1. M May Pythagoras’ Theorem The square on the hypotenuse equals the sum of the squares on the other two sides

2. M May c2 = a2 + b2c2 = a2 + b2

4. c 2 = a 2 + b 2 a = 12,b = 5 c 2 = 12 2 + 5 2 c 2 = 144 + 25 c 2 = 169 c = √169 c = 13 By Pythagoras’ Theorem

5. M May c 2 = a 2 + b 2 a = 15,c = 25 25 2 = 15 2 + b 2 625 = 225 + b 2 b 2 = 625 - 225 b 2 = 400 b = √400 b = 20 By Pythagoras’ Theorem

6. M May Calculate x in each triangle (give answers to 1 dec pl). x 6 8 (a) x 7 3 (b) x 9 9 (c) x 2 9 (d) x 12 8 (e) x 20 13 (f) 9 x 11 (g) x 25 20 (h)

7. M May Calculate x in each triangle (give answers to 1 dec pl). x 6 8 (a) x 7 3 (b) x 9 9 (c) x 2 9 (d) By Pythagoras’ Th m. x 2 = 8 2 + 6 2 x 2 = 64 + 36 x 2 = 100 x = √ 100 x = 10 By Pythagoras’ Th m. x 2 = 7 2 + 3 2 x 2 = 49 + 9 x 2 = 58 x = √ 58 x = 7.6 By Pythagoras’ Th m. x 2 = 9 2 + 9 2 x 2 = 81 + 81 x 2 = 162 x = √ 162 x = 12.7 By Pythagoras’ Th m. x 2 = 9 2 + 2 2 x 2 = 81 + 4 x 2 = 85 x = √ 85 x = 9.2

8. M May Calculate x in each triangle (give answers to 1 dec pl). By Pythagoras’ Th m. 12 2 = x 2 + 8 2 144 = x 2 + 64 x 2 = 144 - 64 x 2 = 80 x = √ 80 x = 8.9 By Pythagoras’ Th m. 20 2 = x 2 + 13 2 400 = x 2 + 169 x 2 = 400 - 169 x 2 = 231 x = √ 231 x = 15.2 By Pythagoras’ Th m. 11 2 = x 2 + 9 2 121 = x 2 + 81 x 2 = 121 - 81 x 2 = 40 x = √ 40 x = 6.3 By Pythagoras’ Th m. 25 2 = x 2 + 20 2 625 = x 2 + 400 x 2 = 625 - 400 x 2 = 225 x = √ 225 x = 15 x 12 8 (e) 9 x 11 (g) x 25 20 (h) x 20 13 (f)