2. 2 (c)2003 Brooks/Cole, a division of Thomson Learning, Inc. Thomson Learning ™ is a trademark used herein under license. Figure 6.28 The Charpy V-notch properties for a BCC carbon steel and a FCC stainless steel. The FCC crystal structure typically leads top higher absorbed energies and no transition temperature

3. Dislocations & Materials Classes Covalent Ceramics (Si, diamond): Motion hard. -directional (angular) bonding Ionic Ceramics (NaCl): Motion hard. -need to avoid ++ and - - neighbors. ++++ +++ ++++ --- ---- --- Metals: Disl. motion easier. -non-directional bonding -close-packed directions for slip. electron cloudion cores + + + + +++++++ + +++++ +++++ + +

4. Dislocation Motion Dislocations & plastic deformation Cubic & hexagonal metals - plastic deformation is by plastic shear or slip where one plane of atoms slides over adjacent plane by defect motion (dislocations). If dislocations don't move, deformation doesn't occur! Adapted from Fig. 7.1, Callister 7e.

5. Stronger since grain boundaries pin deformations Slip planes & directions (,  ) change from one crystal to another.  R will vary from one crystal to another. The crystal with the largest  R yields first. Other (less favorably oriented) crystals yield (slip) later. Adapted from Fig. 7.10, Callister 7e. (Fig. 7.10 is courtesy of C. Brady, National Bureau of Standards [now the National Institute of Standards and Technology, Gaithersburg, MD].) Slip Motion in Polycrystals  300  m

6. After seeing the effect of poly crystalline materials we can say (as related to strength): Ordinarily ductility is sacrificed when an alloy is strengthened. The relationship between dislocation motion and mechanical behavior of metals is significance to the understanding of strengthening mechanisms. The ability of a metal to plastically deform depends on the ability of dislocations to move. Virtually all strengthening techniques rely on this simple principle: Restricting or Hindering dislocation motion renders a material harder and stronger. We will consider strengthening single phase metals by: grain size reduction, solid-solution alloying, and strain hardening

7. Strategies for Strengthening: 1: Reduce Grain Size Grain boundaries are barriers to slip. Barrier "strength" increases with Increasing angle of misorientation. Smaller grain size: more barriers to slip. Hall-Petch Equation: Adapted from Fig. 7.14, Callister 7e. (Fig. 7.14 is from A Textbook of Materials Technology, by Van Vlack, Pearson Education, Inc., Upper Saddle River, NJ.)

8.  Impurity atoms distort the lattice & generate stress.  Stress can produce a barrier to dislocation motion. Strategies for Strengthening: 2: Solid Solutions Smaller substitutional impurity Impurity generates local stress at A and B that opposes dislocation motion to the right. A B Larger substitutional impurity Impurity generates local stress at C and D that opposes dislocation motion to the right. C D

9. Stress Concentration at Dislocations Adapted from Fig. 7.4, Callister 7e.

10. Strengthening by Alloying small impurities tend to concentrate at dislocations on the “Compressive stress side” reduce mobility of dislocation  increase strength Adapted from Fig. 7.17, Callister 7e.

11. Strengthening by alloying Large impurities concentrate at dislocations on “Tensile Stress” side – pinning dislocation Adapted from Fig. 7.18, Callister 7e.

12. Strategies for Strengthening: 4. Cold Work (%CW) Room temperature deformation. Common forming operations change the cross sectional area: Adapted from Fig. 11.8, Callister 7e. -Forging A o A d force die blank force -Drawing tensile force A o A d die -Extrusion ram billet container force die holder die A o A d extrusion -Rolling roll A o A d

13. Ti alloy after cold working: Dislocations entangle and multiply Thus, Dislocation motion becomes more difficult. Adapted from Fig. 4.6, Callister 7e. (Fig. 4.6 is courtesy of M.R. Plichta, Michigan Technological University.) During Cold Work 0.9  m

14. Result of Cold Work Dislocation density = –Carefully grown single crystal  ca. 10 3 mm -2 –Deforming sample increases density  10 9 -10 10 mm -2 –Heat treatment reduces density  10 5 -10 6 mm -2 Yield stress increases as  d increases: total dislocation length unit volume large hardening small hardening    y0y0  y1y1

15. Impact of Cold Work Lo-Carbon Steel! Adapted from Fig. 7.20, Callister 7e. Yield strength (  y ) increases. Tensile strength (TS) increases. Ductility (%EL or %AR) decreases. As cold work is increased

16. What is the tensile strength & ductility after cold working? Cold Work Analysis D o =15.2mm Cold Work D d =12.2mm Copper

17. What is the tensile strength & ductility after cold working to 35.6%? Adapted from Fig. 7.19, Callister 7e. (Fig. 7.19 is adapted from Metals Handbook: Properties and Selection: Iron and Steels, Vol. 1, 9th ed., B. Bardes (Ed.), American Society for Metals, 1978, p. 226; and Metals Handbook: Properties and Selection: Nonferrous Alloys and Pure Metals, Vol. 2, 9th ed., H. Baker (Managing Ed.), American Society for Metals, 1979, p. 276 and 327.) Cold Work Analysis % Cold Work 100 300 500 700 Cu 2004060 yield strength (MPa) % Cold Work tensile strength (MPa) 200 Cu 0 400 600 800 204060 340MPa TS = 340MPa ductility (%EL) % Cold Work 20 40 60 204060 0 0 Cu 7% %EL= 7% YS = 300 MPa

18. ©2003 Brooks/Cole, a division of Thomson Learning, Inc. Thomson Learning ™ is a trademark used herein under license.

19. 1 hour treatment at T anneal... decreases TS and increases %EL. Effects of cold work are reversed! 3 Annealing stages to discuss... Adapted from Fig. 7.22, Callister 7e. (Fig. 7.22 is adapted from G. Sachs and K.R. van Horn, Practical Metallurgy, Applied Metallurgy, and the Industrial Processing of Ferrous and Nonferrous Metals and Alloys, American Society for Metals, 1940, p. 139.) Effect of Heating After %CW tensile strength (MPa) ductility (%EL) tensile strength ductility Recovery Recrystallization Grain Growth 600 300 400 500 60 50 40 30 20 annealing temperature (ºC) 200100300400500600700

20. Annihilation reduces dislocation density. Recovery Scenario 1 Results from diffusion Scenario 2 4. opposite dislocations meet and annihilate Dislocations annihilate and form a perfect atomic plane. extra half-plane of atoms extra half-plane of atoms atoms diffuse to regions of tension 2. grey atoms leave by vacancy diffusion allowing disl. to “climb” RR 1. dislocation blocked; can’t move to the right Obstacle dislocation 3. “Climbed” disl. can now move on new slip plane

21. ©2003 Brooks/Cole, a division of Thomson Learning, Inc. Thomson Learning ™ is a trademark used herein under license.

22. New grains are formed that: -- have a low dislocation density -- are small -- consume cold-worked grains. Adapted from Fig. 7.21 (a),(b), Callister 7e. (Fig. 7.21 (a),(b) are courtesy of J.E. Burke, General Electric Company.) 33% cold worked brass New crystals nucleate after 3 sec. at 580  C. 0.6 mm Recrystallization

23. All cold-worked grains are consumed. Adapted from Fig. 7.21 (c),(d), Callister 7e. (Fig. 7.21 (c),(d) are courtesy of J.E. Burke, General Electric Company.) After 4 seconds After 8 seconds 0.6 mm Further Recrystallization

24. At longer times, larger grains consume smaller ones. Why? Grain boundary area (and therefore energy) is reduced. After 8 s, 580ºC After 15 min, 580ºC 0.6 mm Adapted from Fig. 7.21 (d),(e), Callister 7e. (Fig. 7.21 (d),(e) are courtesy of J.E. Burke, General Electric Company.) Grain Growth Empirical Relation: coefficient dependent on material & Temp. grain dia. At time t. elapsed time exponent typ. ~ 2 This is: Ostwald Ripening

25. TRTR Adapted from Fig. 7.22, Callister 7e. º º T R = recrystallization temperature

26. Recrystallization Temperature, T R T R = recrystallization temperature = point of highest rate of property change 1.T R  0.3-0.6 T m (K) 2.Due to diffusion  annealing time  T R = f(t) shorter annealing time => higher T R 3.Higher %CW => lower T R – strain hardening 4.Pure metals lower T R due to dislocation movements Easier to move in pure metals => lower T R

27. 27 Figure 7.9 The fibrous grain structure of a low carbon steel produced by cold working: (a) 10% cold work, (b) 30% cold work, (c) 60% cold work, and (d) 90% cold work (250). (Source: From ASM Handbook Vol. 9, Metallography and Microstructure, (1985) ASM International, Materials Park, OH 44073. Used with permission.)

28. 28 Example 7.3 Design of a Stamping Process One method for producing fans for cooling automotive and truck engines is to stamp the blades from cold-rolled steel sheet, then attach the blades to a “spider’’ that holds the blades in the proper position. A number of fan blades, all produced at the same time, have failed by the initiation and propagation of a fatigue crack transverse to the axis of the blade (Figure 7.11). All other fan blades perform satisfactorily. Provide an explanation for the failure of the blades and redesign the manufacturing process to prevent these failures.

29. 29 ©2003 Brooks/Cole, a division of Thomson Learning, Inc. Thomson Learning ™ is a trademark used herein under license. Figure 7.11 Orientations of samples (for Example 7.3) Example 7.3 (continued)