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Similar Polygons 6.3 Yes: ABCD ~ FEHG No PQ = 12 m  Q = 30.

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Presentation on theme: "Similar Polygons 6.3 Yes: ABCD ~ FEHG No PQ = 12 m  Q = 30."— Presentation transcript:

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2 Similar Polygons 6.3 Yes: ABCD ~ FEHG No PQ = 12 m  Q = 30

3 Similar Polygons 6.3 Chapter 6 Similarity Section 6.3 Similar Polygons

4 6.3 Definition Similar Polygons Trapezoid ABCD ~ Trapezoid PQRS  B   Q,  A   P,  C   R,  D   S

5 Similar Polygons 6.3  S   C  T   D  U   E Corresponding components must line up in the similarity statement

6 Similar Polygons 6.3  L   G  M   H  N   I Corresponding components must line up in the similarity statement

7 Similar Polygons 6.3  Q   A  R   B  S   C  T   D Corresponding components must line up in the similarity statement

8 Similar Polygons 6.3 Definition: Scale Factor The ratio of any two corresponding sides of similar polygons. Scale Factor

9 Similar Polygons 6.3 Solution 1. Find the Scale Factor 2. Find the ratio of XY and BE 3. Set up a proportion and solve for XY Scale Factor: Ratio of CD and XY Proportion 2(XY) = 9

10 Similar Polygons 6.3 3  D   Y m  Y + m  X = 180 Consecutive Interior Angle Theorem m  Y + 117 = 180 m  Y = 63 m  D = 63

11 Similar Polygons 6.3 3 p = XW + WZ + YZ + XY Need to find YZ 2(YZ) = 18 YZ = 9 9 p = 6 + + 9 + p = 24

12 Similar Polygons 6.3 3 9 Ratio of the perimeters = scale factor

13 Similar Polygons 6.3 Assume the angles are congruent

14 Similar Polygons 6.3 Assume the angles are congruent

15 Similar Polygons 6.3 x x + x + 42 = 180 2x + 42 = 180 2x = 138 x = 69 8y = 100

16 Similar Polygons 6.3 y = 11 72 x = 72

17 Similar Polygons 6.3 Ratio of the perimeters = scale factor Fill in what you know and solve 8x =480 x = 60 State your answer The perimeter of  ABC = 60 inches

18 Similar Polygons 6.3 Ratio of the perimeters = scale factor A B C D F G E H 18 Find FG 4(FG) = 18 4½4½ 4½4½

19 Similar Polygons 6.3 A B C D F G E H 18 EF = GH and FG = EH 4½4½ 4½4½ p = EF + FG + GH + EH p = EF + FG + EF + FG p = 2(EF) + 2(FG) 15 = 2(EF) + 2(4½) 15 = 2(EF) + 9 6 = 2(EF) 3 = EF 3 3

20 Similar Polygons 6.3 HW # Pg


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