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Review Chapter 6: Oxidation & Reduction Reactions Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop.

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Presentation on theme: "Review Chapter 6: Oxidation & Reduction Reactions Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop."— Presentation transcript:

1 Review Chapter 6: Oxidation & Reduction Reactions Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop

2 Chapter 7 Concepts 2  Be familiar with Potential and Kinetic Energy  Potential Energy changes as bonds break and form  Average KE is proportional to Temperature  Conservation of Energy  Define system vs surroundings  Track direction of heat transfer between system and surroundings  Heat capacity calculations  Specific heat calculations  Exothermic vs Endothermic  Heats of reactions:  Calorimetry problems, q v vs q p  First Law of Thermodynamics  Define Enthalpy  Enthalpy calculations:  Hess’s law  ΔH f ΔH rxn

3 Memorize Total Energy Potential Energy Kinetic Energy = + A calorie (cal) Energy needed to raise the temperature of 1 g H 2 O by 1 °C 1 cal = 4.184 J (exactly) 1 kcal = 1000 cal 1 kcal = 4.184 kJ 1 Cal = 1000 cal = 1 kcal 1 kcal = 4.184 kJ  E = E final – E initial T (K)  Avg KE = ½ mv avg 2 q = C ×  t q = s  m   t Work = –P ×  V  E = q + w H = E + PV  H° reaction = – Sum of all  H° f of all of the products Sum of all  H° f of all of the reactants

4 Endothermic & Exothermic PE Reactants Products EXOTHERMIC ENDOTHERMIC Heat released Heat absorbed ENDOTHERMIC Heat + Reactants  Products Products have stronger bonds and therefore a higher potential energy then Reactants. Heat is absorbed by the system. ΔE +ΔH + EXOTHERMIC Reactants  Products + heat Products have weaker bonds and therefore a lower potential energy then Reactants. Heat is released by the system. ΔE - ΔH - PE increases as bonds break PE decreases as bonds form System Surroundings System Surroundings heat

5 System & Surroundings Open system Closed system System Surroundings heat Constant Volume q v ΔE Constant Pressure q p ΔH q system = –q surroundings

6 Hess’s Law Hess’s Law of Heat Summation Going from reactants to products Enthalpy change is same whether reaction takes place in one step or many Reactants Products Path 1 Path 2 step b Path 2 step b Sum of Enthalpies from steps in path 2 = Path 1 Enthalpy

7 Manipulating Thermochemical Rxns aA (state) + bB (state)  cC (state) + dD (state) ΔH 1.When equation is reversed, sign of  H° rxn must also be reversed. 2.If all coefficients of equation are multiplied or divided by same factor, value of  H° rxn must likewise be multiplied or divided by that factor 3.Formulas canceled from both sides of equation must be for substance in same physical states

8 Strategy for Adding Thermochemical Rxns 1.Choose most complex compound in equation for one-step path 2.Choose equation in multi-step path that contains that compound 3.Write equation down so that compound  is on appropriate side of equation  has appropriate coefficient for our reaction 4.Repeat steps 1 – 3 for next most complex compound, etc. 5.Choose equation that allows you to  cancel intermediates  multiply by appropriate coefficient 6.Add reactions together and cancel like terms 7.Add energies together, modifying enthalpy values in same way equation modified  If reversed equation, change sign on enthalpy  If doubled equation, double energy


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