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5-2 Polynomials, Linear Factors, & Zeros

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Presentation on theme: "5-2 Polynomials, Linear Factors, & Zeros"β€” Presentation transcript:

1 5-2 Polynomials, Linear Factors, & Zeros
Today’s Objective: I can write and graph a polynomial function

2 Roots, Zeros & x-intercepts
𝑷 𝒙 = 𝒂 𝒏 𝒙 𝒏 + 𝒂 π’βˆ’πŸ 𝒙 π’βˆ’πŸ +β‹―+ 𝒂 𝟏 𝒙+ 𝒂 𝟎 Factor Theorem π‘₯βˆ’π‘ is a linear factor of the polynomial 𝑃(π‘₯) if and only if b is a zero of the polynomial function 𝑃(π‘₯) Find the zeros Write the polynomial given the zeros: 2, βˆ’2, 3 𝑦= π‘₯βˆ’1 π‘₯+2 (π‘₯βˆ’3) 𝑦= π‘₯ 3 +2 π‘₯ 2 βˆ’24π‘₯ 𝑦=(π‘₯βˆ’ )(π‘₯βˆ’ )(π‘₯βˆ’ ) 2 +2 3 𝑦=π‘₯( π‘₯ 2 +2π‘₯βˆ’24) 1, βˆ’2, 3 𝑦=( π‘₯ 2 βˆ’4)(π‘₯βˆ’3) 𝑦=π‘₯ π‘₯+5 π‘₯βˆ’7 𝑦=π‘₯ π‘₯βˆ’4 (π‘₯+6) 𝑦= π‘₯ 3 βˆ’3 π‘₯ 2 βˆ’4π‘₯+12 0, βˆ’5, 7 0, 4, βˆ’6

3 Graphing with zeros 𝑓(π‘₯)=π‘₯(π‘₯βˆ’4)(π‘₯+3) Find and plot the zeros
Sketch end behavior Pick easy midpoints between zeros to estimate turning point Zeros: 0, 4, βˆ’3 𝑓(βˆ’2)= βˆ’2(βˆ’2βˆ’4)(βˆ’2+3) =12 𝑓(2)= 2(2βˆ’4)(2+3) =βˆ’20

4 Zeros with Multiplicity
𝑓(π‘₯)= (π‘₯+2) 2 (π‘₯βˆ’2)(π‘₯βˆ’3) Find and plot the zeros Sketch end behavior Pick easy midpoints between zeros to estimate turning point 𝑓(π‘₯)=(π‘₯+2)(π‘₯+2)(π‘₯βˆ’2)(π‘₯βˆ’3) Even multiplicity turns graph at zero Odd multiplicity pauses graph zero Zeros: βˆ’2, βˆ’2, 2, 3 𝑓(0)= (0+2) 2 (0βˆ’2)(0βˆ’3) =24 𝑓(2.5)= (2.5βˆ’2)(2.5βˆ’3) =βˆ’5 W.S. 5-1/5-2 Polynomials, Linear Factors & Zeros


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