1. Precalculus Unit 5 Hyperbolas

2. A hyperbola is a set of points in a plane the difference of whose distances from two fixed points, called foci, is a constant. F1F1 F2F2 d1d1 d2d2 P For any point P that is on the hyperbola, d 2 – d 1 is always the same. In this example, the origin is the center of the hyperbola. It is midway between the foci.

3. F F V V C A line through the foci intersects the hyperbola at two points, called the vertices. The segment connecting the vertices is called the transverse axis of the hyperbola. The center of the hyperbola is located at the midpoint of the transverse axis. As x and y get larger the branches of the hyperbola approach a pair of intersecting lines called the asymptotes of the hyperbola. These asymptotes pass through the center of the hyperbola. The distance from the center to a vertex is a.

4. F F V V C The figure at the left is an example of a hyperbola whose branches open up and down instead of right and left. Since the transverse axis is vertical, this type of hyperbola is often referred to as a vertical hyperbola. When the transverse axis is horizontal, the hyperbola is referred to as a horizontal hyperbola.

5. (x – h) 2 (y – k) 2 a2a2 b2b2 Horizontal Hyperbola (y – k) 2 (x – h) 2 b2b2 a2a2 – = 1 Vertical Hyperbola – = 1 The center of a hyperbola is at the point (h, k) in either form For either hyperbola, c 2 = a 2 + b 2 Where c is the distance from the center to a focus point. The equations of the asymptotes are y = (x – h) + k and y = (x – h) + k baba baba -

6. Ex : x 2 y 2 16 7 c 2 = 16 + 7 = 23 c =  23 Foci: (  23, 0) and (-  23, 0) – = 1 Center: (0, 0) The x-term comes first in the subtraction so this is a horizontal hyperbola Vertices: (4, 0) and (-4, 0) From the pythagorean relation c 2 = a 2 + b 2 a 2 =16 so a = 4. The vertices are to the right and left of center x 4 spaces.

7. Graph: x 2 y 2 4 9 c 2 = 9 + 4 = 13 c =  13 = 3.61 Foci: (3.61, 0) and (-3.61, 0) – = 1 Center: (0, 0) The x-term comes first in the subtraction so this is a horizontal hyperbola Vertices: (2, 0) and (-2, 0) From the center locate the points that are up three spaces and down three spaces Draw a dotted rectangle through the four points you have found. Draw the asymptotes as dotted lines that pass diagonally through the rectangle. Draw the hyperbola. From the center locate the points that are two spaces to the right and two spaces to the left

8. Graph: (x + 2) 2 (y – 1) 2 9 25 c 2 = 9 + 25 = 34 c =  34 = 5.83 Foci: (-7.83, 1) and (3.83, 1) – = 1 Center: (-2, 1) Horizontal hyperbola Vertices: (-5, 1) and (1, 1) Asymptotes: y = (x + 2) + 1 5353 y = (x + 2) + 1 5353 -

9. (y – 1) 2 (x – 3) 2 4 9 c 2 = 9 + 4 = 13 c =  13 = 3.61 Foci: (3, 4.61) and (3, -2.61) – = 1 Center: (3, 1) The hyperbola is vertical Graph: 9y 2 – 4x 2 – 18y + 24x – 63 = 0 9(y 2 – 2y + ___) – 4(x 2 – 6x + ___) = 63 + ___ – ___91936 9(y – 1) 2 – 4(x – 3) 2 = 36 Asymptotes: y = (x – 3) + 1 2323 y = (x – 3) + 1 2323 -

10. Find the standard form of the equation of a hyperbola given: 49 = 25 + b 2 b 2 = 24 Horizontal hyperbola Foci: (-7, 0) and (7, 0) Vertices: (-5, 0) and (5, 0) 10 8 FFVV Center: (0, 0) c 2 = a 2 + b 2 (x – h) 2 (y – k) 2 a2a2 b2b2 – = 1 x 2 y 2 2524 – = 1 a 2 = 25 and c 2 = 49 C

11. Center: (-1, -2) Vertical hyperbola Find the standard form equation of the hyperbola that is graphed at the right (y – k) 2 (x – h) 2 b2b2 a2a2 – = 1 a = 3 and b = 5 (y + 2) 2 (x + 1) 2 259 – = 1

12. 3.5.18 General Effects of the Parameters A and C When A ≠ C, and A x C < 0, the resulting conic is an hyperbola.

13. Definition of Eccentricity of an Ellipse The eccentricity of an ellipse is

14. Homework: Page 663 2-16 even, 24 – 40 even, 47, 52