1. Aim: Review the distance and midpoint Do Now: in the triangle, find the lengths of two legs (-2,4) (3,6) (3,4)

2. Distance between a point and a line y = x + 2 P (2,1) l

3. The slope of line l is 1 then the slope of PQ must be -1, since they are perpendicular to each other Use point-slope form of a line to get y – 1= -1(x – 2) y – 1 = -x + 2, y = -x + 3 Solve the system of equations y = x + 2 y = -x + 3

4. We can use this formula to check our answer by rewriting y = x + 2 into x – y + 2 = 0 A = 1, B = –1 and C = 2

6. 1.Find the distance from the point (1,2) to line x + 2y = 3 2. Find the distance from the point (-3,4) to line 2x – y = – 4 3. Points (-1,6) and (3,-5) are the endpoints of the diameter of a circle, find the coordinates of the center