw) value calculation because the values of amplitude and phase of G(jw) at the given frequency can be simply read from the two given plots of the filter.

13
Amplitude and Phase diagrams Istituto Tecnico Industriale Statale G. Marconi - Forlì |G(jw)| vs. f is the filter amplitude diagram*. *=remember that: G(jw) vs. f is the filter phase diagram* Examples of amplitude and phase diagrams of an RC low pass filter with R=1K and C=1 F.

14
Output amplitude calculation with graphical method (1/2) Istituto Tecnico Industriale Statale G. Marconi - Forlì V I, f RC low-pass filter amplitude diagram V O, f sinusoidal inputsinusoidal output 1) V I, I and f are given 2) the filter amplitude diagram value at the frequency f can be read from the plot. 3) V O =|G(jw)| V I is easily calculated, since |G(jw)| is the value read from the plot in step 2)..

15
Output amplitude calculation with graphical method (2/2) Istituto Tecnico Industriale Statale G. Marconi - Forlì Case 1): V I =1,5V I =0 0 f=100Hz From the filter amplitude diagram at f=100Hz we read |G(jw)| =0,8. Hence the output voltage amplitude at f=100Hz is V O =0,8*1,5V=1,2V Case 2): V I =1,5V I =0 0 f=1KHz From the filter amplitude diagram at f=1KHz we read |G(jw)| =0,18. Hence the output voltage amplitude at f=1KHz is V O =0,18*1,5V=0,27V

16
Output phase calculation with graphical method (1/2) Istituto Tecnico Industriale Statale G. Marconi - Forlì I, f RC low-pass filter phase diagram O, f sinusoidal inputsinusoidal output 1) V I, I and f are given 2) the filter phase diagram value at the frequency f can be read from the plot. 3) O = G(jw) + I is easily calculated, since G(jw) is the value read from the plot in step 2).

17
Output phase calculation with graphical method (2/2) Istituto Tecnico Industriale Statale G. Marconi - Forlì Case 1): V I =1,5V I =0 0 f=100Hz From the filter phase diagram at f=100Hz we read G(jw) = Hence the output voltage phase at f=100Hz is O = = Case 2): V I =1,5V I =0 0 f=1KHz From the filter phase diagram at f=1KHz we read G(jw) = Hence the output voltage phase at f=1KHz is O = =-81 0 Graphical method advantages: - no need to calculate amplitude and phase: they are simply read from the plots. - it is a general approach valid for all kind of filters: it is only needed the knowledge of the amplitude and phase plots.

18
Amplitude diagram analysis Istituto Tecnico Industriale Statale G. Marconi - Forlì 1) The cutoff frequency f C is defined as the frequency value at which |G(jw)|=0,7 In fact, all input signals with f f C are cut, i.e. the filter output has an amplitude significantly lower than the input. 2) The filter band B is defined as the range of input frequencies for which the filter attenuation is 0,7. In practice B=[0, f C ]. The bandwidth is the width of B=f C -0=f C 3) The relationship between f C and is: frequency scale is logarithmic f C =160Hz pass band B stop band

19
Phase diagram analysis Istituto Tecnico Industriale Statale G. Marconi - Forlì The cutoff frequency f C corresponds to the frequency value at which G(jw) = The filter introduces a maximum phase shift (a delay) of –90 0. All input signals with frequencies within the filter pass band [0, f C ] are delayed less than 45/(360*f)=0,125/f. Input signals with frequencies outside the filter pass band are delayed more than 0,125*f, with a maximum delay of 0,25/f corresponding to the maximum phase shift of –90 0. frequency scale is logarithmic f C =160Hz

20
Why a frequency logarithmic scale? Istituto Tecnico Industriale Statale G. Marconi - Forlì 1) frequency logarithmic scale: the whole waveform is clearly outlined and the amplitude values at different frequencies can be read with reasonable accuracy 2) frequency linear scale: the amplitude values at different frequencies cannot be read so the graph is useless. The same considerations hold for the phase plot. f C =160Hz frequency linear scale frequency log. scale

21
Whole logarithmic scale: the Bode plot Istituto Tecnico Industriale Statale G. Marconi - Forlì Analitycal formula for output calculation: V O = G(jw) V I. Normalization (dimensionless): V O /1V= G(jw) V I /1V. logarithmic: 20Log(V O /1V)=20Log G(jw) +20Log(V I /1V) Output calculation in dB: V O [dBV]= G(jw) [dB]+V I [dBV] |G(jw)|[dB] vs. f is Bode plot It is a full log. diagram. f=f C |G(jw)|=-3dB (in fact, 20Log(0,7)=-3dB). When f>f C Bode plot slope is 20dB/dec. f C =160Hz 1dec 20dB

22
Bode plot representation advantages Istituto Tecnico Industriale Statale G. Marconi - Forlì Very simple output calculation: V O =|G(jw)|+V I [dB] (only a sum) Very easy to draw!!! it can be approximated by: |G(jw)|=0 for f

23
Design for a given f C or B Istituto Tecnico Industriale Statale G. Marconi - Forlì The design of a first order RC low pass filter for a given f C or B is very simple: 1) calculate the filter time constant: 2) Choose a capacitor value among those available in the laboratory: for instance, C=1 F. 3) calculate the corresponding value of R: 4) if R is in the [100,100K] range OK!!!, otherwise go back to point 2) choosing another C value. Example: design a low pass filter with f C =1KHz. 1)2)3)4) OK!!!

24
How to use MS-excel to draw Amplitude and Phase diagrams Istituto Tecnico Industriale Statale G. Marconi - Forlì Electronic sheet tools are useful for automated calculations and diagram representations very useful for transfer function plot drawings.

25
Lesson 3 Targets: Istituto Tecnico Industriale Statale G. Marconi - Forlì Lesson 3: Analysis of the CR high-pass filter (2h) Learn the schematic of a high-pass CR filter and its transfer function G(jw) Learn how to draw the amplitude and phase plots of the filter Learn the relationship between, f C and B of the filter Learn how to calculate the output of the filter Learn how to design the filter Learn how to simulate the filter with CAD tools in English language.

26
First-order passive CR high-pass filter schematic: Istituto Tecnico Industriale Statale G. Marconi - Forlì CR high pass filter schematic VO(jw) VI(jw) VI=V I e j i VO=V O e j o Same schematic as the RC low pass filter but with R and C interchanged. Using the same impedance divider model: G(jw)=VO(jw)/VI(jw)=Z 2 /(Z 1 + Z 2 ), where Z 1 =1/jwC and Z 2 =R. After a few mathematics we get: =RC=0,16ms same formula as the low pass filter

27
Amplitude and Phase diagrams Istituto Tecnico Industriale Statale G. Marconi - Forlì f C and B are defined in the same way as the RC low pass. However, B=[f C, ] because the filter attenuates only the frequencies < f C, significantly. f C =1KHz 1dec 20dB B=[f C, ] f C =1KHz G(fc) =+45 0 |G(f C )| = -3dB

28
Diagrams characteristics Istituto Tecnico Industriale Statale G. Marconi - Forlì Amplitude: B= [f C, ] because signals are not attenuated when f>f C. Bw=. |G(f C )|=-3dB (corresponding to a 0,7* attenuation) when f

29
Filter design and Bode plot drawing Istituto Tecnico Industriale Statale G. Marconi - Forlì The filter design for a given f C can be done using the same 4 steps algorithm as the low pass filter: 1) calculate the filter time constant: 2) Choose a capacitor value among those available in the laboratory: for instance, C=1 F. 3) calculate the corresponding value of R: 4) if R [100,100K] OK!!!, otherwise go back to point 2) choosing another C value available. |G(jw)| [dB] f (log) fCfC 0,1f C 0,01f C 0,001f C 0dB -20dB -40dB -60dB Bode plot drawing: |G(jw)|=0 for f>f C horizontal line |G(jw)|=20*Log(f/f C ) straight line with slope +20dB/dec when f

30
Output calculation examples Istituto Tecnico Industriale Statale G. Marconi - Forlì CR high pass filter with amplitude and phase diagrams of slide 27. V O [dBV]=|G(f)|[dB]+V I [dBV] O = G(f) + I Case 1): V I =1V=0dBV I =0 0 f=100Hz G(100Hz) =83 0. |G(100Hz)|=-20dB V O =-20dB+0dBV=-20dBV=0,1V O = =83 0 Case 2): V I =1V=0dBV I =0 0 f=1000Hz=1KHz G(1KHz) =45 0. |G(1KHz)|=-3dB V O =-3dB+0dBV=-3dBV=0,7V O = =45 0 Case 3): V I =1V=0dBV I =0 0 f=10000Hz=10KHz G(10KHz) =7 0. |G(10KHz)|=-0,09dB V O =-0,09dB+0dBV=-0,09dBV=0,99V O = =7 0

31
Circuit simulation: LTspiceIV Istituto Tecnico Industriale Statale G. Marconi - Forlì LTspiceIV download free from

32
Pros and cons of simulation Istituto Tecnico Industriale Statale G. Marconi - Forlì Simulation advantages: Fast time to market: you do not need to wait physical implementation of the circuit to know its behavior No hand calculations no human error, no interconnection errors Simulation drawbacks: If components models are not accurate the circuit can exhibit unexpected behavior Parasitic components are not included and are circuit layout dependent difficult to predict. Thats what differentiates the good from the bad designer. The Pros are exceedingly better than the Cons: thats why simulation is ALWAYS used to prototype new designs.

33
Lesson 4 Targets: Istituto Tecnico Industriale Statale G. Marconi - Forlì Lesson 4: An introduction to active filters and simulation examples (2h) Learn the main differences between RC passive and active filters. Learn the schematics of low-pass and high-pass RC active filters. Learn the amplitude and phase diagrams of active filters. Learn the schematic and the frequency response diagrams of the pass-band second order RC active filter. Learn how to simulate active filters. Learn some practical applications of filters. Learn the difference between first-order and higher order filters.

34
Istituto Tecnico Industriale Statale G. Marconi - Forlì Passive vs. active filters Lets consider an RC low pass filter connected to a 1K load RL: VO(jw) VO=V O e j o VI(jw) VI=V I e j i The effect of RL is to change Z 2 : Z 2 =C//RL=RL/(1+jwCRL) Consequently G(jw) changes too and becomes: Consequences: 1) Maximum amplitude = 1+R/RL <1 2) f C = (1+R/RL)/2

35
Istituto Tecnico Industriale Statale G. Marconi - Forlì Limits of passive filters The main limits of passive filters are: 1) the frequency response of the filter is dependent on the RL load. In particular, the maximum amplitude of the filter when connected to a load is <1 and load dependent. f C value is load dependent too. 2) the maximum amplitude of a passive filter is =1 (no signal gain) even when not connected to any RL load. Active filters are able to provide both a frequency response independent of any RL load and a signal gain >1. They are obtained adding an active component such as an OP.AMP. (OPerational AMPlifier) to a passive filter.

36
Istituto Tecnico Industriale Statale G. Marconi - Forlì First order low-pass active filter Schematic: Inverting amplifier configuration G(jw)=-Z 2 /Z 1 where Z 1 =R1=159 and Z 2 =C//R2=R2/(1+jw 2 ), 2 =C*R2=0,159ms Advantages: G(jw) independent of any RL (>100 ) connected to filter output VO because of the low OPAMP output resistance Programmable low frequency gain = R2/R1

37
Istituto Tecnico Industriale Statale G. Marconi - Forlì low-pass active filter frequency response Amplitude: Same diagram as passive filter shifted up of 20*Log(R2/R1) Phase: Same diagram as passive filter shifted up of f C is the frequency at which |G| is –3dB with respect to its low frequency value (same definition used for amplifiers): |G(f C )|=|G(0)|-3dB. When f= f C G (f C ) = G (0) – 45 0 f C =1KHz |G(f C )|=17dB G (f C )=135 0

38
Istituto Tecnico Industriale Statale G. Marconi - Forlì First order high-pass active filter Schematic: G(jw)=-Z 2 /Z 1 where Z 2 =R2=1,59K and Z 1 =R1+1/jwC=(1+jw 1 )/jwC, 1 =C*R1=0,159ms 2 =C*R2=1,59ms High frequency gain = 2 / 1 =R2/R1 Independent of load RL (if RL>100 )

39
Istituto Tecnico Industriale Statale G. Marconi - Forlì high-pass active filter frequency response Amplitude: Same diagram of passive filter shifted up of 20*Log(R2/R1) Phase: Same diagram of passive filter shifted up of f C is the frequency at which |G| is –3dB with respect to its high frequency value: |G(f C )|=|G(f= )|-3dB. When f= f C G (f C ) = G (0) – 45 0 f C =1KHz |G(f C )|=17dB G (f C )=225 0

40
Istituto Tecnico Industriale Statale G. Marconi - Forlì Whats a pass-band active filter? Low-pass filter: only low frequency inputs are not attenuated. High-pass filter: only high frequency inputs are not attenuated. Pass-band only frequency inputs [f1,f2] are not attenuated. B=[f1,f2] is the pass-band of the filter. Simpler pass-band filter: cascade of low-pass + high-pass filters: f C1 INPUT SIGNAL f C2 OUTPUT SIGNAL frequencies above f C1 are attenuated frequencies above f C1 and below f C2 are attenuated low-pass with f C =f C1 high-pass with f C =f C2 Works only if f C2 >f C1 ; It doesnt matter if low-pass is first or second in the cascade if they are active filters.

41
Istituto Tecnico Industriale Statale G. Marconi - Forlì Second order pass-band active filter Schematic: G(jw)=-Z 2 /Z 1 where Z 2 =R2//C2=R2/(1+ jw 2 ) Z 1 =R1+1/jwC1=(1+jw 1 )/jwC1, 1 =C1*R1=30 s 2 =C2*R2=9.54 s 12 =C1*R2=47,7 s Filter pass-band B=[f C1,f C2 ], with f C1

42
Istituto Tecnico Industriale Statale G. Marconi - Forlì Pass-band active filter frequency response The Bode plot of the pass-band active filter is exactly the sum of the Bode plots of the low-pass and high-pass active filters with the same 2 and 1, respectively. f C1 =5,3K G (f C1 )=205 0 f C2 =16,7K G (f C2 )=155 0 The phase diagram of the pass-band active filter is the sum decreased of of the phase diagrams of the low-pass and high-pass active filters with the same 2 and 1, respectively.

43
Istituto Tecnico Industriale Statale G. Marconi - Forlì Filter simulation: passive vs. active The RL load does not affect active filter response while it affects both amplitude and phase response of the passive filter. Without RL the two responses C1 C2 are the same.

44
Istituto Tecnico Industriale Statale G. Marconi - Forlì Filter simulation: pass-band C2 Average value of input square waveform cut. High frequency components cut too. Output is almost sinusoidal (depends on filter selectivity). C1

45
Istituto Tecnico Industriale Statale G. Marconi - Forlì Filter applications: ADSL modem 6 th order low-pass You can phone while browsing the Internet!!! The phone signal doesnt disturb the ADSL signal because of the high-pass filter embedded in the ADSL module. The ADSL signal doesnt disturb the phone signal because of the low-pass filter inserted just before the phone receiver.

46
Istituto Tecnico Industriale Statale G. Marconi - Forlì Filter applications: audio systems audio signal [0,20KHz] cross-over low-pass [0,3KHz] cross-over high-pass [3K,20K] woofer (bass) tweeter (high) A Hi-Fi (High Fidelity) audio system is composed of at least two different speakers: a woofer to reproduce bass sounds and a tweeter for the high sounds. A cross-over filter is placed before each speaker so that the speaker can be reached only by the frequency components of the input audio signal it is able to reproduce. Cross-over filters are typically 2 nd or 3 rd order low-pass or high-pass filters.

47
Higher order filters. Istituto Tecnico Industriale Statale G. Marconi - Forlì In practical applications 2 nd or higher order filters are typically used because of their higher selectivity: Low-pass filter attenuation at f=10*f C is: 1 st order nd order rd order The higher the order of the filter the better its ability to select only the frequencies within its pass band B. |G(jw)| [dB] f (log) fCfC 10f C 100f C 1000f C 0dB -20dB -40dB -60dB 1 st order: -20dB/dec 2 nd order: -40dB/dec 3 rd order: -60dB/dec Note: the order of a filter is equal to the number of reactive components in its schematic (i.e. the number of poles of its transfer function).

48
Bibliography (1/3) Istituto Tecnico Industriale Statale G. Marconi - Forlì The following list of references can be used for an in-depth investigation of the subject of the presentation: 1.The Analysis and Design of Linear Circuits, 6th Edition, R. E. Thomas, A. J. Rosa, G. J. Toussaint, ISBN: , (basic textbook on linear circuits analysis with a complete chapter on AC analysis and Bode plots of analog filters). 2.http://www.animations.physics.unsw.edu.au/jw/RCfilters.htmlhttp://www.animations.physics.unsw.edu.au/jw/RCfilters.html (basic analysis of RC filters with animations). 3.http://www.play-hookey.com/ac_theory/filter_basics.html (basic theory of active and passive filters).http://www.play-hookey.com/ac_theory/filter_basics.html 4.http://www.educypedia.be/electronics/analogfil.htm (link to several resources on analog filters, both passive and active).http://www.educypedia.be/electronics/analogfil.htm

49
Bibliography (2/3) Istituto Tecnico Industriale Statale G. Marconi - Forlì 03Sp09_L05_Filters.pdf (lecture on basic filter topologies and solutions). 03Sp09_L05_Filters.pdf 6.http://dev.emcelettronica.com/performing-ac-analysis-ltspice (method to perform an AC analysis of an RC filter with Ltspice)http://dev.emcelettronica.com/performing-ac-analysis-ltspice roToFilters.pdfhttp://www.swarthmore.edu/NatSci/echeeve1/Ref/DataSheet/Int roToFilters.pdf (basic introduction to analog filters from National Semiconductor Corp., with examples of real analog filters IC's and criteria to select among filter topologies). 8.Active Filter Cookbook, D. Lancaster, 2nd ed. Thatcher, Synergetics Press, 1995 (a comprehensive textbook on active filter design and analysis) 5. 7.

50
Bibliography (3/3) Istituto Tecnico Industriale Statale G. Marconi - Forlì 9. (analysis of the bode plots of an RC low pass filter) (chapter on Bode plot analysis of linear systems with stability criteria).http://www.che.ttu.edu/pcoc/software/ppt/Chap09.ppt 11. (lecture on Bode plots and second order linear systems)http://eprints.iisc.ernet.in/13500/1/lec_5_web.pdf

Similar presentations

© 2017 SlidePlayer.com Inc.

All rights reserved.

Ads by Google