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Ch 10: Polynomials E) Factoring x 2 + bx + c Objective: To factor polynomials when a = 1.

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Presentation on theme: "Ch 10: Polynomials E) Factoring x 2 + bx + c Objective: To factor polynomials when a = 1."— Presentation transcript:

1 Ch 10: Polynomials E) Factoring x 2 + bx + c Objective: To factor polynomials when a = 1

2 Definitions Polynomial in Standard Form: ax 2 + bx + c = 0 A polynomial written in descending order based on the exponents. Polynomial in Factored Form: (x + c 1 )( x + c 2 ) = 0 A polynomial written as the product of two (or more) binomials.

3 Table Method 1)Arrange the polynomial in Standard Form everything on one side and zero on the other 2)Create a table (see below) listing all of the factors of c in columns 1 and 2 3)Place the sum of columns 1 & 2 into column 3 4)Look for the value of b in column 3 and place the values from columns 1 & 2 into the Factored Form. (x + )( x + ) = 0 x 2 + 7x + 12 = 0 1  12, 2  6, 3  4, and the negatives 112 26 3 4 −1−1 − 12 −2−2 −6−6 −3−3 −4−4 = − 13 = − 8 = − 7 = 13 = 8 = 7 + + + + + + + = b c1c1 c2c2 c1c1 c2c2

4 Table Method Example 1 Example 2 x 2 – 8x + 12 = 0x 2 + x − 12 = 0 (x + )( x + ) = 0 112 26 3 4 −1−1 − 12 −2−2 −6−6 −3−3 −4−4 = − 13 = − 8 = − 7 = 13 = 8 = 7 + + + + + + + = b c1c1 c2c2 c1c1 c2c2 (x + )( x + ) = 0 1 − 12 2 −6−6 3 −4−4 −1−112 −2−26 −3−34 = 11 = 4 = 1 = − 11 = − 4 = − 1 + + + + + + + = b c1c1 c2c2 c1c1 c2c2 (x − 2)( x − 6) = 0(x − 3)( x + 4) = 0

5 “X” Method 1)Arrange the polynomial in Standard Form everything on one side and zero on the other 2)Place the value of b at the top of the “x” 3)Place the value of c at the bottom of the “x” 4)Find the values that can be inserted into the left & right side of the “x” whose sum is on the top and product is on the bottom. use trial & error 5)Place those values into the Factored Form x 2 + 7x + 12 = 0 7 12 1 1 + 12 ≠ 7 add (+) multiply (  ) 26 2 + 6 ≠ 7 34 3 + 4 = 7 (x + )( x + ) = 0 c1c1 c2c2

6 “X” Method Example 1 Example 2 −4−4 −5−5 1 −5−5 (x + )( x + ) = 0 c1c1 c2c2 x 2 – 6x + 9 = 0x 2 – 4x − 5 = 0 add (+) multiply (  ) −6−6 9 −3−3 −3−3 (x + )( x + ) = 0 c1c1 c2c2 add (+) multiply (  ) (x + 1)( x − 5) = 0(x − 3)( x − 3) = 0

7 Algebra Tiles 1)Arrange the polynomial in Standard Form everything on one side and zero on the other 2)Lay out the tiles that represent the polynomial x 2 + 7x + 12 = 0 7x12 x2x2 3) Rearrange the tiles so they form a rectangle 4) The tiles across the bottom and down the right side represent the binomials in Factored Form.

8 Algebra Tiles 1)Arrange the polynomial in Standard Form everything on one side and zero on the other 2)Lay out the tiles that represent the polynomial x 2 + 7x + 12 = 0 7x12 x2x2 3) Rearrange the tiles so they form a rectangle 4) The tiles across the bottom and down the right side represent the binomials in Factored Form. x + 4 x + 3 ++= (x + 4)(x + 3)

9 Algebra Tiles Example 1 Example 2 x 2 − 3x − 4 = 0x 2 + 5x + 6 = 0 156 x + 2 x + 3 (x + 2)(x + 3)= 0 134 x − 4 - x − 1 (x − 4)(-x − 1)= 0 (x − 4)( x + 1) = 0

10 Classwork 1) 3) 2) 4) x 2 − 8x + 15 = 0x 2 − 16x + 63 = 0 x 2 + 14x + 48 = 0 x 2 + 2x − 15 = 0 (x − 5)(x − 3) = 0(x − 7)(x − 9) = 0 (x + 6)(x + 8) = 0(x + 5)(x − 3) = 0

11 5) 7) 6) 8) x 2 − 2x + 1 = 0x2x2 x 2 + 2x − 8 = 0x 2 + 11x + 30 = 0 (x − 1)(x − 1) = 0(x − 1)(x + 1) = 0 (x − 2)(x + 4) = 0 (x + 5)(x + 6) = 0 − 1 = 0 + 0x


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