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Remembering: Molarity and Stoichiometry Because we know you brain is getting full!!!

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Presentation on theme: "Remembering: Molarity and Stoichiometry Because we know you brain is getting full!!!"— Presentation transcript:

1 Remembering: Molarity and Stoichiometry Because we know you brain is getting full!!!

2 Molarity = moles (Molar) or (M) litres

3 Calculate the molarity of 18 moles of LiBr dissolved in 6.0 L. =18 moles 6.0 L = 3.0 M

4 How many moles of AlF 3 are there in 20.5 L of a 0.172 M solution?

5 How many moles of AlF 3 are there in 20.5 L of a 0.172 M solution? 20.5 L x

6 How many moles of AlF 3 are there in 20.5 L of a 0.172 M solution? 20.5 L x 1 L

7 How many moles of AlF 3 are there in 20.5 L of a 0.172 M solution? 20.5 L x 0.172 mole 1 L

8 How many moles of AlF 3 are there in 20.5 L of a 0.172 M solution? 20.5 L x 0.172 mole= 3.53 moles 1 L

9 STOICHIOMETRY

10 Stoichiometry is where you use the balancing coefficients to create a ratio between two different compounds in a chemical reaction.

11 1.How many grams Fe 2 O 3 of are required to produce 105 g of Fe? 2Fe 2 O 3 +3C→4Fe+3CO 2

12 1.How many grams Fe 2 O 3 of are required to produce 105 g of Fe? 2Fe 2 O 3 +3C→4Fe+3CO 2 ?g105 g

13 2 4

14 105 g Fe

15 1.How many grams Fe 2 O 3 of are required to produce 105 g of Fe? 2Fe 2 O 3 +3C→4Fe+3CO 2 ?g105 g 105 g Fe x1 mole 55.8 g

16 1.How many grams Fe 2 O 3 of are required to produce 105 g of Fe? 2Fe 2 O 3 +3C→4Fe+3CO 2 ?g105 g 105 g Fe x1 mole x 2 mole Fe 2 O 55.8 g4 mole Fe

17 1.How many grams Fe 2 O 3 of are required to produce 105 g of Fe? 2Fe 2 O 3 +3C→4Fe+3CO 2 ?g105 g 105 g Fe x1 mole x 2 mole Fe 2 O x 159.6 g 55.8 g4 mole Fe 1 mole

18 1.How many grams Fe 2 O 3 of are required to produce 105 g of Fe? 2Fe 2 O 3 +3C→4Fe+3CO 2 ?g105 g 105 g Fe x1 mole x 2 mole Fe 2 O x 159.6 g = 150. g 55.8 g4 mole Fe 1 mole

19 How many grams of sodium chloride are produced when you react 65.2 g of sodium carbonate? 1 Na 2 CO 3 + 2 HCl → 2 NaCl + 1 H 2 O + 1 CO 2

20 How many grams of sodium chloride are produced when you react 65.2 g of sodium carbonate? 1 Na 2 CO 3 + 2 HCl → 2 NaCl + 1 H 2 O + 1 CO 2 65.2 g ? g

21 How many grams of sodium chloride are produced when you react 65.2 g of sodium carbonate? 1 Na 2 CO 3 + 2 HCl → 2 NaCl + 1 H 2 O + 1 CO 2 65.2 g ? g 65.2 g x Na 2 CO 3 2 1

22 How many grams of sodium chloride are produced when you react 65.2 g of sodium carbonate? 1 Na 2 CO 3 + 2 HCl → 2 NaCl + 1 H 2 O + 1 CO 2 65.2 g ? g 65.2 g x Na 2 CO 3 x 1 mol Na 2 CO 3 106.0 g Na 2 CO 3 2 1

23 How many grams of sodium chloride are produced when you react 65.2 g of sodium carbonate? 1 Na 2 CO 3 + 2 HCl → 2 NaCl + 1 H 2 O + 1 CO 2 65.2 g ? g 65.2 g x Na 2 CO 3 x 1 mol Na 2 CO 3 x 2 mol NaCl 106.0 g Na 2 CO 3 1 mol Na 2 CO 3 2 1

24 How many grams of sodium chloride are produced when you react 65.2 g of sodium carbonate? 1 Na 2 CO 3 + 2 HCl → 2 NaCl + 1 H 2 O + 1 CO 2 65.2 g ? g 65.2 g x Na 2 CO 3 x 1 mol Na 2 CO 3 x 2 mol NaCl x 58.5 g NaCl 106.0 g Na 2 CO 3 1 mol Na 2 CO 3 1 mol NaCl 2 1

25 How many grams of sodium chloride are produced when you react 65.2 g of sodium carbonate? 1 Na 2 CO 3 + 2 HCl → 2 NaCl + 1 H 2 O + 1 CO 2 65.2 g ? g 65.2 g x Na 2 CO 3 x 1 mol Na 2 CO 3 x 2 mol NaCl x 58.5 g NaCl = 72.0 g 106.0 g Na 2 CO 3 1 mol Na 2 CO 3 1 mol NaCl 2 1

26 30.2 L of HCl gas (as STP) is dissolved in 0.500 L of water to produce an acid solution. What volume of 0.200 M Ba(OH) 2 will neutralize this solution? 2 HCl + 1 Ba(OH) 2 → 2 H 2 O + 1 BaCl 2

27 30.2 L of HCl gas (as STP) is dissolved in 0.500 L of water to produce an acid solution. What volume of 0.200 M Ba(OH) 2 will neutralize this solution? 2 HCl + 1 Ba(OH) 2 → 2 H 2 O + 1 BaCl 2 30.2 L ? L 30.2 L HCl 1 2

28 30.2 L of HCl gas (as STP) is dissolved in 0.500 L of water to produce an acid solution. What volume of 0.200 M Ba(OH) 2 will neutralize this solution? 2 HCl + 1 Ba(OH) 2 → 2 H 2 O + 1 BaCl 2 30.2 L ? L 30.2 L HCl x 1 mol HCl 22.4 L 1 2

29 30.2 L of HCl gas (as STP) is dissolved in 0.500 L of water to produce an acid solution. What volume of 0.200 M Ba(OH) 2 will neutralize this solution? 2 HCl + 1 Ba(OH) 2 → 2 H 2 O + 1 BaCl 2 30.2 L ? L 30.2 L HCl x 1 mol HCl x 1 mol Ba(OH) 2 22.4 L 2 mol HCl 1 2

30 30.2 L of HCl gas (as STP) is dissolved in 0.500 L of water to produce an acid solution. What volume of 0.200 M Ba(OH) 2 will neutralize this solution? 2 HCl + 1 Ba(OH) 2 → 2 H 2 O + 1 BaCl 2 30.2 L ? L 30.2 L HCl x 1 mol HCl x 1 mol Ba(OH) 2 x 1 L Ba(OH) 2 = 22.4 L 2 mol HCl 0.200 mol Ba(OH) 2 1 2

31 30.2 L of HCl gas (as STP) is dissolved in 0.500 L of water to produce an acid solution. What volume of 0.200 M Ba(OH) 2 will neutralize this solution? 2 HCl + 1 Ba(OH) 2 → 2 H 2 O + 1 BaCl 2 30.2 L ? L 30.2 L HCl x 1 mol HCl x 1 mol Ba(OH) 2 x 1 L Ba(OH) 2 = 3.37 L 22.4 L 2 mol HCl 0.200 mol Ba(OH) 2 1 2

32 250. mL of water is added to 100.0 mL of 0.200 M H 2 SO 4. What volume of 0.300 M KOH will neutralize it? 1 H 2 SO 4 + 2 KOH → 2 HOH + 1 K 2 SO 4

33 250. mL of water is added to 100.0 mL of 0.200 M H 2 SO 4. What volume of 0.300 M KOH will neutralize it? 1 H 2 SO 4 + 2 KOH → 2 HOH + 1 K 2 SO 4 0.100 L? L

34 250. mL of water is added to 100.0 mL of 0.200 M H 2 SO 4. What volume of 0.300 M KOH will neutralize it? 1 H 2 SO 4 + 2 KOH → 2 HOH + 1 K 2 SO 4 0.100 L? L 0.1000 L H 2 SO 4

35 250. mL of water is added to 100.0 mL of 0.200 M H 2 SO 4. What volume of 0.300 M KOH will neutralize it? 1 H 2 SO 4 + 2 KOH → 2 HOH + 1 K 2 SO 4 0.100 L? L 0.1000 L H 2 SO 4 x 0.200 mol H 2 SO 4 1L

36 250. mL of water is added to 100.0 mL of 0.200 M H 2 SO 4. What volume of 0.300 M KOH will neutralize it? 1 H 2 SO 4 + 2 KOH → 2 HOH + 1 K 2 SO 4 0.100 L? L 0.1000 L H 2 SO 4 x 0.200 mol H 2 SO 4 x 2 mol KOH 1L 1 mol H 2 SO 4

37 250. mL of water is added to 100.0 mL of 0.200 M H 2 SO 4. What volume of 0.300 M KOH will neutralize it? 1 H 2 SO 4 + 2 KOH → 2 HOH + 1 K 2 SO 4 0.100 L? L 0.1000 L H 2 SO 4 x 0.200 mol H 2 SO 4 x 2 mol KOH x 1 L KOH 1L 1 mol H 2 SO 4 0.300 mol KOH

38 250. mL of water is added to 100.0 mL of 0.200 M H 2 SO 4. What volume of 0.300 M KOH will neutralize it? 1 H 2 SO 4 + 2 KOH → 2 HOH + 1 K 2 SO 4 0.100 L? L 0.1000 L H 2 SO 4 x 0.200 mol H 2 SO 4 x 2 mol KOH x 1 L KOH 1L 1 mol H 2 SO 4 0.300 mol KOH = 0.133 L of KOH

39 Homework: Worksheet #4 (in Molarity Unit)


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