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Acids Lesson 13 Indicators Theory. Indicators Indicators are organic chemicals with large complex formulas. They are weak acids where the acid and base.

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Presentation on theme: "Acids Lesson 13 Indicators Theory. Indicators Indicators are organic chemicals with large complex formulas. They are weak acids where the acid and base."— Presentation transcript:

1 Acids Lesson 13 Indicators Theory

2 Indicators Indicators are organic chemicals with large complex formulas. They are weak acids where the acid and base forms have different colours.

3 Methyl Red

4 Look up Alizarin yellow on page 7 of your data package. It tells you that it changes from yellow to red as pH increases. This means that the acid form is yellow and the base form is red.

5

6 Transition Point=10.1+ 12.0 2 = 11.05

7 Alizarin Yellow HInd ⇄ H + +Ind - Acid form Base form yellowred The solution is yellow when the pH < 11.05 The solution is red when the pH > 11.05 At the transition point pH = 11.05, the yellow [HInd] = [Ind - ] red and the solution looks orange, which is a blend of yellow and red. Ka=[H + ][Ind - ] [HInd]

8 Alizarin Yellow HInd ⇄ H++Ind- Acid form Base form yellowred The solution is yellow when the pH < 11.05 The solution is red when the pH > 11.05 At the transition point pH = 11.05, the yellow [HInd] = [Ind - ] red and the solution looks orange, which is a blend of yellow and red. Ka=[H + ][Ind - ] [HInd] Ka=[H + ][Ind - ] [HInd]

9 Alizarin Yellow HInd ⇄ H++Ind- Acid form Base form yellowred The solution is yellow when the pH < 11.05 The solution is red when the pH > 11.05 At the transition point pH = 11.05, the yellow [HInd] = [Ind - ] red and the solution looks orange, which is a blend of yellow and red. Ka=[H + ][Ind - ] [HInd] Ka=[H + ][Ind - ]=[H + ]Only at the trans point [HInd]

10 Calculate the Ka for methyl orange. Transition point pH= (3.2 + 4.4)/2 = 3.8 [H + ]=10 -pH =10 -3.8 =1.58 x 10 -4 M Ka=[H + ]=2 x 10 -4 An indicator has a Ka = 1.0 x 10 -6, calculate the pH of the transition point. Ka=[H + ]=1.0 x 10 -6 M pH = -log[H + ]=-Log[1.0 x 10 -6 ] =6.00 The indicator is chlorophenol red because (5.2 + 6.8)/2 = 6.0

11 There are a few indicators that are diprotic and can change colours twice. You have one of those in this lab and it is called thymol blue. H 2 Ind ⇄ H + +HInd - HInd - ⇄ H + +Ind 2- pH 024678101214

12 There are a few indicators that are diprotic and can change colours twice. You have one of those in this lab and it is called thymol blue. H 2 Ind ⇄ H + +HInd - Red HInd - ⇄ H + +Ind 2- pH 024678101214

13 There are a few indicators that are diprotic and can change colours twice. You have one of those in this lab and it is called thymol blue. H 2 Ind ⇄ H + +HInd - Redblue HInd - ⇄ H + +Ind 2- Blue pH 024678101214

14 There are a few indicators that are diprotic and can change colours twice. You have one of those in this lab and it is called thymol blue. H 2 Ind ⇄ H + +HInd - Redblue HInd - ⇄ H + +Ind 2- BlueYellow pH 024678101214

15 There are a few indicators that are diprotic and can change colours twice. You have one of those in this lab and it is called thymol blue. H 2 Ind ⇄ H + +HInd - Redpurpleblue [H 2 Ind] = [HInd - ] HInd - ⇄ H + +Ind 2- BlueYellow pH 024678101214

16 There are a few indicators that are diprotic and can change colours twice. You have one of those in this lab and it is called thymol blue. H 2 Ind ⇄ H + +HInd - Redpurpleblue [H 2 Ind] = [HInd - ] HInd - ⇄ H + +Ind 2- BluegreenYellow [HInd - ] = [Ind 2- ] pH 024678101214


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