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13.6 Circles. T127 Circle equation: (x-h) 2 + (y-k) 2 = r 2 Where (h,k) is the center of the circle and r = radius.

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Presentation on theme: "13.6 Circles. T127 Circle equation: (x-h) 2 + (y-k) 2 = r 2 Where (h,k) is the center of the circle and r = radius."— Presentation transcript:

1 13.6 Circles

2 T127 Circle equation: (x-h) 2 + (y-k) 2 = r 2 Where (h,k) is the center of the circle and r = radius

3 Write the equation for a circle whose center is (1,5) and has a radius of 4. (x-1) 2 + (y-5) 2 = 16 Find the center and radius of the graph (x+2) 2 + (y-1) 2 = 25 Center (-2,1) Radius = 5

4 Complete the square! Is x 2 – 8x + y 2 -10y = 8an equation of a circle? x 2 – 8x + ____+ y 2 – 10y + ____= 8 16 25 Center is (4,5) radius = 7 (x-4) 2 + (y-5) 2 = 49

5 Write an equation of a circle with center (-5,0) and a radius of (x-(-5)) 2 + (y-0) 2 = ( ) 2 (x+5) 2 + (y) 2 =

6 Find the center, radius, diameter, circumference and area of: (x+5) 2 + (y-2) 2 = 27 3 3 Center Radius Diameter Circumference Area (-5,2) 9 18 18Л 81Л

7 Describe the graph of (x-2) 2 + (y+5) 2 = 0 The center is (2,-5), the radius is 0. It is a circle that has shrunk to a single point! It is called a point circle.

8 Describe the graph of x 2 + (y-4) 2 = -25 Center is (0,4) and the radius is the square root of -25. However, the square root of -25 is not a real number, so it can’t be drawn on a coordinate plane. Since the square root of -25 is an imaginary number the equation is said to represent an imaginary circle.

9 Equation for a circle (x-h) 2 + (y-k) 2 = r 2 To find the length of the radius, take the square root of each side. Does this look familiar? Distance formula


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