7 DNS: The IP address of “neon.tcpip-lab.edu ” is 188.8.131.52 ARP: What is the MAC address of 184.108.40.206? Sending a packet from Argon to Neon DNS: What is the IP address of “neon.tcpip-lab.edu ” ? ARP: The MAC address of 220.127.116.11 is 00:e0:f9:23:a8:20 18.104.22.168 is not on my local network. Therefore, I need to send the packet to my default gateway with address 22.214.171.124 frame 126.96.36.199 is on my local network. Therefore, I can send the packet directly. ARP: The MAC address of 188.8.131.52 is 00:20:af:03:98:28 ARP: What is the MAC address of 184.108.40.206? frame
8 Communications Architecture The complexity of the communication task is reduced by using multiple protocol layers: Each protocol is implemented independently Each protocol is responsible for a specific subtask Protocols are grouped in a hierarchy A structured set of protocols is called a communications architecture or protocol suite or stack
9 TCP/IP Protocol Suite The TCP/IP protocol suite is the protocol architecture of the Internet The TCP/IP suite has four layers: Application, Transport, Network, and Data Link Layer End systems (hosts) implement all four layers. Gateways (Routers) only have the bottom two layers.
10 Functions of the Layers Data Link Layer: –Service: Reliable transfer of frames over a link Media Access Control on a LAN –Functions: Framing, media access control, error checking Network Layer: –Service: Move packets from source host to destination host –Functions: Routing, addressing Transport Layer: –Service: Delivery of data between hosts –Functions: Connection establishment/termination, error control, flow control Application Layer: –Service: Application specific (delivery of email, retrieval of HTML documents, reliable transfer of file) –Functions: Application specific
11 Layered Communications An entity of a particular layer can only communicate with: 1. a peer layer entity using a common protocol (Peer Protocol) 2. adjacent layers to provide services and to receive services
13 Layers in the Example Send HTTP Request to neon Establish a connection to 220.127.116.11 at port 80 Open TCP connection to 18.104.22.168 port 80 Send a datagram (which contains a connection request) to 22.214.171.124 Send IP datagram to 126.96.36.199 Send the datagram to 188.8.131.52 Send Ethernet frame to 00:e0:f9:23:a8:20 Send Ethernet frame to 00:20:af:03:98:28 Send IP data-gram to 184.108.40.206 Send the datagram to 220.127.116.11 Frame is an IP datagram IP datagram is a TCP segment for port 80
14 Layers and Services Service provided by TCP to HTTP: –reliable transmission of data over a logical connection Service provided by IP to TCP: –unreliable transmission of IP datagrams across an IP network Service provided by Ethernet to IP: –transmission of a frame across an Ethernet segment Other services: –DNS: translation between domain names and IP addresses –ARP: Translation between IP addresses and MAC addresses
15 Encapsulation and Demultiplexing As data is moving down the protocol stack, each protocol is adding layer-specific control information
16 Different Views of Networking Different Layers of the protocol stack have a different view of the network. This is HTTP’s and TCP’s view of the network.
21 ARP and RARP Note: –The Internet is based on IP addresses –Data link protocols (Ethernet, FDDI, ATM) may have different (MAC) addresses The ARP and RARP protocols perform the translation between IP addresses and MAC layer addresses We will discuss ARP for broadcast LANs, particularly Ethernet LANs
24 Address Translation with ARP ARP Request: Argon broadcasts an ARP request to all stations on the network: “What is the hardware address of Router137?”
25 Address Translation with ARP ARP Reply: Router 137 responds with an ARP Reply which contains the hardware address
26 ARP Cache Since sending an ARP request/reply for each IP datagram is inefficient, hosts maintain a cache (ARP Cache) of current entries. The entries expire after 20 minutes. Contents of the ARP Cache: (18.104.22.168) at 00:10:4B:C5:D1:15 [ether] on eth0 (22.214.171.124) at 00:B0:D0:E1:17:D5 [ether] on eth0 (126.96.36.199) at 00:B0:D0:DE:70:E6 [ether] on eth0 (188.8.131.52) at 00:05:3C:06:27:35 [ether] on eth1 (184.108.40.206) at 00:B0:D0:E1:17:DB [ether] on eth0 (220.127.116.11) at 00:B0:D0:E1:17:DF [ether] on eth0
27 Things to know about ARP What happens if an ARP Request is made for a non-existing host? Several ARP requests are made with increasing time intervals between requests. Eventually, ARP gives up. What if a host sends an ARP request for its own IP address? The other machines respond (gratuitous ARP) as if it was a normal ARP request. This is useful for detecting if an IP address has already been assigned.
28 Proxy ARP Proxy ARP: Host or router responds to ARP Request that arrives from one of its connected networks for a host that is on another of its connected networks.
31 Introduction There are many different devices for interconnecting networks
32 Ethernet Hub Used to connect hosts to Ethernet LAN and to connect multiple Ethernet LANs Collisions are propagated
Bridges/LAN switches A bridge or LAN switch is a device that interconnects two or more Local Area Networks (LANs) and forwards packets between these networks. Bridges/LAN switches operate at the Data Link Layer (Layer 2)
Terminology: Bridge, LAN switch, Ethernet switch There are different terms to refer to a data-link layer interconnection device: The term bridge was coined in the early 1980s. Today, the terms LAN switch or (in the context of Ethernet) Ethernet switch are used. Convention: Since many of the concepts, configuration commands, and protocols for LAN switches were developed in the 1980s, and commonly use the old term `bridge’, we will, with few exceptions, refer to LAN switches as bridges. 34
35 Ethernet Hubs vs. Ethernet Switches An Ethernet switch is a packet switch for Ethernet frames Buffering of frames prevents collisions. Each port is isolated and builds its own collision domain An Ethernet Hub does not perform buffering: Collisions occur if two frames arrive at the same time. HubSwitch
36 Routers Routers operate at the Network Layer (Layer 3) Interconnect IP networks
37 Gateways The term “Gateway” is used with different meanings in different contexts “Gateway” is a generic term for routers (Level 3) “Gateway” is also used for a device that interconnects different Layer 3 networks and which performs translation of protocols (“Multi-protocol router”)
38 Interconnecting networks: Bridges versus Routers Routers Each host’s IP address must be configured If network is reconfigured, IP addresses may need to be reassigned Routing done via RIP or OSPF Each router manipulates packet header (e.g., reduces TTL field) Bridges/LAN switches MAC addresses of hosts are hardwired No network configuration needed Routing done by –learning bridge algorithm –spanning tree algorithm Bridges do not manipulate frames
39 Bridges Overall design goal: Complete transparency “Plug-and-play” Self-configuring without hardware or software changes Bridges should not impact operation of existing LANs Three parts to understanding bridges: (1) Forwarding of Frames (2) Learning of Addresses (3) Spanning Tree Algorithm
40 Need for a forwarding between networks What do bridges do if some LANs are reachable only in multiple hops ? What do bridges do if the path between two LANs is not unique ?
41 Transparent Bridges Three principal approaches can be found: –Fixed Routing –Source Routing –Spanning Tree Routing (IEEE 802.1d) We only discuss the last one in detail. Bridges that execute the spanning tree algorithm are called transparent bridges
42 (1) Frame Forwarding Each bridge maintains a MAC forwarding table Forwarding table plays the same role as the routing table of an IP router Entries have the form ( MAC address, port, age), where MAC address: host name or group address port:port number of bridge age:aging time of entry (in seconds) with interpretation: a machine with MAC address lies in direction of the port number from the bridge. The entry is age time units old. MAC addressportage a0:e1:34:82:ca:34 45:6d:20:23:fe:2e 1212 10 20 MAC forwarding table
43 Assume a MAC frame arrives on port x. (1) Frame Forwarding Is MAC address of destination in forwarding table for ports A, B, or C ? Forward the frame on the appropriate port Flood the frame, i.e., send the frame on all ports except port x. Found? Not found ?
44 Routing tables entries are set automatically with a simple heuristic: The source field of a frame that arrives on a port tells which hosts are reachable from this port. (2) Address Learning (Learning Bridges) Port 1 Port 2 Port 3 Port 4 Port 5 Port 6 Src=x, Dest=y x is at Port 3 Src=y, Dest=x Src=x, Dest=y y is at Port 4 Src=x, Dest=y
45 Learning Algorithm: For each frame received, the source stores the source field in the forwarding database together with the port where the frame was received. All entries are deleted after some time (default is 15 seconds). (2) Address Learning (Learning Bridges) Port 1 Port 2 Port 3 Port 4 Port 5 Port 6 x is at Port 3 Src=y, Dest=x y is at Port 4
46 Flooding Can Lead to Loops Switches sometimes need to broadcast frames –Upon receiving a frame with an unfamiliar destination –Upon receiving a frame sent to the broadcast address Broadcasting is implemented by flooding –Transmitting frame out every interface –… except the one where the frame arrived Flooding can lead to forwarding loops –E.g., if the network contains a cycle of switches –Either accidentally, or by design for higher reliability
47 Solution: Spanning Trees Ensure the topology has no loops –Avoid using some of the links when flooding –… to avoid forming a loop Spanning tree –Sub-graph that covers all vertices but contains no cycles
48 Solution: Spanning Trees Ensure the topology has no loops –Avoid using some of the links when flooding –… to avoid forming a loop Spanning tree –Sub-graph that covers all vertices but contains no cycles –Links not in the spanning tree do not forward frames
49 Constructing a Spanning Tree Need a distributed algorithm –Switches cooperate to build the spanning tree –… and adapt automatically when failures occur Key ingredients of the algorithm –Switches need to elect a “root” The switch with the smallest identifier –For each of its interfaces, a switch identifies if the interface is on the shortest path from the root And it excludes an interface from the tree if not
50 Constructing a Spanning Tree (cont. I) root One hop Three hops
51 Constructing a Spanning Tree (cont. II) Use broadcast messages; e.g. (Y, d, X) –From node X –Claiming Y is the root –And the distance from X to root is d
52 Steps in Spanning Tree Algorithm Initially, each switch thinks it is the root –Switch sends a message out every interface identifying itself as the root –Example: switch X announces (X, 0, X) Switches update their view of the root –Upon receiving a message, check the root id –If the new id is smaller, start viewing that switch as root Switches compute their distance from the root –Add 1 to the distance received from a neighbor –Identify interfaces not on a shortest path to the root –… and exclude them from the spanning tree
53 Example From Switch #4’s Viewpoint Switch #4 thinks it is the root –Sends (4, 0, 4) message to 2 and 7 Then, switch #4 hears from #2 –Receives (2, 0, 2) message from 2 –… and thinks that #2 is the root –And realizes it is just one hop away Then, switch #4 hears from #7 –Receives (2, 1, 7) from 7 –And realizes this is a longer path –So, prefers its own one-hop path –And removes 4-7 link from the tree 1 2 3 4 5 6 7
54 Example From Switch #4’s Viewpoint Switch #2 hears about switch #1 –Switch 2 hears (1, 1, 3) from 3 –Switch 2 starts treating 1 as root –And sends (1, 2, 2) to neighbors Switch #4 hears from switch #2 –Switch 4 starts treating 1 as root –And sends (1, 3, 4) to neighbors Switch #4 hears from switch #7 –Switch 4 receives (1, 3, 7) from 7 –And realizes this is a longer path –So, prefers its own three-hop path –And removes 4-7 Iink from the tree 1 2 3 4 5 6 7
55 Robust Spanning Tree Algorithm Algorithm must react to failures –Failure of the root node Need to elect a new root, with the next lowest identifier –Failure of other switches and links Need to recompute the spanning tree Root switch continues sending messages –Periodically reannouncing itself as the root (1, 0, 1) –Other switches continue forwarding messages Detecting failures through timeout (soft state!) –Switch waits to hear from others –Eventually times out and claims to be the root
Spanning Tree Protocol (IEEE 802.1d) The Spanning Tree Protocol (SPT) is a solution to prevent loops when forwarding frames between LANs The SPT is standardized as the IEEE 802.1d protocol The SPT organizes bridges and LANs as spanning tree in a dynamic environment –Frames are forwarded only along the branches of the spanning tree –Note: Trees don’t have loops Bridges that run the SPT are called transparent bridges Bridges exchange messages to configure the bridge (Configuration Bridge Protocol Data Unit or BPDUs) to build the tree. 56
58 What do the BPDUs do? With the help of the BPDUs, bridges can: Elect a single bridge as the root bridge. Calculate the distance of the shortest path to the root bridge Each LAN can determine a designated bridge, which is the bridge closest to the root. The designated bridge will forward packets towards the root bridge. Each bridge can determine a root port, the port that gives the best path to the root. Select ports to be included in the spanning tree.
59 Concepts Each bridge as a unique identifier:Bridge ID Bridge ID = Priority : 2 bytes Bridge MAC address: 6 bytes –Priority is configured –Bridge MAC address is lowest MAC addresses of all ports Each port of a bridge has a unique identifier (port ID). Root Bridge: The bridge with the lowest identifier is the root of the spanning tree. Root Port:Each bridge has a root port which identifies the next hop from a bridge to the root.
60 Concepts Root Path Cost: For each bridge, the cost of the min-cost path to the root. Designated Bridge, Designated Port: Single bridge on a LAN that provides the minimal cost path to the root for this LAN: - if two bridges have the same cost, select the one with highest priority - if the min-cost bridge has two or more ports on the LAN, select the port with the lowest identifier Note: We assume that “cost” of a path is the number of “hops”.
61 Steps of Spanning Tree Algorithm Each bridge is sending out BPDUs that contain the following information: The transmission of BPDUs results in the distributed computation of a spanning tree The convergence of the algorithm is very quick root bridge (what the sender thinks it is) root path cost for sending bridge Identifies sending bridge Identifies the sending port root ID cost bridge ID port ID
62 Ordering of Messages We define an ordering of BPDU messages We say M1 advertises a better path than M2 (“M1<
"name": "62 Ordering of Messages We define an ordering of BPDU messages We say M1 advertises a better path than M2 ( M1<
63 Initially, all bridges assume they are the root bridge. Each bridge B sends BPDUs of this form on its LANs from each port P: Each bridge looks at the BPDUs received on all its ports and its own transmitted BPDUs. Root bridge is the smallest received root ID that has been received so far (Whenever a smaller ID arrives, the root is updated) Initializing the Spanning Tree Protocol B B 0 0 B B P P
64 Each bridge B looks on all its ports for BPDUs that are better than its own BPDUs Suppose a bridge with BPDU: receives a “better” BPDU: Then it will update the BPDU to: However, the new BPDU is not necessarily sent out On each bridge, the port where the “best BPDU” (via relation “<<“) was received is the root port of the bridge. Operations of Spanning Tree Protocol R1 C1 B1 P1 M1 R2 C2 B2 P2 M2 R2 C2+1 B1 P1
65 Say, B has generated a BPDU for each port x B will send this BPDU on port x only if its BPDU is better (via relation “<<“) than any BPDU that B received from port x. In this case, B also assumes that it is the designated bridge for the LAN to which the port connects And port x is the designated port of that LAN When to send a BPDU R R Cost B B x x
66 Selecting the Ports for the Spanning Tree Each bridges makes a local decision which of its ports are part of the spanning tree Now B can decide which ports are in the spanning tree: B’s root port is part of the spanning tree All designated ports are part of the spanning tree All other ports are not part of the spanning tree B’s ports that are in the spanning tree will forward packets (=forwarding state) B’s ports that are not in the spanning tree will not forward packets (=blocking state)
67 Building the Spanning Tree Consider the network on the right. Assume that the bridges have calculated the designated ports (D) and the root ports (P) as indicated. What is the spanning tree? –On each LAN, connect R ports to the D ports on this LAN
69 IP (Internet Protocol) is a Network Layer Protocol. IP’s current version is Version 4 (IPv4). It is specified in RFC 891. Orientation
70 IP: The waist of the hourglass IP is the waist of the hourglass of the Internet protocol architecture Multiple higher-layer protocols Multiple lower-layer protocols Only one protocol at the network layer.
71 Application protocol IP is the highest layer protocol which is implemented at both routers and hosts
72 IP Service Delivery service of IP is minimal IP provides an unreliable connectionless best effort service (also called: “datagram service”). –Unreliable: IP does not make an attempt to recover lost packets –Connectionless: Each packet (“datagram”) is handled independently. IP is not aware that packets between hosts may be sent in a logical sequence –Best effort: IP does not make guarantees on the service (no throughput guarantee, no delay guarantee,…) Consequences: Higher layer protocols have to deal with losses or with duplicate packets Packets may be delivered out-of-sequence
73 IP supports the following services: one-to-one (unicast) one-to-all (broadcast) one-to-several(multicast) IP multicast also supports a many-to-many service. IP multicast requires support of other protocols (IGMP, multicast routing) IP Service unicast broadcast multicast
74 20 bytes ≤ Header Size < 2 4 x 4 bytes = 60 bytes 20 bytes ≤ Total Length < 2 16 bytes = 65536 bytes IP Datagram Format
75 IP Datagram Format Question: In which order are the bytes of an IP datagram transmitted? Answer: Transmission is row by row For each row: 1. First transmit bits 0-7 2. Then transmit bits 8-15 3. Then transmit bits 16-23 4. Then transmit bits 24-31 This is called network byte order or big endian byte ordering. Note: some computers store 32-bit words in little endian format.
76 Fields of the IP Header Version (4 bits): current version is 4, next version will be 6. Header length (4 bits): length of IP header, in multiples of 4 bytes DS/ECN field (1 byte) –This field was previously called as Type-of-Service (TOS) field. The role of this field has been re-defined, but is “backwards compatible” to TOS interpretation –Differentiated Service (DS) (6 bits): Used to specify service level (currently not supported in the Internet) –Explicit Congestion Notification (ECN) (2 bits): New feedback mechanism used by TCP
77 Fields of the IP Header Identification (16 bits): Unique identification of a datagram from a host. Incremented whenever a datagram is transmitted Flags (3 bits): –First bit always set to 0 –DF bit (Do not fragment) –MF bit (More fragments) Will be explained later Fragmentation
78 Fields of the IP Header Time To Live (TTL) (1 byte): –Specifies longest paths before datagram is dropped –Role of TTL field: Ensure that packet is eventually dropped when a routing loop occurs Used as follows: –Sender sets the value (e.g., 64) –Each router decrements the value by 1 –When the value reaches 0, the datagram is dropped
79 Fields of the IP Header Protocol (1 byte): Specifies the higher-layer protocol. Used for demultiplexing to higher layers. Header checksum (2 bytes): A simple 16-bit long checksum which is computed for the header of the datagram.
80 Fields of the IP Header Options: Security restrictions Record Route: each router that processes the packet adds its IP address to the header. Timestamp: each router that processes the packet adds its IP address and time to the header. (loose) Source Routing: specifies a list of routers that must be traversed. (strict) Source Routing: specifies a list of the only routers that can be traversed. Padding: Padding bytes are added to ensure that header ends on a 4-byte boundary
81 Maximum Transmission Unit Maximum size of IP datagram is 65535, but the data link layer protocol generally imposes a limit that is much smaller Example: –Ethernet frames have a maximum payload of 1500 bytes IP datagrams encapsulated in Ethernet frame cannot be longer than 1500 bytes The limit on the maximum IP datagram size, imposed by the data link protocol is called maximum transmission unit (MTU) MTUs for various data link protocols: Ethernet: 1500FDDI:4352 802.3:1492ATM AAL5: 9180 802.5: 4464PPP: negotiated
82 IP Fragmentation MTUs: FDDI: 4352 Ethernet: 1500 Fragmentation: IP router splits the datagram into several datagram Fragments are reassembled at receiver What if the size of an IP datagram exceeds the MTU? IP datagram is fragmented into smaller units. What if the route contains networks with different MTUs?
83 Where is Fragmentation done? Fragmentation can be done at the sender or at intermediate routers The same datagram can be fragmented several times. Reassembly of original datagram is only done at destination hosts (except in NAT’s case) !!
84 What’s involved in Fragmentation? The following fields in the IP header are involved: Identification When a datagram is fragmented, the identification is the same in all fragments Flags DF bit is set: Datagram cannot be fragmented and must be discarded if MTU is too small MF bit set: This datagram is part of a fragment and an additional fragment follows this one
85 What’s involved in Fragmentation? The following fields in the IP header are involved: Fragment offset Offset of the payload of the current fragment in the original datagram Total length Total length of the current fragment
86 Example of Fragmentation A datagram with size 2400 bytes must be fragmented according to an MTU limit of 1000 bytes
What is an IP Address? An IP address is a unique global address for a network interface An IP address: - is a 32 bit long identifier - encodes a network number (network prefix) and a host number
Dotted Decimal Notation IP addresses are written in a so-called dotted decimal notation Each byte is identified by a decimal number in the range [0..255]: Example: 10001111100000001000100110010000 1 st Byte = 128 2 nd Byte = 143 3 rd Byte = 137 4 th Byte = 144 18.104.22.168
The network prefix identifies a network and the host number identifies a specific host (actually, interface on the network). How do we know how long the network prefix is? –The network prefix is implicitly defined (see class-based addressing) –The network prefix is indicated by a netmask. Network prefix and Host number network prefixhost number
Example: ellington.cs.virginia.edu Network id is: 22.214.171.124 Host number is: 137.144 Network mask is: 255.255.0.0 or ffff0000 Prefix notation: 126.96.36.199/16 »Network prefix is 16 bits long Example 128.143137.144
The old way: Classful IP Adresses When Internet addresses were standardized (early 1980s), the Internet address space was divided up into classes: –Class A: Network prefix is 8 bits long –Class B: Network prefix is 16 bits long –Class C: Network prefix is 24 bits long Each IP address contained a key which identifies the class: –Class A: IP address starts with “0” –Class B: IP address starts with “10” –Class C: IP address starts with “110”
We will learn about multicast addresses later in this course.
Subnetting Problem: Organizations have multiple networks which are independently managed –Solution 1: Allocate one or more addresses for each network Difficult to manage From the outside of the organization, each network must be addressable. –Solution 2: Add another level of hierarchy to the IP addressing structure University Network Medical School Library Engineering School
Basic Idea of Subnetting Split the host number portion of an IP address into a subnet number and a (smaller) host number. Result is a 3-layer hierarchy Then: Subnets can be freely assigned within the organization Internally, subnets are treated as separate networks Subnet structure is not visible outside the organization network prefixhost number subnet number network prefix host number extended network prefix
Routers and hosts use an extended network prefix (subnet mask) to identify the start of the host numbers * There are different ways of subnetting. Commonly used netmasks for university networks with /16 prefix (Class B) are 255.255.255.0 and 255.255.0.0 Subnet Masks
Each layer-2 network (Ethernet segment, FDDI segment) is allocated a subnet address. Typical Addressing Plan for an Organization that uses subnetting 188.8.131.52/16
Advantages of Subnetting With subnetting, IP addresses use a 3-layer hierarchy: »Network »Subnet »Host Improves efficiency of IP addresses by not consuming an entire address space for each physical network. Reduces router complexity. Since external routers do not know about subnetting, the complexity of routing tables at external routers is reduced. Note: Length of the subnet mask need not be identical at all subnetworks.
CIDR - Classless Interdomain Routing IP backbone routers have one routing table entry for each network address: –With subnetting, a backbone router only needs to know one entry for each network –This is acceptable for Class A and Class B networks 2 7 = 128 Class A networks 2 14 = 16,384 Class B networks –But this is not acceptable for Class C networks 2 21 = 2,097,152 Class C networks In 1993, the size of the routing tables started to outgrow the capacity of routers Consequence: The Class-based assignment of IP addresses had to be abandoned
CIDR - Classless Interdomain Routing Goals: –Restructure IP address assignments to increase efficiency –Hierarchical routing aggregation to minimize route table entries Key Concept: The length of the network id (prefix) in the IP addresses is kept arbitrary Consequence: Routers advertise the IP address and the length of the prefix
CIDR Example CIDR notation of a network address: 192.0.2.0/18 "18" says that the first 18 bits are the network part of the address (and 14 bits are available for specific host addresses) The network part is called the prefix Assume that a site requires a network address with 1000 addresses With CIDR, the network is assigned a continuous block of 1024 addresses with a 22-bit long prefix
CIDR and Address assignments Backbone ISPs obtain large block of IP addresses space and then reallocate portions of their address blocks to their customers. Example: Assume that an ISP owns the address block 184.108.40.206/18, which represents 16,384 (2 14 ) IP addresses Suppose a client requires 800 host addresses With classful addresses: need to assign a class B address (and waste ~64,700 addresses) or four individual Class Cs (and introducing 4 new routes into the global Internet routing tables) With CIDR: Assign a /22 block, e.g., 220.127.116.11/22, and allocated a block of 1,024 (2 10 ) IP addresses.
CIDR and Routing Information 18.104.22.168/18 22.214.171.124/15 126.96.36.199/21 Internet Backbone ISP X owns: Company X : 188.8.131.52/22 ISP y : 184.108.40.206/24 Organization z1 : 220.127.116.11/26 Organization z2 : 18.104.22.168/26
CIDR and Routing Information 22.214.171.124/18 126.96.36.199/15 188.8.131.52/21 Internet Backbone ISP X owns: Company X : 184.108.40.206/22 ISP y : 220.127.116.11/24 Organization z1 : 18.104.22.168/26 Organization z2 : 22.214.171.124/26 Backbone sends everything which matches the prefixes 126.96.36.199/18, 188.8.131.52/15, 184.108.40.206/21 to ISP X. ISP X sends everything which matches the prefix: 220.127.116.11/22 to Company X, 18.104.22.168/24 to ISP y Backbone routers do not know anything about Company X, ISP Y, or Organizations z1, z2. ISP X does not know about Organizations z1, z2. ISP y sends everything which matches the prefix: 22.214.171.124/26 to Organizations z1 126.96.36.199/26 to Organizations z2
Example Belongs to: Cable & Wireless USA 188.8.131.52 - 184.108.40.206 1100111100000010 2072 01011000 88 10101010 170 11001111000000100101100000000000 Belongs to: City of Charlottesville, VA: 220.127.116.11 - 18.104.22.168 1100111100000000 You can find about ownership of IP addresses in North America via http://www.arin.net/whois/ The IP Address: 22.214.171.124
The Catch Before subnetting: In any network (or subnet) one can use most of the IP addresses for host addresses. One loses two addresses for every network or subnet. 1.Network Address - One address is reserved to that of the network. 2.Broadcast Address – One address is reserved to address all hosts in that network or subnet.
Subnet Example Network address 172.19.0.0 with /16 network mask Network Host 1721900
Subnet Example Network SubnetHost Network address 172.19.0.0 with /16 network mask Using Subnets: subnet mask 255.255.255.0 or /24 Applying a mask which is larger than the default subnet mask, will divide your network into subnets. Subnet mask used here is 255.255.255.0 or /24 Network Mask: 255.255.0.0 or /16 Subnet Mask: 255.255.255.0 or /24 11111111 00000000 11111111 00000000 Network Host 1721900
Subnet Example Network SubnetHost Network address 172.19.0.0 with /16 network mask 172190Host172191Host172192Host Using Subnets: subnet mask 255.255.255.0 or /24 172193Host17219etc.Host17219254Host17219255Host 255 Subnets 2 8 - 1 Cannot use last subnet as it contains broadcast address Subnets
Subnet Example Network SubnetHost Network address 172.19.0.0 with /16 network mask 172190017219101721920 Using Subnets: subnet mask 255.255.255.0 or /24 172193017219etc.0172192540172192550 255 Subnets 2 8 - 1 Cannot use last subnet as it contains broadcast address Subnets Addresses
Subnet Example Network SubnetHosts Class B address 172.19.0.0 with /16 network mask 172190117219111721921 Using Subnets: subnet mask 255.255.255.0 or /24 172193117219etc.117219254117219255Host Each subnet has 254 hosts, 2 8 – 2 254 Hosts Addresses
Subnet Example Network SubnetHost Network address 172.19.0.0 with /16 network mask 172190255172191255172192255 Using Subnets: subnet mask 255.255.255.0 or /24 17219325517219etc.2551721925425517219255 255 Subnets 2 8 - 1 Cannot use last subnet as it contains broadcast address Broadcast Addresses
Subnet Example Network address 172.19.0.0 with /16 network mask Using Subnets: subnet mask 255.255.255.0 or /24 172.19.0.0/24172.19.10.0/24 172.19.5.0/24 172.19.25.0/24
Important things to remember about Subnetting You can only subnet the host portion, you do not have control of the network portion. Subnetting does not give you more hosts, it only allows you to divide your larger network into smaller networks. When subnetting, you will actually lose host adresses: –For each subnet you lose the address of that subnet –For each subnet you lose the broadcast address of that subnet –You “may” lose the first and last last subnets Why would you want to subnet? –Divide larger network into smaller networks –Limit layer 2 and layer 3 broadcasts to their subnet. –Better management of traffic.
Subnetting – Example Host IP Address: 126.96.36.199 Network Mask: 255.255.0.0 (or /16) Subnet Mask: 255.255.255.192 (or /26) Given the following Host IP Address, Network Mask and Subnet mask find the following information: Major Network Information –Major Network Address –Major Network Broadcast Address –Range of Hosts if not subnetted Subnet Information –Subnet Address –Range of Host Addresses (first host and last host) –Broadcast Address Other Subnet Information –Total number of subnets –Number of hosts per subnet
Major Network Information Host IP Address: 188.8.131.52 Network Mask: 255.255.0.0 Subnet Mask: 255.255.255.192 Major Network Address: 184.108.40.206 Major Network Broadcast Address: 220.127.116.11 Range of Hosts if not Subnetted: 18.104.22.168 to 22.214.171.124
Step 1: Translate Host IP Address and Subnet Mask into binary notation Step 1: Convert to Binary 128 64 32 16 8 4 2 1
Step 2: Determine the Network (or Subnet) where this Host address lives: 1. Draw a line under the mask 2. Perform a bit-wise AND operation on the IP Address and the Subnet Mask Note: 1 AND 1 results in a 1, 0 AND anything results in a 0 3. Express the result in Dotted Decimal Notation 4. The result is the Subnet Address of this Subnet or “Wire” which is 126.96.36.199 Step 2: Find the Subnet Address
Step 2: Determine the Network (or Subnet) where this Host address lives: Quick method: 1.Find the last (right-most) 1 bit in the subnet mask. 2.Copy all of the bits in the IP address to the Network Address 3.Add 0’s for the rest of the bits in the Network Address Step 2: Find the Subnet Address
Step 3: Determine which bits in the address contain Network (subnet) information and which contain Host information: Use the Network Mask: 255.255.0.0 and divide (Great Divide) the from the rest of the address. Use Subnet Mask: 255.255.255.192 and divide (Small Divide) the subnet from the hosts between the last “1” and the first “0” in the subnet mask. Step 3: Subnet Range / Host Range
Host Portion Subnet Address: all 0’s First Host: all 0’s and a 1 Last Host: all 1’s and a 0 Broadcast: all 1’s Step 4: First Host / Last Host
Total number of subnets –Number of subnet bits 10 –2 10 = 1,024 –1,024 total subnets Subtract one “if” all-zeros subnet cannot be used Subtract one “if” all-ones subnet cannot be used Step 5: Total Number of Subnets
Total number of hosts per subnet –Number of host bits 6 –2 6 = 64 –64 host per subnets Subtract one for the subnet address Subtract one for the broadcast address –62 hosts per subnet Step 6: Total Number of Hosts per Subnet
130 Internet is a collection of networks IP provides an end-to-end delivery service for IP datagrams between hosts The delivery service is realized with the help of IP routers Orientation
131 Delivery of an IP datagram IP View at the data link layer: –Internetwork is a collection of LANs or point-to-point links or switched networks that are connected by routers
132 Delivery of an IP datagram IP View at the IP layer: –An IP network is a logical entity with a network number –We represent an IP network as a “cloud” –The IP delivery service takes the view of clouds, and ignores the data link layer view
133 Tenets of end-to-end delivery of datagrams The following conditions must hold so that an IP datagram can be successfully delivered 1.The network prefix of an IP destination address must correspond to a unique data link layer network (=LAN or point-to-point link or switched network). 2.Routers and hosts that have a common network prefix must be able to exchange IP datagrams using a data link protocol (e.g., Ethernet, PPP) 3.An IP network is formed when a data link layer network is connected to at least one other data link layer network via a router. 1.The network prefix of an IP destination address must correspond to a unique data link layer network (=LAN or point-to-point link or switched network). 2.Routers and hosts that have a common network prefix must be able to exchange IP datagrams using a data link protocol (e.g., Ethernet, PPP) 3.An IP network is formed when a data link layer network is connected to at least one other data link layer network via a router.
134 Routing tables Each router and each host keeps a routing table which tells the router how to process an outgoing packet Main columns: 1.Destination address: where is the IP datagram going to? 2.Next hop or interface: how to send the IP datagram? Routing tables are set so that a datagram gets closer to the its destination DestinationNext Hop 188.8.131.52/28 10.1.0.0/24 10.1.2.0/24 10.2.1.0/24 10.3.1.0/24 184.108.40.206/16 R4 direct direct R4 direct R4 Routing table of a host or router IP datagrams can be directly delivered (“direct”) or are sent to a next hop router (“R4”)
135 Delivery of IP datagrams There are two distinct processes to delivering IP datagrams: 1. Forwarding: How to pass a packet from an input interface to the output interface? 2.Routing: How to find and setup the routing tables? Forwarding must be done as fast as possible: –on routers, is often done with support of hardware –on PCs, is done in kernel of the operating system Routing is less time-critical –On a PC, routing is done as a background process
136 Processing of an IP datagram in IP IP router: IP forwarding enabled Host: IP forwarding disabled
137 Processing of an IP datagram in IP Processing of IP datagrams is very similar on an IP router and a host Main difference: “IP forwarding” is enabled on router and disabled on host IP forwarding enabled if a datagram is received, but it is not for the local system, the datagram will be sent to a different system IP forwarding disabled if a datagram is received, but it is not for the local system, the datagram will be discarded
138 Processing of an IP datagram at a router 1.IP header validation 2.Process options in IP header 3.Parsing the destination IP address 4.Routing table lookup 5.Decrement TTL 6.Perform fragmentation (if necessary) 7.Calculate checksum 8.Transmit to next hop 9.Send ICMP packet (if necessary) Receive an IP datagram
139 Routing table lookup When a router or host need to transmit an IP datagram, it performs a routing table lookup Routing table lookup: Use the IP destination address as a key to search the routing table. Result of the lookup is the IP address of a next hop router, or the name of a network interface Destination address Next hop network prefix or host IP address or loopback address or default route IP address of next hop router* or Name of a network interface *Note: A router has many IP addresses. The IP address in the routing table refers to the address of the network interface on the same directly connected network.
140 Type of routing table entries Network route –Destination addresses is a network address (e.g., 10.0.2.0/24) –Most entries are network routes Host route –Destination address is an interface address (e.g., 10.0.1.2/32) –Used to specify a separate route for certain hosts Default route –Used when no network or host route matches –The router that is listed as the next hop of the default route is the default gateway (for Cisco: “gateway of last resort) Loopback address –Routing table for the loopback address (127.0.0.1) –The next hop lists the loopback (lo0) interface as outgoing interface
141 Longest Prefix Match Longest Prefix Match: Search for the routing table entry that has the longest match with the prefix of the destination IP address 1.Search for a match on all 32 bits 2.Search for a match for 31 bits ….. 32.Search for a match on 0 bits Host route, loopback entry 32-bit prefix match Default route is represented as 0.0.0.0/0 0-bit prefix match 220.127.116.11 The longest prefix match for 18.104.22.168 is for 24 bits with entry 22.214.171.124/24 Datagram will be sent to R4
142 Route Aggregation Longest prefix match algorithm permits the aggregation of prefixes with identical next hop address to a single entry This contributes significantly to reducing the size of routing tables of Internet routers DestinationNext Hop 10.1.0.0/24 10.1.2.0/24 10.2.1.0/24 10.3.1.0/24 126.96.36.199/14 R3 direct direct R3 R2 DestinationNext Hop 10.1.0.0/24 10.1.2.0/24 10.2.1.0/24 10.3.1.0/24 188.8.131.52/16 184.108.40.206/28 R3 direct direct R3 R2 R2
144 Orientation We move one layer up and look at the transport layer.
145 Orientation Transport layer protocols are end-to-end protocols They are only implemented at the hosts
146 Transport Protocols in the Internet UDP - User Datagram Protocol datagram oriented unreliable, connectionless simple unicast and multicast useful only for few applications, e.g., multimedia applications Used by a lot for services –network management (SNMP), routing (RIP), naming (DNS), etc. TCP - Transmission Control Protocol stream oriented reliable, connection-oriented complex only unicast used for most Internet applications: –web (http), email (smtp), file transfer (ftp), terminal (telnet), etc. The Internet supports 2 transport protocols
147 UDP - User Datagram Protocol UDP supports unreliable transmissions of datagrams UDP merely extends the host-to-to-host delivery service of IP datagram to an application-to-application service The only thing that UDP adds is multiplexing and demultiplexing
148 Port Numbers UDP (and TCP) use port numbers to identify applications A globally unique address at the transport layer (for both UDP and TCP) is a tuple There are 65,535 UDP ports per host.
150 Overview TCP = Transmission Control Protocol Connection-oriented protocol Provides a reliable unicast end-to-end byte stream over an unreliable internetwork.
151 Connection-Oriented Before any data transfer, TCP establishes a connection: One TCP entity is waiting for a connection (“server”) The other TCP entity (“client”) contacts the server The actual procedure for setting up connections is more complex. Each connection is full duplex
152 Reliable Byte stream is broken up into chunks which are called seg- ments Receiver sends acknowledgements (ACKs) for segments TCP maintains a timer. If an ACK is not received in time, the segment is retransmitted Detecting errors: TCP has checksums for header and data. Segments with invalid checksums are discarded Each byte that is transmitted has a sequence number
153 Byte Stream Service To the lower layers, TCP handles data in blocks called segments. To the higher layers TCP handles data as a sequence of bytes and does not identify boundaries between bytes So: Higher layers do not know about the beginning and end of segments !
154 TCP Format TCP segments have a minimum 20 byte header with >= 0 bytes of data.
155 TCP header fields Port Number: A port number identifies the endpoint of a connection. A pair identifies one endpoint of a connection. Two pairs and identify a TCP connection.
156 TCP header fields Sequence Number (SeqNo): –Sequence number is 32 bits long. –So the range of SeqNo is 0 <= SeqNo <= 2 32 -1 4.3 Gbyte –Each sequence number identifies a byte in the byte stream –Initial Sequence Number (ISN) of a connection is set during connection establishment
157 TCP header fields Acknowledgement Number (AckNo): –Acknowledgements are piggybacked, I.e a segment from A -> B can contain an acknowledgement for a segment sent in the B -> A direction. –A host uses the AckNo field to send acknowledgements. (If a host sends an AckNo in a segment it sets the “ACK flag”) –The AckNo contains the next SeqNo that a hosts wants to receive Example: The acknowledgement for a segment with sequence number 0 and 1500 data bytes is AckNo=1500+1
158 TCP header fields Acknowledge Number (cont’d) –TCP uses the sliding window flow protocol to regulate the flow of traffic from sender to receiver –TCP uses the following variation of sliding window: –no NACKs (Negative ACKnowledgement) –only cumulative ACKs Example: Assume: Sender sends two segments with “0..1500” and “1501..3000”, but receiver only gets the second segment. In this case, the receiver cannot acknowledge the second packet. It can only send AckNo=0+1
159 TCP header fields Header Length ( 4bits): –Length of header in 32-bit words –Note that TCP header has variable length (with minimum 20 bytes)
160 TCP header fields Flag bits: –URG: Urgent pointer is valid –If the bit is set, the following bytes contain an urgent message in the range: SeqNo <= urgent message <= SeqNo+urgent pointer –ACK: Acknowledgement Number is valid –PSH: PUSH Flag –Notification from sender to the receiver that the receiver should pass all data that it has to the application. –Normally set by sender when the sender’s buffer is empty
161 TCP header fields Flag bits: –RST: Reset the connection –The flag causes the receiver to reset the connection –Receiver of a RST terminates the connection and indicates higher layer application about the reset –SYN: Synchronize sequence numbers –Sent in the first packet when initiating a connection –FIN: Sender is finished with sending –Used for closing a connection –Both sides of a connection must send a FIN
162 TCP header fields Window Size: –Each side of the connection advertises the window size –Window size is the maximum number of bytes that a receiver can accept. –Maximum window size is 2 16 -1= 65535 bytes TCP Checksum: –TCP checksum covers TCP segment and IP pseudo header (see discussion on UDP). Urgent Pointer: –Only valid if URG flag is set
163 Connection Management in TCP Opening a TCP Connection Closing a TCP Connection Special Scenarios
164 TCP Connection Establishment TCP uses a three-way handshake to open a connection: (1) ACTIVE OPEN: Client sends a segment with –SYN bit set –port number of client –initial sequence number (ISN) of client (2) PASSIVE OPEN: Server responds with a segment with –SYN bit set –initial sequence number of server –ACK for ISN of client (3) Client acknowledges by sending a segment with: – ACK ISN of server
167 Why is a Two-Way Handshake not enough? When aida initiates the data transfer (starting with SeqNo=15322112355), mng will reject all data. Will be discarded as a duplicate SYN
168 TCP Connection Termination Each end of the data flow must be shut down independently (“half-close”) If one end is done it sends a FIN segment. This means that no more data will be sent Four steps involved: (1) X sends a FIN to Y (active close) (2) Y ACKs the FIN, (at this time: Y can still send data to X) (3) and Y sends a FIN to X (passive close) (4) X ACKs the FIN.
171 TCP States in “Normal” Connection Lifetime
172 2MSL Wait State 2MSL Wait State = TIME_WAIT When TCP does an active close, and sends the final ACK, the connection must stay in in the TIME_WAIT state for twice the maximum segment lifetime. 2MSL= 2 * Maximum Segment Lifetime Why? TCP is given a chance to resend the final ACK. (Server will timeout after sending the FIN segment and resend the FIN) The MSL is set to 2 minutes or 1 minute or 30 seconds.
173 Resetting Connections Resetting connections is done by setting the RST flag When is the RST flag set? –Connection request arrives and no server process is waiting on the destination port –Abort (Terminate) a connection Causes the receiver to throw away buffered data. Receiver does not acknowledge the RST segment
174 Interactive and bulk data in TCP TCP applications can be put into the following categories bulk data transfer- ftp, mail, http interactive data transfer- telnet, rlogin TCP has algorithms to deal which each type of applications efficiently.
175 Delayed Acknowledgement TCP delays transmission of ACKs for up to 200ms The hope is to have data ready in that time frame. Then, the ACK can be piggybacked with the data segment. Delayed ACKs explain why the ACK and the “echo of character” are sent in the same segment.
176 Nagle’s Algorithm There are fewer transmissions than there are characters. Aida never has multiple segments outstanding. This is due to Nagle’s Algorithm: Each TCP connection can have only one small (1-byte) segment outstanding that has not been acknowledged. Implementation: Send one byte and buffer all subsequent bytes until acknowledgement is received.Then send all buffered bytes in a single segment. (Only enforced if data is arriving from application one byte at a time) Nagle’s rule reduces the amount of small segments. The algorithm can be disabled.
177 Flow Control Congestion Control Error Control TCP:
178 What is Flow/Congestion/Error Control ? Flow Control: Algorithms to prevent that the sender overruns the receiver with information? Congestion Control: Algorithms to prevent that the sender overloads the network Error Control: Algorithms to recover or conceal the effects from packet losses The goal of each of the control mechanisms is different. But the implementation is combined
179 TCP Flow Control TCP implements sliding window flow control Sending acknowledgements is separated from setting the window size at sender. Acknowledgements do not automatically increase the window size Acknowledgements are cumulative
180 Sliding Window Flow Control Sliding Window Protocol is performed at the byte level: Here: Sender can transmit sequence numbers 6,7,8.
181 Sliding Window: “Window Closes” Transmission of a single byte (with SeqNo = 6) and acknowledgement is received (AckNo = 5, Win=4):
182 Sliding Window: “Window Opens” Acknowledgement is received that enlarges the window to the right (AckNo = 5, Win=6): A receiver opens a window when TCP buffer empties (meaning that data is delivered to the application).
183 Sliding Window: “Window Shrinks” Acknowledgement is received that reduces the window from the right (AckNo = 5, Win=3): Shrinking a window should not be used
184 Window Management in TCP The receiver is returning two parameters to the sender The interpretation is: I am ready to receive new data with SeqNo= AckNo, AckNo+1, …., AckNo+Win-1 Receiver can acknowledge data without opening the window Receiver can change the window size without acknowledging data
186 TCP Congestion Control TCP has a mechanism for congestion control. The mechanism is implemented at the sender The window size at the sender is set as follows: where flow control window is advertised by the receiver congestion window is adjusted based on feedback from the network Send Window = MIN (flow control window, congestion window)
187 TCP Congestion Control The sender has two additional parameters: –Congestion Window (cwnd) Initial value is 1 MSS (=maximum segment size) counted as bytes –Slow-start threshold Value (ssthresh) Initial value is the advertised window size) Congestion control works in two modes: –slow start (cwnd < ssthresh) –congestion avoidance (cwnd >= ssthresh)
188 Slow Start Initial value: –cwnd = 1 segment Note: cwnd is actually measured in bytes: 1 segment = MSS bytes Each time an ACK is received, the congestion window is increased by MSS bytes. –cwnd = cwnd + MSS –If an ACK acknowledges two segments, cwnd is still increased by only 1 segment. –Even if ACK acknowledges a segment that is smaller than MSS bytes long, cwnd is increased by MSS. Does Slow Start increment slowly? Not really. In fact, the increase of cwnd can be exponential
189 Slow Start Example The congestion window size grows very rapidly –For every ACK, we increase cwnd by 1 irrespective of the number of segments ACK’ed TCP slows down the increase of cwnd when cwnd > ssthresh
190 Congestion Avoidance Congestion avoidance phase is started if cwnd has reached the slow-start threshold value If cwnd >= ssthresh then each time an ACK is received, increment cwnd as follows: cwnd = cwnd + MSS(MSS/ cwnd) So cwnd is increased by one segment (=MSS bytes) only if all segments have been acknowledged.
191 Slow Start / Congestion Avoidance Here we give a more accurate version than in our earlier discussion of Slow Start: If cwnd <= ssthresh then Each time an Ack is received: cwnd = cwnd + MSS else /* cwnd > ssthresh */ Each time an Ack is received : cwnd = cwnd + MSS. MSS / cwnd endif
192 Example of Slow Start/Congestion Avoidance Assume that ssthresh = 8 Roundtrip times Cwnd (in segments) ssthresh
193 Responses to Congestion Most often, a packet loss in a network is due to an overflow at a congested router (rather than due to a transmission error) So, TCP assumes there is congestion if it detects a packet loss A TCP sender can detect lost packets via: Timeout of a retransmission timer Receipt of a duplicate ACK When TCP assumes that a packet loss is caused by congestion it reduces the size of the sending window
194 TCP Tahoe Congestion is assumed if sender has timeout or receipt of duplicate ACK Each time when congestion occurs, –cwnd is reset to one: cwnd = MSS –ssthresh is set to half the current size of the congestion window: ssthressh = cwnd / 2 –and slow-start is entered
195 Slow Start / Congestion Avoidance A typical plot of cwnd for a TCP connection (MSS = 1500 bytes) with TCP Tahoe:
196 Background: ARQ Error Control Two types of errors: –Lost packets –Damaged packets Most Error Control techniques are based on: 1. Error Detection Scheme (Parity checks, CRC). 2. Retransmission Scheme. Error control schemes that involve error detection and retransmission of lost or corrupted packets are referred to as Automatic Repeat Request (ARQ) error control.
197 Background: ARQ Error Control All retransmission schemes use all or a subset of the following procedures: Positive acknowledgments (ACK) Negative acknowledgment (NACK) All retransmission schemes (using ACK, NACK or both) rely on the use of timers The most common ARQ retransmission schemes are: Stop-and-Wait ARQ Go-Back-N ARQ Selective Repeat ARQ
198 Error Control in TCP TCP implements a variation of the Go-back-N retransmission scheme TCP maintains a Retransmission Timer for each connection: –The timer is started during a transmission. A timeout causes a retransmission TCP couples error control and congestion control (i.e., it assumes that errors are caused by congestion) TCP allows accelerated retransmissions (Fast Retransmit)
199 TCP Retransmission Timer Retransmission Timer: –The setting of the retransmission timer is crucial for efficiency –Timeout value too small results in unnecessary retransmissions –Timeout value too large long waiting time before a retransmission can be issued –A problem is that the delays in the network are not fixed –Therefore, the retransmission timers must be adaptive
200 Round-Trip Time Measurements The retransmission mechanism of TCP is adaptive The retransmission timers are set based on round-trip time (RTT) measurements that TCP performs The RTT is based on time difference between segment transmission and ACK But: TCP does not ACK each segment Each connection has only one timer
201 Round-Trip Time Measurements Retransmission timer is set to a Retransmission Timeout (RTO) value. RTO is calculated based on the RTT measurements. The RTT measurements are smoothed by the following estimators srtt and rttvar: srtt n+1 = RTT + (1- ) srtt n rttvar n+1 = ( | RTT - srtt n+1 | ) + (1- ) rttvar n RTO n+1 = srtt n+1 + 4 rttvar n+1 The gains are set to =1/4 and =1/8 srtt 0 = 0 sec, rttvar 0 = 3 sec, Also: RTO 1 = srtt 1 + 2 rttvar 1
202 Karn’s Algorithm If an ACK for a retransmitted segment is received, the sender cannot tell if the ACK belongs to the original or the retransmission. Karn’s Algorithm: Don’t update srtt on any segments that have been retransmitted. Each time when TCP retransmits, it sets: RTO n+1 = min( 2 RTO n, 64) (exponential backoff)
RFC 1631 A short term solution to the problem of the depletion of IP addresses –Long term solution is IP v6 –CIDR (Classless InterDomain Routing ) is a possible short term solution –NAT is another NAT is a way to conserve IP addresses –Can be used to hide a number of hosts behind a single IP address –Uses private addresses: 10.0.0.0-10.255.255.255, 172.16.0.0-220.127.116.11 or 192.168.0.0-192.168.255.255 204
205 Network Address Translation (NAT) NAT is a router function where IP addresses (and possibly port numbers) of IP datagrams are replaced at the boundary of a private network NAT is a method that enables hosts on private networks to communicate with hosts on the Internet NAT is run on routers that connect private networks to the public Internet, to replace the IP address-port pair of an IP packet with another IP address-port pair.
206 Basic Operation of NAT NAT device has address translation table One to one address translation
207 Pooling of IP Addresses Scenario: Corporate network has many hosts but only a small number of public IP addresses NAT solution: –Corporate network is managed with a private address space –NAT device, located at the boundary between the corporate network and the public Internet, manages a pool of public IP addresses –When a host from the corporate network sends an IP datagram to a host in the public Internet, the NAT device picks a public IP address from the address pool, and binds this address to the private address of the host
209 Supporting Migration between Network Service Providers Scenario: In CIDR, the IP addresses in a corporate network are obtained from the service provider. Changing the service provider requires changing all IP addresses in the network. NAT solution: –Assign private addresses to the hosts of the corporate network –NAT device has static address translation entries which bind the private address of a host to the public address. –Migration to a new network service provider merely requires an update of the NAT device. The migration is not noticeable to the hosts on the network. Note: –The difference to the use of NAT with IP address pooling is that the mapping of public and private IP addresses is static.
210 Supporting Migration between network service Providers
211 IP Masquerading Also called: Network address and port translation (NAPT), port address translation (PAT). Scenario: Single public IP address is mapped to multiple hosts in a private network. NAT solution: –Assign private addresses to the hosts of the corporate network –NAT device modifies the port numbers for outgoing traffic
213 Load Balancing of Servers Scenario: Balance the load on a set of identical servers, which are accessible from a single IP address NAT solution: –Here, the servers are assigned private addresses –NAT device acts as a proxy for requests to the server from the public network –The NAT device changes the destination IP address of arriving packets to one of the private addresses for a server –A sensible strategy for balancing the load of the servers is to assign the addresses of the servers in a round-robin fashion.
215 Concerns about NAT Performance: –Modifying the IP header by changing the IP address requires that NAT boxes recalculate the IP header checksum –Modifying port number requires that NAT boxes recalculate TCP checksum Fragmentation –Care must be taken that a datagram that is fragmented before it reaches the NAT device, is not assigned a different IP address or different port numbers for each of the fragments.
216 Concerns about NAT End-to-end connectivity: –NAT destroys universal end-to-end reachability of hosts on the Internet. –A host in the public Internet often cannot initiate communication to a host in a private network. –The problem is worse, when two hosts that are in a private network need to communicate with each other.
217 Concerns about NAT IP address in application data: –Applications that carry IP addresses in the payload of the application data generally do not work across a private- public network boundary. –Some NAT devices inspect the payload of widely used application layer protocols and, if an IP address is detected in the application-layer header or the application payload, translate the address according to the address translation table.
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