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2.5 – Factoring Quadratics Special Cases. Special Case #1: Perfect Squares You can recognize this case because the coefficient of x and the constant are.

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Presentation on theme: "2.5 – Factoring Quadratics Special Cases. Special Case #1: Perfect Squares You can recognize this case because the coefficient of x and the constant are."— Presentation transcript:

1 2.5 – Factoring Quadratics Special Cases

2 Special Case #1: Perfect Squares You can recognize this case because the coefficient of x and the constant are both perfect squares. The coefficient of x has to be 2 x a x b!

3 Factor: = 4 = 3 Check 2x4x3 = 24 4 3

4 7 9 Factor: = 9 = 7 Check 2x9x7 = 126

5 = 2 = 5 5 2 Factor: Check 2x5x2 = 20 Always check for common factors first!

6 = y = 4 y 4 Factor: Check 2 x 4 x y = 8y

7 Special Case #2: Difference of Squares You can recognize this case because there are only two terms and there is always a “-” between them!

8 = 3 3 10 = 10 Factor: 10 3

9 8 8 = 11 11 = 8 11 Factor:

10 1 = 1 5 5 1 = 5 Factor: Always check for common factors first!

11 Homework: P AGE 115 #2 – 12


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