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Lesson #28 - Surface Area of Prisms.

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Presentation on theme: "Lesson #28 - Surface Area of Prisms."— Presentation transcript:

1 Lesson #28 - Surface Area of Prisms

2 A=pr2 A=bh 2 =p(6cm)2 =36p cm2 =(4m)(3m) 2 =113.1 cm2 =6 m2 5 m 4 m
1) Area of a Circle Area of a Triangle 3 m 4 m 5 m 6 cm A=pr2 A=bh 2 =p(6cm)2 =36p cm2 =(4m)(3m) 2 =113.1 cm2 =6 m2

3 A=(b1+b2)(h) A=apothem(P) 2 2 =(5mm)(6)(4mm) =(2cm+4cm)(3cm) 2 2
Area of a Polygon Area of a Trapezoid 3 cm 4 cm 2 cm 4 mm 5 mm A=apothem(P) 2 A=(b1+b2)(h) 2 =(5mm)(6)(4mm) 2 =(2cm+4cm)(3cm) 2 =60 mm2 =9 cm2

4 A=6s2 =6(3cm)2 A=54 cm2 2) TSA of a Cube 3 cm
Homework Take-Up- 5 minutes

5 3) TSA of a prism 5 cm 21 cm Homework Take-Up- 5 minutes

6 4) TSA of a cylinder 5 cm 10 cm r=5 cm h=10 cm
A cube has 6 equal area si

7 Homework Pg #3-5 Pg #6,8 & 12 Pg # 14ab,15


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