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Year 11 GCSE Maths - Intermediate Triangles and Interior and Exterior Angles In this lesson you will learn: How to prove that the angles of a triangle.

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Presentation on theme: "Year 11 GCSE Maths - Intermediate Triangles and Interior and Exterior Angles In this lesson you will learn: How to prove that the angles of a triangle."— Presentation transcript:

1 Year 11 GCSE Maths - Intermediate Triangles and Interior and Exterior Angles In this lesson you will learn: How to prove that the angles of a triangle will always add up to 180º ; How to use angle notation – the way we refer to angles in complicated diagrams ; How to work out the total of the interior (inside) angles of any polygon.

2 a b c In the diagram above we have a triangle in- between two parallel lines. At the top of the triangle there are three angles: a, b and c. Because these three angles make a straight line: a + b + c = 180º How to prove the angles of a triangle = 180º

3 a b c c Because of the Z-rule, we see that this angle here is also equal to c Remember: this means the two angles marked c are ALTERNATE angles!!

4 a b c a Because of the Z-rule again, we see that this angle here is equal to a Remember: this means the two angles marked a are also ALTERNATE angles!! c

5 a b c a Now we have a, b and c as the three angles in the triangle…….. …. And we already know that a + b + c = 180º so this proves the angles in a triangle add up to 180º !! c

6 Using Angle notation Often we can get away with referring to an angle as just a, or b, or c or even just x or y. But sometimes this can be a little unclear. Copy the diagram on the next slide…..

7 Just saying ‘the angle F’ could actually be referring to one of ten possible angles at the point F. If we actually mean angle 1, then we give a three-letter code which starts at one end of the angle, goes to F, and finishes at the other end of the angle we want. 1 2 3 4 A B C D E F 5 6 7 8 9 10 11 12

8 So for angle 1 we start at B, then go to F and finish at A, and we write: Angle 1 = BFA (sometimes you write this as BFA) 1 2 3 4 A B C D E F 5 6 7 8 9 10 11 12

9 BUT notice we could go the other way round and start at A, then go to F and finish at B, and we write: Angle 1 = AFB instead. Either answer is correct!! 1 2 3 4 A B C D E F 5 6 7 8 9 10 11 12

10 Also for angle 4 we start at D, then go to F and finish at E, and we write: Angle 4 = DFE (or EFD) (sometimes you write this as DFE) 1 2 3 4 A B C D E F 5 6 7 8 9 10 11 12

11 And for angle 9 we start at F, then go to C and finish at D, and we write: Angle 9 = FCD (or DCF) (sometimes you write this as FCD) 1 2 3 4 A B C D E F 5 6 7 8 9 10 11 12

12 1 2 3 4 A B C D E F 5 6 7 8 9 10 11 12 Now you have a go at writing the three-letter coding for the following angles: Angle 2Angle 4Angle 10 Angle 6Angle 12Angle 3+4

13 1 2 3 4 A B C D E F 5 6 7 8 9 10 11 12 The answers are: Angle 2 = BFC or CFBAngle 4 = DFE or EFD Angle 10 = CDF or FDCAngle 6 = ABF or FBA Angle 12 = FED or DEFAngle 3+4 = CFE or EFC

14 Interior Angles of a Polygon A polygon is any shape with straight lines for sides, so a circle is NOT a polygon. A pentagon

15 Interior Angles of a Polygon To find the total of the angles inside any polygon, just pick a vertex (corner) and divide the polygon into triangles, starting at that vertex: VERTEX

16 Interior Angles of a Polygon Now each triangle has a total of 180º, so with three triangles, the pentagon has total interior angles of 3 x 180º = 540º

17 Interior Angles of a Polygon What about a heptagon? This has 7 sides. Copy the one below into your book and label the vertex shown: VERTEX Now divide it into triangles…

18 Interior Angles of a Polygon You can see now that the heptagon has been divided into 5 triangles. That means the interior angles of a heptagon must add up to 5 x 180º = 900º.

19 Interior Angles of a Polygon Now copy this table and fill it in for the 2 polygons we have looked at so far: Name of Polygon Number of sides Number of triangles Working out Total of Interior angles Triangle31 1 x 180 180º Quadrilateral Pentagon Hexagon Heptagon75 5 x 180 900º Octagon8 Decagon10

20 Interior Angles of a Polygon Now complete your table – here’s a hint: look for patterns in the numbers!! Name of Polygon Number of sides Number of triangles Working out Total of Interior angles Triangle31 1 x 180 180º Quadrilateral Pentagon Hexagon Heptagon75 5 x 180 900º Octagon8 Decagon10

21 Interior Angles of a Polygon Challenge Question: What would be the total of the Interior angles of a 42- sided polygon? Answer: The number of triangles that can be drawn is always two less than the number of sides in the polygon, so: 40 x 180 = 7200º !!


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