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Geometry Ch. 5 Test Review

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Presentation on theme: "Geometry Ch. 5 Test Review"— Presentation transcript:

1 Geometry Ch. 5 Test Review

2 5-1 Midsegment Solve for x

3 5-2 Perpendicular Bisector / Angle Bisector Solve for x

4 5-3 Incenter Solve for x. Radii of circle X= -1 congruent

5 5-3 Graph the points. Find Circumcenter. Find Orthocenter.
Perp bisectors 5-3 Graph the points Find Circumcenter Find Orthocenter. (0,0) altitudes (4,-3)

6 5-3 & 5-4 Point of Concurrency Name it!
Perpendiculuar Bisector Median Altitude

7 5-3 Draw an angle bisector!

8 5-3-5-4 Point of Concurrency Name it!
incenter Angle Bisectors Form _________________ Perpendicular Bisectors Form _____________ Medians Form __________________ Altitudes Form _________________ circumcenter centroid orthocenter

9 5-3-5-4 Point of Concurrency Name the line!

10 5-4 Centroid 10 5 12 36

11 5-6 List the SIDES in order. Smallest to largest.
54

12 5-6 Determine the SHORTEST side?
Not EG 5-6 Determine the SHORTEST side? Look for next small L 47 X M S L M 67 DG O S

13 5-6 Write sides in order from smallest to largest
DG, ED, EG/ EG, FG, EF L 47 X M S L M 67 O S

14 5-6 Longest side of triangle?
In triangle ABC, m<A = 2x + 20, m<B = 4x – 30, m<C = x + 50. Solve for x. Find LONGEST side of triangle ABC. 2x x – 30 + x + 50 = 180 7x + 40 = 180 7x = 140 x = 20

15 Continuation… Longest side..
In triangle ABC, m<A = 2x + 20, m<B = 4x – 30, m<C = x + 50. Solve for x. Find LONGEST side of triangle ABC. C m<A = 2(20)+20 = 60 70 A 60 50 m<B = 4(20) – 30 = 50 B m<C = = 70 AB

16 5-6 Which lengths could be SIDES of a triangle?
No, >8.5 2.5, 8.5, 5.5 6, 5, 11 5x, 8x, 12x No, 6+5>11 Yes, 5x+8x>12x

17 5-6 Triangle Inequality Find range of values.
Small side + small side > 3rd side 5-6 Triangle Inequality Find range of values. If lengths of sides of a triangle are 2k+3 and 6k, then the third side must be greater than ________ and less than _________ 4k-3 8k+3 Small side + small side > 3rd side 2k+3 + 6k > x 2k+3 + x > 6k OR -2k k -3 8k+3 > x x > 4k-3 x < 8k+3 Greater than Less than

18 AEB > BDC Big so Big By Hinge Theorem
5-7 Hinge Theorem & Converse of Hinge Theorem Fill in with <, >, or =. By which theorem? AEB > BDC so Big Big By Hinge Theorem

19 By Converse of Hinge Theorem
5-7 Hinge Theorem & Converse of Hinge Theorem Fill in with <, >, or =. By which theorem? AB<ED so Big By Converse of Hinge Theorem Big


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