2. Aim: How do we factor the trinomial in the form of Do Now: Factor the following 1. x 2 – 6x + 8 2. x 2 – 8x – 9 3. 3x 2 + 17x + 10

3. We know how to factor the trinomials in the form of whose leading coefficient is 1 3x 2 + 17x + 10 has the leading coefficient other than 1 We can use two different methods to factor it Method 1: try and error (3x + 2)(x + 5)

4. Factor: 3x 2 + 17x + 10 Method 2 Divide 1 st term by the leading coefficient and multiply the last term by the leading coefficient Simplify ( x + 15)( x + 2) Factor x 2 + 17x + 30 and leave a space before each x (3x + 15)(3x + 2) Put 3 back into each binomial (x + 5)(3x + 2) Divide each binomial by the GCF if there is (are)

5. Factor: 3x 2 - 10x - 8 ( x – 12)( x + 2) (3x – 12)(3x + 2) (x – 4)(3x + 2) Divide 1st term by the leading coefficient and multiply the last term by the leading coefficient Simplify Factor x 2 + 17x + 30 and leave a space before each x Put 3 back into each binomial Divide each binomial by the GCF if there is (are)

6. 1. 6x 2 + x – 15 3. 3x 2 + 20x + 12 Factor the following trinomials 2. 12x 2 – 9x – 3 x 2 + x – 90 ( x + 10)( x – 9) (6x + 10)(6x – 9)(3x + 5)(2x – 3) 3(4x 2 – 3x – 1) 3( x +1)( x – 4) 3(4x + 1)(4x – 4) 3(4x + 1)(x – 1) 3(x 2 – 3x – 4) x 2 + 20x + 36(3x + 18)(3x + 2) (x + 6)(3x + 2)

7. Factor each trinomial if possible. 1) x 2 –10x + 24 2) x 2 + 3x – 18 3) 2x 2 – x – 21 4) 3x 2 + 11x + 10 5) 3x 2 – 12x – 15 6) 5x 2 + 12x + 4