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Published byOsborne Palmer Modified over 8 years ago
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By Angelica Gonzalez 2 nd Period
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Volume The amount of space, measured in cubic units, that an object takes up. Prism: V=Bh Cylinder: V=Bh Pyramid: V=1/3Bh Cone: V=1/3Bh Sphere: V=4/3(3.14)r^3
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Word Problem A cylinder has a diameter of 14 inches and a height of 21 inches. What is its volume?
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Pi The ratio of the circumference to the diameter of a circle; equal to about 3.141592+.
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Word Problem
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Area The area of a figure is the number of squares required to cover it completely. Square: A=s^2 Rectangle: A=lw or A=bh Triangle: A=1/2bh or A=bh/2 Circle: A=(3.14)r^2
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Word Problem A circle has a radius of 5 cm. Find the area.
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Perimeter A path that surrounds an area. Square: P=4s Rectangle: P=2l+2w or P=2(l+w)
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Word Problem What is the perimeter of this figure?
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Circumference The size of something as given by the distance around it. Circle: C=2(3.14)r
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Word Problem If a circle has a diameter of 8 inches, what is the circumference?
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Surface Area A measure of the number of square units needed to cover the faces or surfaces of a figure. Cube(total): S=6s^2 Prism(lateral): S=Ph Prism(total): S=Ph+2B Pyramid(lateral): S=1/2Pl Pyramid(total): S=1/2Pl+B Cylinder(lateral): S=2(3.14)rh Cylinder(total): S=2(3.14)rh+2(3.14)r^2 or S=2(3.14)r(h+r)
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Word Problem Find the lateral surface area a cylinder with a height of 12 cm. and a diameter of 8 cm.
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Pythagorean Theorem a^2+b^2=c^2
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Word Problem
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Simple Interest Formula I = prt
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Word Problem
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P P represents the perimeter of the base of a three-dimensional figure.
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Word Problem
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B B represents the area f the base of a three- dimensional figure.
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Word Problem
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